Hi Dale,

Unfortunately, you didn't say in what for format your

data is saved into, so I presume it's saved as a list

of strings. Perhaps there is a faster/better way, but

this should suffice if your datasize isn't enormous.

data = list()

data[1] = "icsrvepf"

data[2] = "fpevrsci"

data[3] = "ics"

data[4] = "p"

data[5] = ""

data[6] = "f"

data[7] = "ic"

names = as.character(c("i", "c", "s", "r", "v", "e",

"p", "f"))

mymatrix = matrix(0, nrow = 7, ncol = 8)

colnames(mymatrix) = names

for (i in 1:length(data)) {

# split the string into separate characters

chars = strsplit(data[[i]], split="")[[1]]

mymatrix[i,which(names %in%chars)] = 1

}

mymatrix

HTH,

Martin Lam

--- Dale Steele <

[hidden email]> wrote:

> I have a data management problem which exceeds my

> meager R programming

> skills and would greatly appreciate suggestions on

> how to proceed? The

> data consists of a series of observation periods.

> Specific behaviors are

> recorded for each time period in the order each is

> observed. Their are

> 8 possible behaviors, coded as "i" "c" "s" "r" "v"

> "e" "p" "f".

>

> The data looks like:

> -->

> icsrvepf

> fpevrsci

> ics

> p

>

> f

> ic

> <--

>

> I would like to convert the about to a matrix of the

> form:

>

> i c s r v e p f

> 1 1 1 1 1 1 1 1

> 1 1 1 1 1 1 1 1

> 1 1 1 0 0 0 0 0

> 0 0 0 0 0 0 1 0

> 0 0 0 0 0 0 0 0

> 0 0 0 0 0 0 0 1

> 1 1 0 0 0 0 0 0

>

> Thanks.

>

> Dale

>

> Dale Steele, MD

> Pediatric Emergency Medicine

> Brown Medical School

>

> ______________________________________________

>

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>

https://stat.ethz.ch/mailman/listinfo/r-help> PLEASE do read the posting guide!

>

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