Get means of matrix

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Get means of matrix

jpara3
Hi everyone

I have a dataframe "data" wich is the result of join multiple csv (400 rows and 600cols every csv). The "data" dataframe has n rows and m columns (200000 rows and 600 cols) , and I have add a new colum, "csvdata", in which I specify the number of csv at wich those data belong.

So, the dataframe "data" looks like:

x1    x2     x3    ....    xn    csvdata
21   23    32    ....    12    1
27   21    39    ....    14    1
24   22    30    ....    11    1
..............................................
21   24    32    ....   19     2
27   21    39    ....    14    2
..............................................
27   22     30    ....    11    n

   

I want to store into a matrix the mean values of different substes of data of every csv, for example:

region1,1 (rows 1:20,columns 1:20) for every "csvdata" value
region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value
....

And so on for hole data.frame.

I have tryed:

area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)

But this error is the output I obtain:
 
Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) :
  arguments must have same length

I�m sure that it is not very complex to do it, but I have no idea of how to do it.

Thanks for all.

         
        [[alternative HTML version deleted]]


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Re: Get means of matrix

PIKAL Petr
Hi

See in line

> -----Original Message-----
> From: R-help [mailto:[hidden email]] On Behalf Of Jesús
> Para Fernández
> Sent: Wednesday, November 18, 2015 11:20 AM
> To: [hidden email]
> Subject: [R] Get means of matrix
>
> Hi everyone
>
> I have a dataframe "data" wich is the result of join multiple csv (400
> rows and 600cols every csv). The "data" dataframe has n rows and m
> columns (200000 rows and 600 cols) , and I have add a new colum,
> "csvdata", in which I specify the number of csv at wich those data
> belong.
>
> So, the dataframe "data" looks like:
>
> x1    x2     x3    ....    xn    csvdata
> 21   23    32    ....    12    1
> 27   21    39    ....    14    1
> 24   22    30    ....    11    1
> ..............................................
> 21   24    32    ....   19     2
> 27   21    39    ....    14    2
> ..............................................
> 27   22     30    ....    11    n
>
>
>
> I want to store into a matrix the mean values of different substes of
> data of every csv, for example:
>
> region1,1 (rows 1:20,columns 1:20) for every "csvdata" value region 2,1
> (rows 21:40,columns 1:20) para every "csvdata" value ....
>
> And so on for hole data.frame.
>
> I have tryed:
>
> area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
> area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
>
> But this error is the output I obtain:
>
> Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) :
>   arguments must have same length

Most probably length(datos$csvdata) is not 20 as you specified by data[1:20,1].

If you have already number of csv file in your data$csvdata you can do

area <- aggregate(data[,1:n], list(data$csvdata), mean, na.rm=TRUE)

If you want to aggregate each 20 rows you can elaborate index

ind <- rep(1:20, each=20)
area <- aggregate(data[,1:n], list(ind), mean, na.rm=TRUE)

Cheers
Petr

>
> I m sure that it is not very complex to do it, but I have no idea of
> how to do it.
>
> Thanks for all.
>
>
>       [[alternative HTML version deleted]]


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Re: Get means of matrix

Jim Lemon-4
In reply to this post by jpara3
Hi Jesus,
While I do not have your data and cannot test this, the problem may be that
you are using two different names for the data frame. Is this more or less
what you want?

datos<-data.frame(x1=sample(20:40,40,TRUE),x2=sample(20:40,40,TRUE),
 x3=sample(20:40,40,TRUE),csvdata=rep(1:2,each=20))
sapply(datos[datos$csvdata==1,],mean,na.rm=TRUE)
sapply(datos[datos$csvdata==2,],mean,na.rm=TRUE)

Jim


On Wed, Nov 18, 2015 at 9:19 PM, Jesús Para Fernández <
[hidden email]> wrote:

> Hi everyone
>
> I have a dataframe "data" wich is the result of join multiple csv (400
> rows and 600cols every csv). The "data" dataframe has n rows and m columns
> (200000 rows and 600 cols) , and I have add a new colum, "csvdata", in
> which I specify the number of csv at wich those data belong.
>
> So, the dataframe "data" looks like:
>
> x1    x2     x3    ....    xn    csvdata
> 21   23    32    ....    12    1
> 27   21    39    ....    14    1
> 24   22    30    ....    11    1
> ..............................................
> 21   24    32    ....   19     2
> 27   21    39    ....    14    2
> ..............................................
> 27   22     30    ....    11    n
>
>
>
> I want to store into a matrix the mean values of different substes of data
> of every csv, for example:
>
> region1,1 (rows 1:20,columns 1:20) for every "csvdata" value
> region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value
> ....
>
> And so on for hole data.frame.
>
> I have tryed:
>
> area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
> area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
>
> But this error is the output I obtain:
>
> Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) :
>   arguments must have same length
>
> I´m sure that it is not very complex to do it, but I have no idea of how
> to do it.
>
> Thanks for all.
>
>
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

        [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
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Re: Get means of matrix

djmuseR
In reply to this post by jpara3
Hi:

Here's another way to look at the problem. Instead of manually adding
a new column after k datasets have been read in, read your individual
data files into a list, as long as they all have the same variable
names and the same class (in this case, data.frame). Then create a
vector of names for the list components and use 'apply family' logic
to get the column means, returning the combined results to a data
frame or matrix. Here's a toy example to illustrate the point.
Firstly, three data frames are created and saved to external files:

# Create some artificial data and ship to external files

d1 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))
d2 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))
d3 <- data.frame(x1 = rpois(10, 20), x2 = rpois(10, 23), x3 = rpois(10, 25))

write.csv(d1, file = "d1.csv", row.names = TRUE, quote = FALSE)
write.csv(d2, file = "d2.csv", row.names = TRUE, quote = FALSE)
write.csv(d3, file = "d3.csv", row.names = TRUE, quote = FALSE)

###
# Now, read them back in and store them in a list object

# Vector of file names to process
files <- paste0("d", 1:3, ".csv")

# Create the list of data frames and assign names to list components
L <- lapply(files, function(x) read.csv(x, header = TRUE))
names(L) <- paste0("d", 1:3)

# Compute column means from each list component and row bind them
# Method 1: base R
do.call(rbind, lapply(L, colMeans))


# Method 2: plyr package
library(plyr)
ldply(L, colMeans)


Dennis

On Wed, Nov 18, 2015 at 2:19 AM, Jesús Para Fernández
<[hidden email]> wrote:

> Hi everyone
>
> I have a dataframe "data" wich is the result of join multiple csv (400 rows and 600cols every csv). The "data" dataframe has n rows and m columns (200000 rows and 600 cols) , and I have add a new colum, "csvdata", in which I specify the number of csv at wich those data belong.
>
> So, the dataframe "data" looks like:
>
> x1    x2     x3    ....    xn    csvdata
> 21   23    32    ....    12    1
> 27   21    39    ....    14    1
> 24   22    30    ....    11    1
> ..............................................
> 21   24    32    ....   19     2
> 27   21    39    ....    14    2
> ..............................................
> 27   22     30    ....    11    n
>
>
>
> I want to store into a matrix the mean values of different substes of data of every csv, for example:
>
> region1,1 (rows 1:20,columns 1:20) for every "csvdata" value
> region 2,1 (rows 21:40,columns 1:20) para every "csvdata" value
> ....
>
> And so on for hole data.frame.
>
> I have tryed:
>
> area1<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
> area2<-tapply(as.matrix(data[1:20,1]),datos$csvdata,mean,na.rm=T)
>
> But this error is the output I obtain:
>
> Error in tapply(data[1:30, ], datos$nueva, mean, na.rm = T) :
>   arguments must have same length
>
> I´m sure that it is not very complex to do it, but I have no idea of how to do it.
>
> Thanks for all.
>
>
>         [[alternative HTML version deleted]]
>
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.