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Hi,
Following a straight line indicates less evidence towards non-normality. But QQ-Plot is an exploratory tool. You can confirm your ideas obtained from the QQ-Plot via noramlity tests such as Shapiro-Wilk test. See shapiro.test under stats package and nortest package. Ozgur |
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Hi,
Try boxplot for outliers. To decide whether they influence significantly, try confirmatory normality tests. Ozgur |
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In reply to this post by Özgür Asar
On Tue, Jun 19, 2012 at 12:42 PM, Özgür Asar <[hidden email]> wrote:
> Following a straight line indicates less evidence towards non-normality. But > QQ-Plot is an exploratory tool. > > You can confirm your ideas obtained from the QQ-Plot via noramlity tests > such as Shapiro-Wilk test. > Hmm, some gurus on this list would likely disagree. > fortune('normality') Usually (but not always) doing tests of normality reflect a lack of understanding of the power of rank tests, and an assumption of high power for the tests (qq plots don't always help with that because of their subjectivity). When possible it's good to choose a robust method. Also, doing pre-testing for normality can affect the type I error of the overall analysis. -- Frank Harrell R-help (April 2005) > fortune('normality') The issue really comes down to the fact that the questions: "exactly normal?", and "normal enough?" are 2 very different questions (with the difference becoming greater with increased sample size) and while the first is the easier to answer, the second is generally the more useful one. -- Greg Snow (answering a question about a "normality test" suitable for large data) R-help (April 2009) For more on this, see ?SnowsPenultimateNormalityTest in TeachingDemos and the references within. Also search the archives as this topic pops up regularly. Regards Liviu ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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In reply to this post by Özgür Asar
Or uou can try
library(car) ?qqPlot use that with argument simulate=TRUE, which will give a simulated envelope around the curve for comparison. Kjetil On Tue, Jun 19, 2012 at 9:30 AM, Özgür Asar <[hidden email]> wrote: > Hi, > > Try boxplot for outliers. > > To decide whether they influence significantly, try confirmatory normality > tests. > > Ozgur > > -- > View this message in context: http://r.789695.n4.nabble.com/QQplot-normally-distributed-tp4633819p4633830.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Dear Kjetil,
Simulated point-wise confidence envelopes are available from qqPlot() only for studentized residuals from linear and generalized linear models. For an independent sample of observations, the confidence envelopes produced by qqPlot() are based on the standard errors of the order statistics for the reference distribution. Best, John ------------------------------------------------ John Fox Sen. William McMaster Prof. of Social Statistics Department of Sociology McMaster University Hamilton, Ontario, Canada http://socserv.mcmaster.ca/jfox/ On Tue, 19 Jun 2012 15:21:07 -0400 Kjetil Halvorsen <[hidden email]> wrote: > Or uou can try > library(car) > > ?qqPlot > > use that with argument simulate=TRUE, which will give a simulated > envelope around the curve for > comparison. > > Kjetil > > On Tue, Jun 19, 2012 at 9:30 AM, Özgür Asar <[hidden email]> wrote: > > Hi, > > > > Try boxplot for outliers. > > > > To decide whether they influence significantly, try confirmatory normality > > tests. > > > > Ozgur > > > > -- > > View this message in context: http://r.789695.n4.nabble.com/QQplot-normally-distributed-tp4633819p4633830.html > > Sent from the R help mailing list archive at Nabble.com. > > > > ______________________________________________ > > [hidden email] mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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In reply to this post by Liviu Andronic
Dear Liviu ,
Why do you prefer robust methods in the example of Noor and why you need exact normality here? Ozgur |
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In reply to this post by Noor.v.d.Assem
>Hi,
>So in my example, I can say that the data comes from a moderate normal distribution because the points more at the >right lay straight to a straight line, then the points at the left. Please a confirmation here. >But what is the information above (that the data is from a normal distribution) say about the relationship between two >variables? Dear Noor, Which two variables? Ozgur |
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In reply to this post by Özgür Asar
Dear Özgür
On Wed, Jun 20, 2012 at 7:37 AM, Özgür Asar <[hidden email]> wrote: > Why do you prefer robust methods in the example of Noor and why you need > exact normality here? > The idea is that when you do hypothesis testing to check whether a given distribution is normal, the results are rarely informative: - if you do not reject the null: you couldn't find sufficient evidence to reject normality, but you don't know what distribution your data follows. You cannot conclude from this result that your data is normal. - if you reject the null: according to the assumptions of the specific test chosen, you find that your distribution doesn't follow normality. But you still don't know what distribution it follows. And at this point you should decide whether you want to check for "exact" normality, which no distribution conforms to, or "approximate" normality. Again, see ?SnowsPenultimateNormalityTest and the numerous comments of Greg Snow on this subject on r-help. For example [1]. I also like Uwe Liggs take here [2] (which largely inspired my comments above). Regards Liviu [1] http://tolstoy.newcastle.edu.au/R/e13/help/11/01/0440.html [2] http://tolstoy.newcastle.edu.au/R/e8/help/09/12/6955.html ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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In reply to this post by Noor.v.d.Assem
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