Thanks.
That works great!
> df <- data.frame(x=c(1,1,NA,NA,2), y=c('a','a','a','b','b'), z=c(TRUE,FALSE,TRUE,FALSE,TRUE))
> cond1 <- 'x==1'
> cond2 <- 'x==1 & z'
> df
x y z
1 1 a TRUE
2 1 a FALSE
3 NA a TRUE
4 NA b FALSE
5 2 b TRUE
> subset(df, subset = ifelse(is.na(eval(parse(text=cond1))), TRUE, eval(parse(text=cond1))))
x y z
1 1 a TRUE
2 1 a FALSE
3 NA a TRUE
4 NA b FALSE
> subset(df, subset = ifelse(is.na(eval(parse(text=cond2))), TRUE, eval(parse(text=cond2))))
x y z
1 1 a TRUE
3 NA a TRUE
----- Original Message -----
From: "S Ellison" <
[hidden email]>
To: "Sebastien Bihorel" <
[hidden email]>
Sent: Monday, April 9, 2018 8:31:55 AM
Subject: RE: Question about subset
> Before I try to re-invent the wheel, I would like to know if one of the base or
> recommended packages would contain a variant of the subset function that
> would consider missing values as true.
The subset argument to subset is something that evaluates to logical - a vector of True or False.
If you wanted to treat missing values _in that_ as TRUE, wrap it in an ifelse:
ifelse(is.na(condition), TRUE, condition)
where condition can be a logical or an expression evaluating to logical.
S Ellison
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