Re: Asking for help

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Re: Asking for help

Ista Zahn
For help in formulating your question in a way that makes it easy to
help you see http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example

When asking for help on the R-help mailing list in particular, make
sure to send plain-text email.

Best,
Ista

On Wed, Apr 19, 2017 at 3:56 PM, Santiago Bueno <[hidden email]> wrote:

> I have tried to ask for help ragarding R software but it seems that I do
> not know how to send my questions. Can someone "PLEASE" tutor me on how to
> structure my messages?
>
> Best regards,
>
> Santiago
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

______________________________________________
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https://stat.ethz.ch/mailman/listinfo/r-help
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Re: Asking for help

Boris Steipe
What about the advice I sent you this morning?


B.


> On Apr 19, 2017, at 1:49 PM, Boris Steipe <[hidden email]> wrote:
>
> No attachments please. Use the dput() function. And keep the correspondence on the list, there are many colleagues who are far more knowledgeable than I am.
>
> Cheers,
> Boris
>
>
>
>
>> On Apr 19, 2017, at 1:47 PM, Santiago Bueno <[hidden email]> wrote:
>>
>> Thanks a lot Mr. Steipe. I have attached to this email an Excel file with 48 observations.  The problem is that when I try to get the prediction plot for the following model:
>> start <- coef (lm(log(Btot)~I(log(dbh**2*haut)),data=dat[dat$Btot>0,]))
>> start[1] <- exp(start[1])
>> names(start) <- c("a","b")
>> model18 <- nls(Btot~a*(dbh**2*haut)**b,data=dat,start=start,weights=1/dat$dbh**4)
>> summary(model18)
>>
>> using this code:
>>
>> with(dat,plot(dbh**2*haut,Btot,xlab="dbh^2*H(cm^2.m)",ylab="Biomass (t)", pch=19))
>> D <- seq(0,180,length=20)
>> H <- seq(0,61,length=20)
>>
>> abline(model18, lwd=3)
>>
>> I get the data points but not the prediction line (see below)
>>
>> <image.png>
>> If you can help me in getting this line, I will be eternaly grateful..
>>
>> Best regards,
>>
>> Santiago Bueno
>>
>> On Wed, Apr 19, 2017 at 12:20 PM, Boris Steipe <[hidden email]> wrote:
>> Can you provide a small reproducible example and explain what exactly is going wrong?
>>
>> Just a handful of data points will do.
>>
>>
>> B.
>>
>>
>>
>>> On Apr 18, 2017, at 2:16 PM, Santiago Bueno <[hidden email]> wrote:
>>>
>>> Thanks Boris, the following is an extract of my data. I have developed
>>> biomass models using codes like:
>>>
>>> start <- coef (lm(log(Btot)~I(log(dbh**2*haut)),data=dat[dat$Btot>0,]))
>>>
>>> start[1] <- exp(start[1])
>>>
>>> names(start) <- c("a","b")
>>>
>>> M1 <- nls(Btot~a*(dbh**2*haut)**b,data=dat,start=start,weights=1/dat$dbh**4)
>>>
>>>
>>> start <- coef(lm(log(Btot)~I(log(dbh))+I(log(haut)),data=dat[dat$Btot>0,]))
>>>
>>> start[1] <- exp(start[1])
>>>
>>> names(start) <- c("a","b1","b2")
>>>
>>> M2 <- nls(Btot~a*dbh**b1*haut**b2,data=dat,start=start,weights=1/dat$dbh**4)
>>>
>>>
>>> Tree No dbh haut Btot
>>> 1 35.00 18.90 0.535
>>> 2 25.00 16.60 0.248
>>> 3 23.00 19.50 0.228
>>> 4 13.50 15.60 0.080
>>> 5 20.00 18.80 0.172
>>> 6 23.00 17.40 0.190
>>> 7 29.00 19.90 0.559
>>> 8 17.60 18.20 0.117
>>> 9 31.00 25.30 0.645
>>> 10 26.00 23.50 0.394
>>> 11 13.00 13.00 0.038
>>> 12 32.00 20.70 0.443
>>> It is my interest to get prediction plots for the models. I have tried to
>>> use the following codes with no success: Let m be one of the fitted models
>>> with dbh as the only entry. To construct a plot of the predictions made by
>>> this model I have tried:
>>> with(dat,plot(dbh,Btot,xlab="Dbh(cm)",ylab="Biomass (t)"))
>>> D <- seq(par("usr")[1],par("usr")[2],length=200)
>>> lines(D,predict(m,newdata=data.frame(dbh=D)),col="red")
>>> For a model m that has dbh and height as entries, I have tried to get its
>>> predictions as follows:
>>> D <- seq(0,180,length=20)
>>> H <- seq(0,61,length=20)
>>> B <- matrix(predict(m,newdata=expand.grid(dbh=D,height=H)),length(D))
>>>
>>> Can someone provide help please!!!
>>>
>>>
>>> Best regards,
>>>
>>> Santiago Bueno
>>>
>>>      [[alternative HTML version deleted]]
>>>
>>> ______________________________________________
>>> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>> <Biomasa_Total.xls>
>

> On Apr 19, 2017, at 4:13 PM, Ista Zahn <[hidden email]> wrote:
>
> For help in formulating your question in a way that makes it easy to
> help you see http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
>
> When asking for help on the R-help mailing list in particular, make
> sure to send plain-text email.
>
> Best,
> Ista
>
> On Wed, Apr 19, 2017 at 3:56 PM, Santiago Bueno <[hidden email]> wrote:
>> I have tried to ask for help ragarding R software but it seems that I do
>> not know how to send my questions. Can someone "PLEASE" tutor me on how to
>> structure my messages?
>>
>> Best regards,
>>
>> Santiago
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
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and provide commented, minimal, self-contained, reproducible code.
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asking for help

Saifuddin, Miah Mohammad
In reply to this post by Ista Zahn
I have a data frame having 163863 values. I want to subset it so that each set has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second. how can I do that, preferably in a loop.


TIA

        [[alternative HTML version deleted]]

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Re: asking for help

Bert Gunter-2
By 163863 "values" do you mean rows in the data frame? If so, please
read about indexing in any online R tutorial or the Intro to R
tutorial that ships with R. This is an absolutely basic R operation,
and if you are unwilling or unable to put in the time to learn about
it, you should probably consider using other software.

If you mean something else, then please read and follow the posting
guide to help you post your question in a way that will make your
meaning clear and enable others to help you. And please post in *plain
text*, not HTML, which can get mangled by the mail software (though it
was fine this time).

Also, please note that "looping" in R is often unnecessary and inefficient.

Cheers,
Bert



-- Bert
Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )


On Mon, Apr 24, 2017 at 9:34 PM, Saifuddin, Miah Mohammad
<[hidden email]> wrote:

> I have a data frame having 163863 values. I want to subset it so that each set has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second. how can I do that, preferably in a loop.
>
>
> TIA
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
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Re: asking for help

Thomas Mailund
In reply to this post by Saifuddin, Miah Mohammad
If you write something like

indices <- rep(1:(163863/6069), each = 6069)

you can get the i’th block of rows with

table[indices == i,]

It looks like a little more work than a loop would be since you have to run through all rows for each block, but the implicit loop in this approach is likely to be faster than an explicit for-loop.

Cheers
 Thomas

On 25 Apr 2017, 07.01 +0200, Saifuddin, Miah Mohammad <[hidden email]>, wrote:
I have a data frame having 163863 values. I want to subset it so that each set has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second. how can I do that, preferably in a loop.


TIA

[[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

        [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
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Re: asking for help

PIKAL Petr
Hi

> -----Original Message-----
> From: R-help [mailto:[hidden email]] On Behalf Of Thomas
> Mailund
> Sent: Tuesday, April 25, 2017 11:20 AM
> To: [hidden email]; Saifuddin, Miah Mohammad
> <[hidden email]>
> Subject: Re: [R] asking for help
>
> If you write something like
>
> indices <- rep(1:(163863/6069), each = 6069)

You can get similar result by

indices2 <- 0:163862%/%6069

but starting with zero.

or the same with
indices2 <- (0:163862%/%6069)+1

Cheers
Petr

>
> you can get the i’th block of rows with
>
> table[indices == i,]
>
> It looks like a little more work than a loop would be since you have to run
> through all rows for each block, but the implicit loop in this approach is likely
> to be faster than an explicit for-loop.
>
> Cheers
>  Thomas
>
> On 25 Apr 2017, 07.01 +0200, Saifuddin, Miah Mohammad
> <[hidden email]>, wrote:
> I have a data frame having 163863 values. I want to subset it so that each set
> has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second.
> how can I do that, preferably in a loop.
>
>
> TIA
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

________________________________
Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům.
Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému.
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Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu.

V případě, že je tento e-mail součástí obchodního jednání:
- vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu.
- a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou.
- trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech.
- odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá.

This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system.
If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient.
______________________________________________
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Re: asking for help

Anthoni, Peter (IMK)
Hi,

the cut function might be helpful.

vec=1: 163863
fcut=cut(vec,seq(1, 163863+1,by= 6069),include.lowest = T,right=F)
aggregate(vec,by=list(fcut),min)
aggregate(vec,by=list(fcut),max)

cheers
Peter



On 25. Apr 2017, at 14:33, PIKAL Petr <[hidden email]<mailto:[hidden email]>> wrote:

Hi

-----Original Message-----
From: R-help [mailto:[hidden email]] On Behalf Of Thomas
Mailund
Sent: Tuesday, April 25, 2017 11:20 AM
To: [hidden email]<mailto:[hidden email]>; Saifuddin, Miah Mohammad
<[hidden email]<mailto:[hidden email]>>
Subject: Re: [R] asking for help

If you write something like

indices <- rep(1:(163863/6069), each = 6069)

You can get similar result by

indices2 <- 0:163862%/%6069

but starting with zero.

or the same with
indices2 <- (0:163862%/%6069)+1

Cheers
Petr


you can get the i’th block of rows with

table[indices == i,]

It looks like a little more work than a loop would be since you have to run
through all rows for each block, but the implicit loop in this approach is likely
to be faster than an explicit for-loop.

Cheers
 Thomas

On 25 Apr 2017, 07.01 +0200, Saifuddin, Miah Mohammad
<[hidden email]<mailto:[hidden email]>>, wrote:
I have a data frame having 163863 values. I want to subset it so that each set
has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second.
how can I do that, preferably in a loop.


TIA

[[alternative HTML version deleted]]

______________________________________________
[hidden email]<mailto:[hidden email]> mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.

     [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.

________________________________
Tento e-mail a jakékoliv k němu připojené dokumenty jsou důvěrné a jsou určeny pouze jeho adresátům.
Jestliže jste obdržel(a) tento e-mail omylem, informujte laskavě neprodleně jeho odesílatele. Obsah tohoto emailu i s přílohami a jeho kopie vymažte ze svého systému.
Nejste-li zamýšleným adresátem tohoto emailu, nejste oprávněni tento email jakkoliv užívat, rozšiřovat, kopírovat či zveřejňovat.
Odesílatel e-mailu neodpovídá za eventuální škodu způsobenou modifikacemi či zpožděním přenosu e-mailu.

V případě, že je tento e-mail součástí obchodního jednání:
- vyhrazuje si odesílatel právo ukončit kdykoliv jednání o uzavření smlouvy, a to z jakéhokoliv důvodu i bez uvedení důvodu.
- a obsahuje-li nabídku, je adresát oprávněn nabídku bezodkladně přijmout; Odesílatel tohoto e-mailu (nabídky) vylučuje přijetí nabídky ze strany příjemce s dodatkem či odchylkou.
- trvá odesílatel na tom, že příslušná smlouva je uzavřena teprve výslovným dosažením shody na všech jejích náležitostech.
- odesílatel tohoto emailu informuje, že není oprávněn uzavírat za společnost žádné smlouvy s výjimkou případů, kdy k tomu byl písemně zmocněn nebo písemně pověřen a takové pověření nebo plná moc byly adresátovi tohoto emailu případně osobě, kterou adresát zastupuje, předloženy nebo jejich existence je adresátovi či osobě jím zastoupené známá.

This e-mail and any documents attached to it may be confidential and are intended only for its intended recipients.
If you received this e-mail by mistake, please immediately inform its sender. Delete the contents of this e-mail with all attachments and its copies from your system.
If you are not the intended recipient of this e-mail, you are not authorized to use, disseminate, copy or disclose this e-mail in any manner.
The sender of this e-mail shall not be liable for any possible damage caused by modifications of the e-mail or by delay with transfer of the email.

In case that this e-mail forms part of business dealings:
- the sender reserves the right to end negotiations about entering into a contract in any time, for any reason, and without stating any reasoning.
- if the e-mail contains an offer, the recipient is entitled to immediately accept such offer; The sender of this e-mail (offer) excludes any acceptance of the offer on the part of the recipient containing any amendment or variation.
- the sender insists on that the respective contract is concluded only upon an express mutual agreement on all its aspects.
- the sender of this e-mail informs that he/she is not authorized to enter into any contracts on behalf of the company except for cases in which he/she is expressly authorized to do so in writing, and such authorization or power of attorney is submitted to the recipient or the person represented by the recipient, or the existence of such authorization is known to the recipient of the person represented by the recipient.
______________________________________________
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
and provide commented, minimal, self-contained, reproducible code.


        [[alternative HTML version deleted]]

______________________________________________
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Re: asking for help

Saifuddin, Miah Mohammad
Dear Altruist,


Thank you so much.


This does it.


I shall keep connected.


Regards,

Miah


________________________________
From: Anthoni, Peter (IMK) <[hidden email]>
Sent: Tuesday, April 25, 2017 8:38 AM
To: Saifuddin, Miah Mohammad
Cc: Thomas Mailund; [hidden email]; PIKAL Petr
Subject: Re: [R] asking for help

Hi,

the cut function might be helpful.

vec=1: 163863
fcut=cut(vec,seq(1, 163863+1,by= 6069),include.lowest = T,right=F)
aggregate(vec,by=list(fcut),min)
aggregate(vec,by=list(fcut),max)

cheers
Peter



On 25. Apr 2017, at 14:33, PIKAL Petr <[hidden email]<mailto:[hidden email]>> wrote:

Hi

-----Original Message-----
From: R-help [mailto:[hidden email]] On Behalf Of Thomas
Mailund
Sent: Tuesday, April 25, 2017 11:20 AM
To: [hidden email]<mailto:[hidden email]>; Saifuddin, Miah Mohammad
<[hidden email]<mailto:[hidden email]>>
Subject: Re: [R] asking for help

If you write something like

indices <- rep(1:(163863/6069), each = 6069)

You can get similar result by

indices2 <- 0:163862%/%6069

but starting with zero.

or the same with
indices2 <- (0:163862%/%6069)+1

Cheers
Petr


you can get the i’th block of rows with

table[indices == i,]

It looks like a little more work than a loop would be since you have to run
through all rows for each block, but the implicit loop in this approach is likely
to be faster than an explicit for-loop.

Cheers
 Thomas

On 25 Apr 2017, 07.01 +0200, Saifuddin, Miah Mohammad
<[hidden email]<mailto:[hidden email]>>, wrote:
I have a data frame having 163863 values. I want to subset it so that each set
has 6069 values in it. for example 1:6069 as first, 6070: 6070+6068 as second.
how can I do that, preferably in a loop.


TIA

[[alternative HTML version deleted]]

______________________________________________
[hidden email]<mailto:[hidden email]> mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
and provide commented, minimal, self-contained, reproducible code.

     [[alternative HTML version deleted]]

______________________________________________
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