count frequency

[alaios]

Hello everyone,
please consider the following lines of a matrix


[574,]   59   32
[575,]   59   32
[576,]   59   32
[577,]   59   32
[578,]   59   32
[579,]   59   32
[580,]   59   32
[581,]   60   32
[582,]   60   33
[583,]   60   33
[584,]   60   33
[585,]   60   33
[586,]   60   33
[587,]   60   33
[588,]   60   33
[589,]   60   33
[590,]   60   33
[591,]   61   33
[592,]   61   33
[593,]   61   33
[594,]   61   33
[595,]   61   33
[596,]   61   33
[597,]   61   33
[598,]   61   33
[599,]   61   33
[600,]   61   33
[601,]   62   34

Is it possible somehow to count the similarities between the first and second
column and put them on a third column like this?

59 32 3
60 33 5
62 34 1

where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)

Best Regards
Alex



     
        [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[Rainer M Krug-6]

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

On 17/09/10 14:19, Alaios wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,]   59   32
> [575,]   59   32
> [576,]   59   32
> [577,]   59   32
> [578,]   59   32
> [579,]   59   32
> [580,]   59   32
> [581,]   60   32
> [582,]   60   33
> [583,]   60   33
> [584,]   60   33
> [585,]   60   33
> [586,]   60   33
> [587,]   60   33
> [588,]   60   33
> [589,]   60   33
> [590,]   60   33
> [591,]   61   33
> [592,]   61   33
> [593,]   61   33
> [594,]   61   33
> [595,]   61   33
> [596,]   61   33
> [597,]   61   33
> [598,]   61   33
> [599,]   61   33
> [600,]   61   33
> [601,]   62   34
>
> Is it possible somehow to count the similarities between the first and second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)

One solution:

> x <- data.frame(a=trunc(runif(10)*10), b=trunc(runif(10)*10))
> x
   a b
1  6 5
2  7 5
3  1 5
4  0 4
5  3 9
6  6 8
7  4 3
8  0 4
9  2 7
10 7 2
> x$comb <- paste(x$a, x$b)
> x
   a b comb
1  6 5  6 5
2  7 5  7 5
3  1 5  1 5
4  0 4  0 4
5  3 9  3 9
6  6 8  6 8
7  4 3  4 3
8  0 4  0 4
9  2 7  2 7
10 7 2  7 2
> table(x$comb)

0 4 1 5 2 7 3 9 4 3 6 5 6 8 7 2 7 5
  2   1   1   1   1   1   1   1   1
>

I am sure, there are better ones

Cheers,

Rainer

>
> Best Regards
> Alex
>
>
>
>      
> [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

- --
Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
Biology, UCT), Dipl. Phys. (Germany)

Centre of Excellence for Invasion Biology
Natural Sciences Building
Office Suite 2039
Stellenbosch University
Main Campus, Merriman Avenue
Stellenbosch
South Africa

Tel:        +33 - (0)9 53 10 27 44
Cell:       +27 - (0)8 39 47 90 42
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Fax (D) :   +49 - (0)3 21 21 25 22 44
Fax (FR):   +33 - (0)9 58 10 27 44
email:      [hidden email]

Skype:      RMkrug
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Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/

iEYEARECAAYFAkyTXoQACgkQoYgNqgF2egrgrgCfUOvMaUOwOC7HPSdbC2fFzdLo
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______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[Henrique Dallazuanna]

Try this:

aggregate(rep(1, nrow(x)), x, sum)

On Fri, Sep 17, 2010 at 9:19 AM, Alaios <[hidden email]> wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,]   59   32
> [575,]   59   32
> [576,]   59   32
> [577,]   59   32
> [578,]   59   32
> [579,]   59   32
> [580,]   59   32
> [581,]   60   32
> [582,]   60   33
> [583,]   60   33
> [584,]   60   33
> [585,]   60   33
> [586,]   60   33
> [587,]   60   33
> [588,]   60   33
> [589,]   60   33
> [590,]   60   33
> [591,]   61   33
> [592,]   61   33
> [593,]   61   33
> [594,]   61   33
> [595,]   61   33
> [596,]   61   33
> [597,]   61   33
> [598,]   61   33
> [599,]   61   33
> [600,]   61   33
> [601,]   62   34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex
>
>
>
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

        [[alternative HTML version deleted]]


______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[Ted.Harding-2]

On 17-Sep-10 12:19:10, Alaios wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
> [574,]   59   32
> [575,]   59   32
> [576,]   59   32
> [577,]   59   32
> [578,]   59   32
> [579,]   59   32
> [580,]   59   32
> [581,]   60   32
> [582,]   60   33
> [583,]   60   33
> [584,]   60   33
> [585,]   60   33
> [586,]   60   33
> [587,]   60   33
> [588,]   60   33
> [589,]   60   33
> [590,]   60   33
> [591,]   61   33
> [592,]   61   33
> [593,]   61   33
> [594,]   61   33
> [595,]   61   33
> [596,]   61   33
> [597,]   61   33
> [598,]   61   33
> [599,]   61   33
> [600,]   61   33
> [601,]   62   34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex

Does the following do what you want?

  a <- c(59,59,59,59,59,59,59,60,60,60,60,60,60,60,
         60,60,60,61,61,61,61,61,61,61,61,61,61,62)
  b <- c(32,32,32,32,32,32,32,32,33,33,33,33,33,33,
         33,33,33,33,33,33,33,33,33,33,33,33,33,34)

  table(data.frame(a=a,b=b))
  #     b
  # a    32 33 34
  #   59  7  0  0
  #   60  1  9  0
  #   61  0 10  0
  #   62  0  0  1

  T <- t(as.matrix(table(data.frame(a=a,b=b))))
  L <- c(table(data.frame(a=a,b=b)))
  B <- as.integer(rep(rownames(T),each=ncol(T)))
  A <- as.integer(rep(colnames(T),nrow(T)))
  cbind(A,B,L)[L>0,]
  #       A  B  L
  # [1,] 59 32  7
  # [2,] 60 32  1
  # [3,] 60 33  9
  # [4,] 61 33 10
  # [5,] 62 34  1

Ted.

--------------------------------------------------------------------
E-Mail: (Ted Harding) <[hidden email]>
Fax-to-email: [phone]
Date: 17-Sep-10                                       Time: 14:15:03
------------------------------ XFMail ------------------------------

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[Jorge I Velez]

Alaios,

Try

as.data.frame(table(x[,1], x[,2))

where x is your matrix.

HTH,
Jorge



On Fri, Sep 17, 2010 at 8:19 AM, Alaios <> wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,]   59   32
> [575,]   59   32
> [576,]   59   32
> [577,]   59   32
> [578,]   59   32
> [579,]   59   32
> [580,]   59   32
> [581,]   60   32
> [582,]   60   33
> [583,]   60   33
> [584,]   60   33
> [585,]   60   33
> [586,]   60   33
> [587,]   60   33
> [588,]   60   33
> [589,]   60   33
> [590,]   60   33
> [591,]   61   33
> [592,]   61   33
> [593,]   61   33
> [594,]   61   33
> [595,]   61   33
> [596,]   61   33
> [597,]   61   33
> [598,]   61   33
> [599,]   61   33
> [600,]   61   33
> [601,]   62   34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex
>
>
>
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

        [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[alaios]

Just to confirm,
this one worked for me

 as.data.frame(table(temp[]))
   Var1 Freq
1     1   11
2     2   29
3     3   29
4     4   29
5     5   29
6     6   29
7     7   29
8     8   29
9     9   29
10   10   29
11   11   29
12   12   29
13   13   29
14   14   29
15   15   29
16   16   29
17   17   29
18   18   30
19   19   29
20   20   29



Best Regards
Alex





________________________________
From: Jorge Ivan Velez <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 4:24:59 PM
Subject: Re: [R] count frequency

Alaios,

Try


as.data.frame(table(x[,1], x[,2))

where x is your matrix.

HTH,
Jorge

 


On Fri, Sep 17, 2010 at 8:19 AM, Alaios <> wrote:

Hello everyone,

>please consider the following lines of a matrix
>
>
>[574,]   59   32
>[575,]   59   32
>[576,]   59   32
>[577,]   59   32
>[578,]   59   32
>[579,]   59   32
>[580,]   59   32
>[581,]   60   32
>[582,]   60   33
>[583,]   60   33
>[584,]   60   33
>[585,]   60   33
>[586,]   60   33
>[587,]   60   33
>[588,]   60   33
>[589,]   60   33
>[590,]   60   33
>[591,]   61   33
>[592,]   61   33
>[593,]   61   33
>[594,]   61   33
>[595,]   61   33
>[596,]   61   33
>[597,]   61   33
>[598,]   61   33
>[599,]   61   33
>[600,]   61   33
>[601,]   62   34
>
>Is it possible somehow to count the similarities between the first and second
>column and put them on a third column like this?
>
>59 32 3
>60 33 5
>62 34 1
>
>where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
>Best Regards
>Alex
>
>
>
>
>       [[alternative HTML version deleted]]
>
>______________________________________________
>[hidden email] mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
>

     
        [[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[alaios]

My bad :(
unfortunately does not work correct.

This is some of the output of the table
..............
[494,]   50   27
[495,]   50   27
[496,]   50   27
[497,]   50   28
[498,]   50   28
[499,]   50   28
[500,]   50   28
[501,]   51   28
[502,]   51   28
[503,]   51   28
[504,]   51   28
[505,]   51   28
[506,]   51   28
[507,]   51   28
[508,]   51   28
[509,]   51   28
[510,]   51   28
[511,]   52   28
[512,]   52   28
[513,]   52   28
[514,]   52   28
[515,]   52   28
[516,]   52   29
[517,]   52   29
[518,]   52   29

............


I need the following results
50 27: 3
50 28: 4
51 28: 10
52 28: 5
52 29: 3


So far nothing worked.
Best Regards
Alex





________________________________
From: Henrique Dallazuanna <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 3:09:36 PM
Subject: Re: [R] count frequency

Try this:

aggregate(rep(1, nrow(x)), x, sum)




Hello everyone,

>please consider the following lines of a matrix
>
>
>[574,]   59   32
>[575,]   59   32
>[576,]   59   32
>[577,]   59   32
>[578,]   59   32
>[579,]   59   32
>[580,]   59   32
>[581,]   60   32
>[582,]   60   33
>[583,]   60   33
>[584,]   60   33
>[585,]   60   33
>[586,]   60   33
>[587,]   60   33
>[588,]   60   33
>[589,]   60   33
>[590,]   60   33
>[591,]   61   33
>[592,]   61   33
>[593,]   61   33
>[594,]   61   33
>[595,]   61   33
>[596,]   61   33
>[597,]   61   33
>[598,]   61   33
>[599,]   61   33
>[600,]   61   33
>[601,]   62   34
>
>Is it possible somehow to count the similarities between the first and second
>column and put them on a third column like this?
>
>59 32 3
>60 33 5
>62 34 1
>
>where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
>Best Regards
>Alex
>
>
>
>
>       [[alternative HTML version deleted]]
>
>______________________________________________
>[hidden email] mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
>

--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O



     
        [[alternative HTML version deleted]]


______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[Henrique Dallazuanna]

So try this :

aggregate(rep(1, nrow(x)), as.data.frame(x), sum)

On Fri, Sep 17, 2010 at 11:54 AM, Alaios <[hidden email]> wrote:

> My bad :(
> unfortunately does not work correct.
>
> This is some of the output of the table
> ..............
> [494,]   50   27
> [495,]   50   27
> [496,]   50   27
> [497,]   50   28
> [498,]   50   28
> [499,]   50   28
> [500,]   50   28
> [501,]   51   28
> [502,]   51   28
> [503,]   51   28
> [504,]   51   28
> [505,]   51   28
> [506,]   51   28
> [507,]   51   28
> [508,]   51   28
> [509,]   51   28
> [510,]   51   28
> [511,]   52   28
> [512,]   52   28
> [513,]   52   28
> [514,]   52   28
> [515,]   52   28
> [516,]   52   29
> [517,]   52   29
> [518,]   52   29
> ............
>
>
> I need the following results
> 50 27: 3
> 50 28: 4
> 51 28: 10
> 52 28: 5
> 52 29: 3
>
> So far nothing worked.
> Best Regards
> Alex
>
>
>
> ------------------------------
> *From:* Henrique Dallazuanna <[hidden email]>
> *To:* Alaios <[hidden email]>
>
> *Cc:* Rhelp <[hidden email]>
> *Sent:* Fri, September 17, 2010 3:09:36 PM
>
> *Subject:* Re: [R] count frequency
>
> Try this:
>
> aggregate(rep(1, nrow(x)), x, sum)
>
> On Fri, Sep 17, 2010 at 9:19 AM, Alaios <[hidden email]> wrote:
>
>> Hello everyone,
>> please consider the following lines of a matrix
>>
>>
>> [574,]   59   32
>> [575,]   59   32
>> [576,]   59   32
>> [577,]   59   32
>> [578,]   59   32
>> [579,]   59   32
>> [580,]   59   32
>> [581,]   60   32
>> [582,]   60   33
>> [583,]   60   33
>> [584,]   60   33
>> [585,]   60   33
>> [586,]   60   33
>> [587,]   60   33
>> [588,]   60   33
>> [589,]   60   33
>> [590,]   60   33
>> [591,]   61   33
>> [592,]   61   33
>> [593,]   61   33
>> [594,]   61   33
>> [595,]   61   33
>> [596,]   61   33
>> [597,]   61   33
>> [598,]   61   33
>> [599,]   61   33
>> [600,]   61   33
>> [601,]   62   34
>>
>> Is it possible somehow to count the similarities between the first and
>> second
>> column and put them on a third column like this?
>>
>> 59 32 3
>> 60 33 5
>> 62 34 1
>>
>> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>>
>> Best Regards
>> Alex
>>
>>
>>
>>
>>        [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> [hidden email] mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
>

--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

        [[alternative HTML version deleted]]


______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

[alaios]

You are pretty good.
Worked nicely :)
Thanks!

Alex




________________________________
From: Henrique Dallazuanna <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 4:58:50 PM
Subject: Re: [R] count frequency

So try this :

aggregate(rep(1, nrow(x)), as.data.frame(x), sum)




My bad :(

>unfortunately does not work correct.
>
>This is some of the output of the table
>..............
>[494,]   50   27
>[495,]   50   27
>[496,]   50   27
>[497,]   50   28
>[498,]   50   28
>[499,]   50   28
>[500,]   50   28
>[501,]   51   28
>[502,]   51   28
>[503,]   51   28
>[504,]   51   28
>[505,]   51   28
>[506,]   51   28
>[507,]   51   28
>[508,]   51   28
>[509,]   51   28
>[510,]   51    28
>[511,]   52   28
>[512,]   52   28
>[513,]   52   28
>[514,]   52   28
>[515,]   52   28
>[516,]   52   29
>[517,]   52   29
>[518,]   52   29
>
>............
>
>
>I need the following results
>50 27: 3
>50 28: 4
>51 28: 10
>52 28: 5
>52 29: 3
>
>
>So far nothing worked.
>Best Regards
>Alex
>
>
>
>
>

________________________________

From: Henrique Dallazuanna <[hidden email]>

>
>Cc: Rhelp <[hidden email]>
>Sent: Fri, September 17, 2010 3:09:36 PM
>
>Subject: Re: [R] count frequency
>
>
>Try this:
>
>aggregate(rep(1, nrow(x)), x, sum)
>
>

>
>Hello everyone,
>>please consider the following lines of a matrix
>>
>>
>>[574,]   59   32
>>[575,]   59   32
>>[576,]   59   32
>>[577,]   59   32
>>[578,]   59   32
>>[579,]   59   32
>>[580,]   59   32
>>[581,]   60   32
>>[582,]   60   33
>>[583,]   60   33
>>[584,]   60   33
>>[585,]   60   33
>>[586,]   60   33
>>[587,]   60   33
>>[588,]   60   33
>>[589,]   60   33
>>[590,]   60   33
>>[591,]   61   33
>>[592,]   61   33
>>[593,]   61   33
>>[594,]   61   33
>>[595,]   61   33
>>[596,]   61   33
>>[597,]   61   33
>>[598,]   61   33
>>[599,]   61   33
>>[600,]   61   33
>>[601,]   62   34
>>
>>Is it possible somehow to count the similarities between the first and second
>>column and put them on a third column like this?
>>
>>59 32 3
>>60 33 5
>>62 34 1
>>
>>where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>>
>>Best Regards
>>Alex
>>
>>
>>
>>
>>       [[alternative HTML version deleted]]
>>
>>______________________________________________
>>[hidden email] mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>--
>Henrique Dallazuanna
>Curitiba-Paraná-Brasil
>25° 25' 40" S 49° 16' 22" O
>
>

--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O



     
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.