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alaios

count frequency

Hello everyone,
please consider the following lines of a matrix

[574,] 59 32
[575,] 59 32
[576,] 59 32
[577,] 59 32
[578,] 59 32
[579,] 59 32
[580,] 59 32
[581,] 60 32
[582,] 60 33
[583,] 60 33
[584,] 60 33
[585,] 60 33
[586,] 60 33
[587,] 60 33
[588,] 60 33
[589,] 60 33
[590,] 60 33
[591,] 61 33
[592,] 61 33
[593,] 61 33
[594,] 61 33
[595,] 61 33
[596,] 61 33
[597,] 61 33
[598,] 61 33
[599,] 61 33
[600,] 61 33
[601,] 62 34

Is it possible somehow to count the similarities between the first and second
column and put them on a third column like this?

59 32 3
60 33 5
62 34 1

where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)

Best Regards
Alex

[[alternative HTML version deleted]]

______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Rainer M Krug-6

Re: count frequency

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1

On 17/09/10 14:19, Alaios wrote:

One solution:

> x <- data.frame(a=trunc(runif(10)*10), b=trunc(runif(10)*10))
> x
a b
1 6 5
2 7 5
3 1 5
4 0 4
5 3 9
6 6 8
7 4 3
8 0 4
9 2 7
10 7 2
> x$comb <- paste(x$a, x$b)
> x
a b comb
1 6 5 6 5
2 7 5 7 5
3 1 5 1 5
4 0 4 0 4
5 3 9 3 9
6 6 8 6 8
7 4 3 4 3
8 0 4 0 4
9 2 7 2 7
10 7 2 7 2
> table(x$comb)

0 4 1 5 2 7 3 9 4 3 6 5 6 8 7 2 7 5
2 1 1 1 1 1 1 1 1
>

I am sure, there are better ones

Cheers,

Rainer

>
> Best Regards
> Alex
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

- --
Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
Biology, UCT), Dipl. Phys. (Germany)

Centre of Excellence for Invasion Biology
Natural Sciences Building
Office Suite 2039
Stellenbosch University
Main Campus, Merriman Avenue
Stellenbosch
South Africa

Tel: +33 - (0)9 53 10 27 44
Cell: +27 - (0)8 39 47 90 42
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Fax (FR): +33 - (0)9 58 10 27 44
email: [hidden email]

Skype: RMkrug
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iEYEARECAAYFAkyTXoQACgkQoYgNqgF2egrgrgCfUOvMaUOwOC7HPSdbC2fFzdLo
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______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Henrique Dallazuanna

Re: count frequency

In reply to this post by alaios

Try this:

aggregate(rep(1, nrow(x)), x, sum)

On Fri, Sep 17, 2010 at 9:19 AM, Alaios <[hidden email]> wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,] 59 32
> [575,] 59 32
> [576,] 59 32
> [577,] 59 32
> [578,] 59 32
> [579,] 59 32
> [580,] 59 32
> [581,] 60 32
> [582,] 60 33
> [583,] 60 33
> [584,] 60 33
> [585,] 60 33
> [586,] 60 33
> [587,] 60 33
> [588,] 60 33
> [589,] 60 33
> [590,] 60 33
> [591,] 61 33
> [592,] 61 33
> [593,] 61 33
> [594,] 61 33
> [595,] 61 33
> [596,] 61 33
> [597,] 61 33
> [598,] 61 33
> [599,] 61 33
> [600,] 61 33
> [601,] 62 34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex
>
>
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

[[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Ted.Harding-2

Re: count frequency

In reply to this post by alaios

On 17-Sep-10 12:19:10, Alaios wrote:

> Hello everyone,
> please consider the following lines of a matrix
>
> [574,] 59 32
> [575,] 59 32
> [576,] 59 32
> [577,] 59 32
> [578,] 59 32
> [579,] 59 32
> [580,] 59 32
> [581,] 60 32
> [582,] 60 33
> [583,] 60 33
> [584,] 60 33
> [585,] 60 33
> [586,] 60 33
> [587,] 60 33
> [588,] 60 33
> [589,] 60 33
> [590,] 60 33
> [591,] 61 33
> [592,] 61 33
> [593,] 61 33
> [594,] 61 33
> [595,] 61 33
> [596,] 61 33
> [597,] 61 33
> [598,] 61 33
> [599,] 61 33
> [600,] 61 33
> [601,] 62 34
>
> Is it possible somehow to count the similarities between the first and
> second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
> Best Regards
> Alex

Does the following do what you want?

a <- c(59,59,59,59,59,59,59,60,60,60,60,60,60,60,
60,60,60,61,61,61,61,61,61,61,61,61,61,62)
b <- c(32,32,32,32,32,32,32,32,33,33,33,33,33,33,
33,33,33,33,33,33,33,33,33,33,33,33,33,34)

table(data.frame(a=a,b=b))
# b
# a 32 33 34
# 59 7 0 0
# 60 1 9 0
# 61 0 10 0
# 62 0 0 1

T <- t(as.matrix(table(data.frame(a=a,b=b))))
L <- c(table(data.frame(a=a,b=b)))
B <- as.integer(rep(rownames(T),each=ncol(T)))
A <- as.integer(rep(colnames(T),nrow(T)))
cbind(A,B,L)[L>0,]
# A B L
# [1,] 59 32 7
# [2,] 60 32 1
# [3,] 60 33 9
# [4,] 61 33 10
# [5,] 62 34 1

Ted.

--------------------------------------------------------------------
E-Mail: (Ted Harding) <[hidden email]>
Fax-to-email: +44 (0)870 094 0861
Date: 17-Sep-10 Time: 14:15:03
------------------------------ XFMail ------------------------------

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Jorge I Velez

Re: count frequency

In reply to this post by alaios

Alaios,

Try

as.data.frame(table(x[,1], x[,2))

where x is your matrix.

HTH,
Jorge

On Fri, Sep 17, 2010 at 8:19 AM, Alaios <> wrote:

[[alternative HTML version deleted]]

______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

alaios

Re: count frequency

Just to confirm,
this one worked for me

as.data.frame(table(temp[]))
Var1 Freq
1 1 11
2 2 29
3 3 29
4 4 29
5 5 29
6 6 29
7 7 29
8 8 29
9 9 29
10 10 29
11 11 29
12 12 29
13 13 29
14 14 29
15 15 29
16 16 29
17 17 29
18 18 30
19 19 29
20 20 29

Best Regards
Alex

________________________________
From: Jorge Ivan Velez <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 4:24:59 PM
Subject: Re: [R] count frequency

Alaios,

Try

as.data.frame(table(x[,1], x[,2))

where x is your matrix.

HTH,
Jorge

On Fri, Sep 17, 2010 at 8:19 AM, Alaios <> wrote:

Hello everyone,

>please consider the following lines of a matrix
>
>
>[574,] 59 32
>[575,] 59 32
>[576,] 59 32
>[577,] 59 32
>[578,] 59 32
>[579,] 59 32
>[580,] 59 32
>[581,] 60 32
>[582,] 60 33
>[583,] 60 33
>[584,] 60 33
>[585,] 60 33
>[586,] 60 33
>[587,] 60 33
>[588,] 60 33
>[589,] 60 33
>[590,] 60 33
>[591,] 61 33
>[592,] 61 33
>[593,] 61 33
>[594,] 61 33
>[595,] 61 33
>[596,] 61 33
>[597,] 61 33
>[598,] 61 33
>[599,] 61 33
>[600,] 61 33
>[601,] 62 34
>
>Is it possible somehow to count the similarities between the first and second
>column and put them on a third column like this?
>
>59 32 3
>60 33 5
>62 34 1
>
>where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>
>Best Regards
>Alex
>
>
>
>
> [[alternative HTML version deleted]]
>
>______________________________________________
>[hidden email] mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
>

alaios

Re: count frequency

In reply to this post by Henrique Dallazuanna

My bad :(
unfortunately does not work correct.

This is some of the output of the table
..............
[494,] 50 27
[495,] 50 27
[496,] 50 27
[497,] 50 28
[498,] 50 28
[499,] 50 28
[500,] 50 28
[501,] 51 28
[502,] 51 28
[503,] 51 28
[504,] 51 28
[505,] 51 28
[506,] 51 28
[507,] 51 28
[508,] 51 28
[509,] 51 28
[510,] 51 28
[511,] 52 28
[512,] 52 28
[513,] 52 28
[514,] 52 28
[515,] 52 28
[516,] 52 29
[517,] 52 29
[518,] 52 29

............

I need the following results
50 27: 3
50 28: 4
51 28: 10
52 28: 5
52 29: 3

So far nothing worked.
Best Regards
Alex

________________________________
From: Henrique Dallazuanna <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 3:09:36 PM
Subject: Re: [R] count frequency

Try this:

aggregate(rep(1, nrow(x)), x, sum)

Hello everyone,

Henrique Dallazuanna

Re: count frequency

So try this :

aggregate(rep(1, nrow(x)), as.data.frame(x), sum)

On Fri, Sep 17, 2010 at 11:54 AM, Alaios <[hidden email]> wrote:

> My bad :(
> unfortunately does not work correct.
>
> This is some of the output of the table
> ..............
> [494,] 50 27
> [495,] 50 27
> [496,] 50 27
> [497,] 50 28
> [498,] 50 28
> [499,] 50 28
> [500,] 50 28
> [501,] 51 28
> [502,] 51 28
> [503,] 51 28
> [504,] 51 28
> [505,] 51 28
> [506,] 51 28
> [507,] 51 28
> [508,] 51 28
> [509,] 51 28
> [510,] 51 28
> [511,] 52 28
> [512,] 52 28
> [513,] 52 28
> [514,] 52 28
> [515,] 52 28
> [516,] 52 29
> [517,] 52 29
> [518,] 52 29
> ............
>
>
> I need the following results
> 50 27: 3
> 50 28: 4
> 51 28: 10
> 52 28: 5
> 52 29: 3
>
> So far nothing worked.
> Best Regards
> Alex
>
>
>
> ------------------------------
> *From:* Henrique Dallazuanna <[hidden email]>
> *To:* Alaios <[hidden email]>
>
> *Cc:* Rhelp <[hidden email]>
> *Sent:* Fri, September 17, 2010 3:09:36 PM
>
> *Subject:* Re: [R] count frequency
>
> Try this:
>
> aggregate(rep(1, nrow(x)), x, sum)
>
> On Fri, Sep 17, 2010 at 9:19 AM, Alaios <[hidden email]> wrote:
>
>> Hello everyone,
>> please consider the following lines of a matrix
>>
>>
>> [574,] 59 32
>> [575,] 59 32
>> [576,] 59 32
>> [577,] 59 32
>> [578,] 59 32
>> [579,] 59 32
>> [580,] 59 32
>> [581,] 60 32
>> [582,] 60 33
>> [583,] 60 33
>> [584,] 60 33
>> [585,] 60 33
>> [586,] 60 33
>> [587,] 60 33
>> [588,] 60 33
>> [589,] 60 33
>> [590,] 60 33
>> [591,] 61 33
>> [592,] 61 33
>> [593,] 61 33
>> [594,] 61 33
>> [595,] 61 33
>> [596,] 61 33
>> [597,] 61 33
>> [598,] 61 33
>> [599,] 61 33
>> [600,] 61 33
>> [601,] 62 34
>>
>> Is it possible somehow to count the similarities between the first and
>> second
>> column and put them on a third column like this?
>>
>> 59 32 3
>> 60 33 5
>> 62 34 1
>>
>> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>>
>> Best Regards
>> Alex
>>
>>
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> [hidden email] mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
>

alaios

Re: count frequency

You are pretty good.
Worked nicely :)
Thanks!

Alex

________________________________
From: Henrique Dallazuanna <[hidden email]>

Cc: Rhelp <[hidden email]>
Sent: Fri, September 17, 2010 4:58:50 PM
Subject: Re: [R] count frequency

So try this :

aggregate(rep(1, nrow(x)), as.data.frame(x), sum)

My bad :(

>unfortunately does not work correct.
>
>This is some of the output of the table
>..............
>[494,] 50 27
>[495,] 50 27
>[496,] 50 27
>[497,] 50 28
>[498,] 50 28
>[499,] 50 28
>[500,] 50 28
>[501,] 51 28
>[502,] 51 28
>[503,] 51 28
>[504,] 51 28
>[505,] 51 28
>[506,] 51 28
>[507,] 51 28
>[508,] 51 28
>[509,] 51 28
>[510,] 51 28
>[511,] 52 28
>[512,] 52 28
>[513,] 52 28
>[514,] 52 28
>[515,] 52 28
>[516,] 52 29
>[517,] 52 29
>[518,] 52 29
>
>............
>
>
>I need the following results
>50 27: 3
>50 28: 4
>51 28: 10
>52 28: 5
>52 29: 3
>
>
>So far nothing worked.
>Best Regards
>Alex
>
>
>
>
>

________________________________

From: Henrique Dallazuanna <[hidden email]>

>
>Cc: Rhelp <[hidden email]>
>Sent: Fri, September 17, 2010 3:09:36 PM
>
>Subject: Re: [R] count frequency
>
>
>Try this:
>
>aggregate(rep(1, nrow(x)), x, sum)
>
>

>
>Hello everyone,
>>please consider the following lines of a matrix
>>
>>
>>[574,] 59 32
>>[575,] 59 32
>>[576,] 59 32
>>[577,] 59 32
>>[578,] 59 32
>>[579,] 59 32
>>[580,] 59 32
>>[581,] 60 32
>>[582,] 60 33
>>[583,] 60 33
>>[584,] 60 33
>>[585,] 60 33
>>[586,] 60 33
>>[587,] 60 33
>>[588,] 60 33
>>[589,] 60 33
>>[590,] 60 33
>>[591,] 61 33
>>[592,] 61 33
>>[593,] 61 33
>>[594,] 61 33
>>[595,] 61 33
>>[596,] 61 33
>>[597,] 61 33
>>[598,] 61 33
>>[599,] 61 33
>>[600,] 61 33
>>[601,] 62 34
>>
>>Is it possible somehow to count the similarities between the first and second
>>column and put them on a third column like this?
>>
>>59 32 3
>>60 33 5
>>62 34 1
>>
>>where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
>>
>>Best Regards
>>Alex
>>
>>
>>
>>
>> [[alternative HTML version deleted]]
>>
>>______________________________________________
>>[hidden email] mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>--
>Henrique Dallazuanna
>Curitiba-Paraná-Brasil
>25° 25' 40" S 49° 16' 22" O
>
>