# find the permutation function of a sorting

9 messages
Open this post in threaded view
|

## find the permutation function of a sorting

 Hi,    Is there any way to find the permutation function of the sorting and to apply the function (or its inverse) elsewhere?    For example, the following permutation function from the sorting in the matrix form is c(1,2,3), c(2,1,3) > sort(c("bc","ac","dd")) [1] "ac" "bc" "dd"    I try to find it in the permutations/permute package, but I can't find it John         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: > > Hi, > >   Is there any way to find the permutation function of the sorting and to > apply the function (or its inverse) elsewhere? > >   For example, the following permutation function from the sorting in the > matrix form is > c(1,2,3), c(2,1,3) > >> sort(c("bc","ac","dd")) > [1] "ac" "bc" "dd" > I think you are asking for the `order` function. >   I try to find it in the permutations/permute package, but I can't find it > > John > > [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 Thanks, David. I got the answer from the web. Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > x <- c(10,7,4,3,8,2) > sort(x, index.return=TRUE) \$x [1]  2  3  4  7  8 10 \$ix [1] 6 4 3 2 5 1 2018-05-23 10:49 GMT+08:00 David Winsemius <[hidden email]>: > > > > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: > > > > Hi, > > > >   Is there any way to find the permutation function of the sorting and to > > apply the function (or its inverse) elsewhere? > > > >   For example, the following permutation function from the sorting in the > > matrix form is > > c(1,2,3), c(2,1,3) > > > >> sort(c("bc","ac","dd")) > > [1] "ac" "bc" "dd" > > > > I think you are asking for the `order` function. > > >   I try to find it in the permutations/permute package, but I can't find > it > > > > John > > > >       [[alternative HTML version deleted]] > >         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 > On May 22, 2018, at 10:57 PM, John <[hidden email]> wrote: > > Thanks, David. > I got the answer from the web. > Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > > > > x <- c(10,7,4,3,8,2) > > sort(x, index.return=TRUE) > \$x > [1]  2  3  4  7  8 10 > > \$ix > [1] 6 4 3 2 5 1 > I don't understand what is being requested. The \$ix value is the same as the one returned `by order`. David. > 2018-05-23 10:49 GMT+08:00 David Winsemius <[hidden email]>: > > > > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: > > > > Hi, > > > >   Is there any way to find the permutation function of the sorting and to > > apply the function (or its inverse) elsewhere? > > > >   For example, the following permutation function from the sorting in the > > matrix form is > > c(1,2,3), c(2,1,3) > > > >> sort(c("bc","ac","dd")) > > [1] "ac" "bc" "dd" > > > > I think you are asking for the `order` function. > > >   I try to find it in the permutations/permute package, but I can't find it > > > > John > > > >       [[alternative HTML version deleted]] > > ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 Perhaps the question was "what is indexing"? On May 23, 2018 5:06:39 AM GMT+02:00, David Winsemius <[hidden email]> wrote: > > >> On May 22, 2018, at 10:57 PM, John <[hidden email]> wrote: >> >> Thanks, David. >> I got the answer from the web. >> Is there any easy way to permute a set (e.g., a set of characters) by >the permutation it returns? Thanks, >> >> >> > x <- c(10,7,4,3,8,2) >> > sort(x, index.return=TRUE) >> \$x >> [1]  2  3  4  7  8 10 >> >> \$ix >> [1] 6 4 3 2 5 1 >> > >I don't understand what is being requested. The \$ix value is the same >as the one returned `by order`. > >David. > > >> 2018-05-23 10:49 GMT+08:00 David Winsemius <[hidden email]>: >> >> >> > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: >> > >> > Hi, >> > >> >   Is there any way to find the permutation function of the sorting >and to >> > apply the function (or its inverse) elsewhere? >> > >> >   For example, the following permutation function from the sorting >in the >> > matrix form is >> > c(1,2,3), c(2,1,3) >> > >> >> sort(c("bc","ac","dd")) >> > [1] "ac" "bc" "dd" >> > >> >> I think you are asking for the `order` function. >> >> >   I try to find it in the permutations/permute package, but I can't >find it >> > >> > John >> > >> >       [[alternative HTML version deleted]] >> >> > >______________________________________________ >[hidden email] mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help>PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html>and provide commented, minimal, self-contained, reproducible code. -- Sent from my phone. Please excuse my brevity. ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 In reply to this post by David Winsemius > sort(c("bc","ac","dd"), index.return=TRUE) \$x [1] "ac" "bc" "dd" \$ix [1] 2 1 3 We have the permutation, namely 1-->2, 2-->1, 3-->3. How can I apply the permutation function to a new set c("D","E", "F")? so that the result is c("E","D", "F"). 2018-05-23 11:06 GMT+08:00 David Winsemius <[hidden email]>: > > > > On May 22, 2018, at 10:57 PM, John <[hidden email]> wrote: > > > > Thanks, David. > > I got the answer from the web. > > Is there any easy way to permute a set (e.g., a set of characters) by > the permutation it returns? Thanks, > > > > > > > x <- c(10,7,4,3,8,2) > > > sort(x, index.return=TRUE) > > \$x > > [1]  2  3  4  7  8 10 > > > > \$ix > > [1] 6 4 3 2 5 1 > > > > I don't understand what is being requested. The \$ix value is the same as > the one returned `by order`. > > David. > > > > 2018-05-23 10:49 GMT+08:00 David Winsemius <[hidden email]>: > > > > > > > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: > > > > > > Hi, > > > > > >   Is there any way to find the permutation function of the sorting and > to > > > apply the function (or its inverse) elsewhere? > > > > > >   For example, the following permutation function from the sorting in > the > > > matrix form is > > > c(1,2,3), c(2,1,3) > > > > > >> sort(c("bc","ac","dd")) > > > [1] "ac" "bc" "dd" > > > > > > > I think you are asking for the `order` function. > > > > >   I try to find it in the permutations/permute package, but I can't > find it > > > > > > John > > > > > >       [[alternative HTML version deleted]] > > > > > >         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
Open this post in threaded view
|

## Re: find the permutation function of a sorting

 > On May 22, 2018, at 11:37 PM, John <[hidden email]> wrote: > > > > sort(c("bc","ac","dd"), index.return=TRUE) > \$x > [1] "ac" "bc" "dd" > > \$ix > [1] 2 1 3 > > > We have the permutation, namely 1-->2, 2-->1, 3-->3. > How can I apply the permutation function to a new set > c("D","E", "F")? > so that the result is > c("E","D", "F"). So you want: > x <- sort(c("bc","ac","dd"), index.return=TRUE) > x \$x [1] "ac" "bc" "dd" \$ix [1] 2 1 3 >  c("D","E", "F")[ x\$ix ] [1] "E" "D" "F" > > 2018-05-23 11:06 GMT+08:00 David Winsemius <[hidden email]>: > > > > On May 22, 2018, at 10:57 PM, John <[hidden email]> wrote: > > > > Thanks, David. > > I got the answer from the web. > > Is there any easy way to permute a set (e.g., a set of characters) by the permutation it returns? Thanks, > > > > > > > x <- c(10,7,4,3,8,2) > > > sort(x, index.return=TRUE) > > \$x > > [1]  2  3  4  7  8 10 > > > > \$ix > > [1] 6 4 3 2 5 1 > > > > I don't understand what is being requested. The \$ix value is the same as the one returned `by order`. > > David. > > > > 2018-05-23 10:49 GMT+08:00 David Winsemius <[hidden email]>: > > > > > > > On May 22, 2018, at 10:06 PM, John <[hidden email]> wrote: > > > > > > Hi, > > > > > >   Is there any way to find the permutation function of the sorting and to > > > apply the function (or its inverse) elsewhere? > > > > > >   For example, the following permutation function from the sorting in the > > > matrix form is > > > c(1,2,3), c(2,1,3) > > > > > >> sort(c("bc","ac","dd")) > > > [1] "ac" "bc" "dd" > > > > > > > I think you are asking for the `order` function. > > > > >   I try to find it in the permutations/permute package, but I can't find it > > > > > > John > > > > > >       [[alternative HTML version deleted]] > > > > > > ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.