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Hi everyone.
I have a DF with the first column being my independant variable and all other columns the dependent variables. Something like: x y1 y2 y3 ... ... ... ... ... ... ... ... What I'm trying to do is to perform a linear model for each of my "y". It is pretty simple with loops, but I'm trying to vectorize it using apply. For instance, I tried something like: apply(DF, 1, function(DF){lm(DF[,1] ~ Band1[,2:5])}) But apparently it does not work. Any help would be greatly appreciated. Phil |
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On Feb 29, 2012, at 1:53 PM, Filoche wrote: > Hi everyone. > > I have a DF with the first column being my independant variable and > all > other columns the dependent variables. > > Something like: > > x y1 y2 y3 > ... ... ... ... > ... ... ... ... > > What I'm trying to do is to perform a linear model for each of my > "y". It is > pretty simple with loops, but I'm trying to vectorize it using > *apply*. > > For instance, I tried something like: > > apply(DF, 1, function(DF){lm(DF[,1] ~ Band1[,2:5])}) apply( DF[2:5], 2, function(x){lm(DF[,1] ~ x)}) You need to use the variable name that you created in the function call and loop over columns, not rows. > > But apparently it does not work. For about four or five reasons. > . David Winsemius, MD West Hartford, CT ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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On Feb 29, 2012, at 6:39 PM, David Winsemius wrote: > > On Feb 29, 2012, at 1:53 PM, Filoche wrote: > >> Hi everyone. >> >> I have a DF with the first column being my independant variable and >> all >> other columns the dependent variables. >> >> Something like: >> >> x y1 y2 y3 >> ... ... ... ... >> ... ... ... ... >> >> What I'm trying to do is to perform a linear model for each of my >> "y". It is >> pretty simple with loops, but I'm trying to vectorize it using >> *apply*. >> >> For instance, I tried something like: >> >> apply(DF, 1, function(DF){lm(DF[,1] ~ Band1[,2:5])}) > > apply( DF[2:5], 2, function(x){lm(DF[,1] ~ x)}) > > You need to use the variable name that you created in the function > call and loop over columns, not rows. I read the request wrong. It would be: apply( DF[2:5], 2, function(y){y ~ DF$x)}) > >> >> But apparently it does not work. > > For about four or five reasons. > >> . > > David Winsemius, MD > West Hartford, CT > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD West Hartford, CT ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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On 2012-02-29 15:45, David Winsemius wrote:
> > On Feb 29, 2012, at 6:39 PM, David Winsemius wrote: > >> >> On Feb 29, 2012, at 1:53 PM, Filoche wrote: >> >>> Hi everyone. >>> >>> I have a DF with the first column being my independant variable and >>> all >>> other columns the dependent variables. >>> >>> Something like: >>> >>> x y1 y2 y3 >>> ... ... ... ... >>> ... ... ... ... >>> >>> What I'm trying to do is to perform a linear model for each of my >>> "y". It is >>> pretty simple with loops, but I'm trying to vectorize it using >>> *apply*. >>> >>> For instance, I tried something like: >>> >>> apply(DF, 1, function(DF){lm(DF[,1] ~ Band1[,2:5])}) >> >> apply( DF[2:5], 2, function(x){lm(DF[,1] ~ x)}) >> >> You need to use the variable name that you created in the function >> call and loop over columns, not rows. > > I read the request wrong. It would be: > > apply( DF[2:5], 2, function(y){y ~ DF$x)}) Another possibility: from ?lm: "If response is a matrix a linear model is fitted separately by least-squares to each column of the matrix." Peter Ehlers > > >> >>> >>> But apparently it does not work. >> >> For about four or five reasons. >> >>> . >> >> David Winsemius, MD >> West Hartford, CT >> >> ______________________________________________ >> [hidden email] mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. > > David Winsemius, MD > West Hartford, CT > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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