Hi,
the function outer can not apply a constant function as in the last line of the following example: > xg <- 1:4 > yg <- 1:4 > fxyg <- outer(xg, yg, function(x,y) x*y) > fconstg <- outer(xg, yg, function(x,y) 1.0) Error in outer(xg, yg, function(x, y) 1) : dims [product 16] do not match the length of object [1] Of course there are simpler ways to construct a constant matrix, that is not my point. It happens for me in the context of generating matrices of partial derivatives, and if on of these partial derivatives happens to be constant it fails. So e.g this works: library(Deriv) f <- function(x,y) (x-1.5)*(y-1)*(x-1.8)+(y-1.9)^2*(x-1.1)^3 fx <- Deriv(f,"x") fy <- Deriv(f,"y") fxy <- Deriv(Deriv(f,"y"),"x") fxx <- Deriv(Deriv(f,"x"),"x") fyy <- Deriv(Deriv(f,"y"),"y") fg <- outer(xg,yg,f) fxg <- outer(xg,yg,fx) fyg <- outer(xg,yg,fy) fxyg <- outer(xg,yg,fxy) fxxg <- outer(xg,yg,fxx) fyyg <- outer(xg,yg,fyy) And with f <- function(x,y) x+y it stops working. Of course I can manually fix this for that special case, but thats not my point. I simply thought "outer" should be able to handle constant functions. Best regards Albrecht [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-devel |
>>>>> Gebhardt, Albrecht <[hidden email]>
>>>>> on Sun, 19 Mar 2017 09:14:56 +0000 writes: > Hi, > the function outer can not apply a constant function as in the last line of the following example: >> xg <- 1:4 >> yg <- 1:4 >> fxyg <- outer(xg, yg, function(x,y) x*y) >> fconstg <- outer(xg, yg, function(x,y) 1.0) > Error in outer(xg, yg, function(x, y) 1) : > dims [product 16] do not match the length of object [1] > Of course there are simpler ways to construct a constant matrix, that is not my point. > It happens for me in the context of generating matrices of partial derivatives, and if on of these partial derivatives happens to be constant it fails. > So e.g this works: > library(Deriv) > f <- function(x,y) (x-1.5)*(y-1)*(x-1.8)+(y-1.9)^2*(x-1.1)^3 > fx <- Deriv(f,"x") > fy <- Deriv(f,"y") > fxy <- Deriv(Deriv(f,"y"),"x") > fxx <- Deriv(Deriv(f,"x"),"x") > fyy <- Deriv(Deriv(f,"y"),"y") > fg <- outer(xg,yg,f) > fxg <- outer(xg,yg,fx) > fyg <- outer(xg,yg,fy) > fxyg <- outer(xg,yg,fxy) > fxxg <- outer(xg,yg,fxx) > fyyg <- outer(xg,yg,fyy) > And with > f <- function(x,y) x+y > it stops working. Of course I can manually fix this for that special case, but thats not my point. I simply thought "outer" should be able to handle constant functions. ?outer clearly states that FUN needs to be vectorized but function(x,y) 1 is not. It is easy to solve by wrapping the function in Vectorize(.): > x <- 1:3; y <- 1:4 > outer(x,y, function(x,y) 1) Error in dim(robj) <- c(dX, dY) : dims [product 12] do not match the length of object [1] > outer(x,y, Vectorize(function(x,y) 1)) [,1] [,2] [,3] [,4] [1,] 1 1 1 1 [2,] 1 1 1 1 [3,] 1 1 1 1 ---------------- So, your "should" above must be read in the sense "It really would be convenient here and correspond to other "recycling" behavior of R" and I agree with that, having experienced the same inconvenience as you several times in the past. outer() being a nice R-level function (i.e., no C speed up) makes it easy to improve: Adding something like the line if(length(robj) == 1L) robj <- rep.int(robj, dX*dY) before dim(robj) <- c(dX, dY) [which gave the error] would solve the issue and not cost much (in the cases it is unneeded). Or is this a bad idea? ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-devel |
> Or is this a bad idea?
I don't like the proposal. I have seen code like the following (in fact, I have written such code, where I had forgotten a function was not vectorized) where the error would have been discovered much later if outer() didn't catch it. > outer(1:3, 11:13, sum) Error in outer(1:3, 11:13, sum) : dims [product 9] do not match the length of object [1] Bill Dunlap TIBCO Software wdunlap tibco.com On Mon, Mar 20, 2017 at 6:36 AM, Martin Maechler <[hidden email]> wrote: >>>>>> Gebhardt, Albrecht <[hidden email]> >>>>>> on Sun, 19 Mar 2017 09:14:56 +0000 writes: > > > Hi, > > the function outer can not apply a constant function as in the last line of the following example: > > >> xg <- 1:4 > >> yg <- 1:4 > >> fxyg <- outer(xg, yg, function(x,y) x*y) > >> fconstg <- outer(xg, yg, function(x,y) 1.0) > > Error in outer(xg, yg, function(x, y) 1) : > > dims [product 16] do not match the length of object [1] > > > Of course there are simpler ways to construct a constant matrix, that is not my point. > > > It happens for me in the context of generating matrices of partial derivatives, and if on of these partial derivatives happens to be constant it fails. > > > So e.g this works: > > > library(Deriv) > > f <- function(x,y) (x-1.5)*(y-1)*(x-1.8)+(y-1.9)^2*(x-1.1)^3 > > fx <- Deriv(f,"x") > > fy <- Deriv(f,"y") > > fxy <- Deriv(Deriv(f,"y"),"x") > > fxx <- Deriv(Deriv(f,"x"),"x") > > fyy <- Deriv(Deriv(f,"y"),"y") > > > fg <- outer(xg,yg,f) > > fxg <- outer(xg,yg,fx) > > fyg <- outer(xg,yg,fy) > > fxyg <- outer(xg,yg,fxy) > > fxxg <- outer(xg,yg,fxx) > > fyyg <- outer(xg,yg,fyy) > > > And with > > > f <- function(x,y) x+y > > > it stops working. Of course I can manually fix this for that special case, but thats not my point. I simply thought "outer" should be able to handle constant functions. > > ?outer clearly states that FUN needs to be vectorized > > but function(x,y) 1 is not. > > It is easy to solve by wrapping the function in Vectorize(.): > >> x <- 1:3; y <- 1:4 > >> outer(x,y, function(x,y) 1) > Error in dim(robj) <- c(dX, dY) : > dims [product 12] do not match the length of object [1] > >> outer(x,y, Vectorize(function(x,y) 1)) > [,1] [,2] [,3] [,4] > [1,] 1 1 1 1 > [2,] 1 1 1 1 > [3,] 1 1 1 1 > > ---------------- > > So, your "should" above must be read in the sense > > "It really would be convenient here and > correspond to other "recycling" behavior of R" > > and I agree with that, having experienced the same inconvenience > as you several times in the past. > > outer() being a nice R-level function (i.e., no C speed up) > makes it easy to improve: > > Adding something like the line > > if(length(robj) == 1L) robj <- rep.int(robj, dX*dY) > > before dim(robj) <- c(dX, dY) [which gave the error] > > would solve the issue and not cost much (in the cases it is unneeded). > > Or is this a bad idea? > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-devel ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-devel |
>>>>> William Dunlap <[hidden email]>
>>>>> on Mon, 20 Mar 2017 10:20:11 -0700 writes: >> Or is this a bad idea? > I don't like the proposal. I have seen code like the following (in > fact, I have written such code, where I had forgotten a function was > not vectorized) where the error would have been discovered much later > if outer() didn't catch it. >> outer(1:3, 11:13, sum) > Error in outer(1:3, 11:13, sum) : > dims [product 9] do not match the length of object [1] > Bill Dunlap > TIBCO Software > wdunlap tibco.com You are right, thank you! Such a "convenience change" would not be a good idea. Martin Maechler ETH Zurich > On Mon, Mar 20, 2017 at 6:36 AM, Martin Maechler > <[hidden email]> wrote: >>>>>>> Gebhardt, Albrecht <[hidden email]> >>>>>>> on Sun, 19 Mar 2017 09:14:56 +0000 writes: >> >> > Hi, >> > the function outer can not apply a constant function as in the last line of the following example: >> >> >> xg <- 1:4 >> >> yg <- 1:4 >> >> fxyg <- outer(xg, yg, function(x,y) x*y) >> >> fconstg <- outer(xg, yg, function(x,y) 1.0) >> > Error in outer(xg, yg, function(x, y) 1) : >> > dims [product 16] do not match the length of object [1] >> >> > Of course there are simpler ways to construct a constant matrix, that is not my point. >> >> > It happens for me in the context of generating matrices of partial derivatives, and if on of these partial derivatives happens to be constant it fails. >> >> > So e.g this works: >> >> > library(Deriv) >> > f <- function(x,y) (x-1.5)*(y-1)*(x-1.8)+(y-1.9)^2*(x-1.1)^3 >> > fx <- Deriv(f,"x") >> > fy <- Deriv(f,"y") >> > fxy <- Deriv(Deriv(f,"y"),"x") >> > fxx <- Deriv(Deriv(f,"x"),"x") >> > fyy <- Deriv(Deriv(f,"y"),"y") >> >> > fg <- outer(xg,yg,f) >> > fxg <- outer(xg,yg,fx) >> > fyg <- outer(xg,yg,fy) >> > fxyg <- outer(xg,yg,fxy) >> > fxxg <- outer(xg,yg,fxx) >> > fyyg <- outer(xg,yg,fyy) >> >> > And with >> >> > f <- function(x,y) x+y >> >> > it stops working. Of course I can manually fix this for that special case, but thats not my point. I simply thought "outer" should be able to handle constant functions. >> >> ?outer clearly states that FUN needs to be vectorized >> >> but function(x,y) 1 is not. >> >> It is easy to solve by wrapping the function in Vectorize(.): >> >>> x <- 1:3; y <- 1:4 >> >>> outer(x,y, function(x,y) 1) >> Error in dim(robj) <- c(dX, dY) : >> dims [product 12] do not match the length of object [1] >> >>> outer(x,y, Vectorize(function(x,y) 1)) >> [,1] [,2] [,3] [,4] >> [1,] 1 1 1 1 >> [2,] 1 1 1 1 >> [3,] 1 1 1 1 >> >> ---------------- >> >> So, your "should" above must be read in the sense >> >> "It really would be convenient here and >> correspond to other "recycling" behavior of R" >> >> and I agree with that, having experienced the same inconvenience >> as you several times in the past. >> >> outer() being a nice R-level function (i.e., no C speed up) >> makes it easy to improve: >> >> Adding something like the line >> >> if(length(robj) == 1L) robj <- rep.int(robj, dX*dY) >> >> before dim(robj) <- c(dX, dY) [which gave the error] >> >> would solve the issue and not cost much (in the cases it is unneeded). >> >> Or is this a bad idea? >> >> ______________________________________________ >> [hidden email] mailing list >> https://stat.ethz.ch/mailman/listinfo/r-devel ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-devel |
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