Hi

just messing around today and am now perplexed by the seq argument "along.with".

Please, I am just just seeking some knowledge here. Obviously I missed a point

and would like to know what it is.

seq(1,10,length.out = 2) makes sense

seq(1,10,by = 2) makes sense

seq(1,10, along.with = 2) What is the purpose of this argument????

per "help" page

along.with

take the length from the length of this argument (assuming "length" here

refers to length of output). Would that not mean I should get two

numbers?

Regardless of the value of the along.with argument, it just returns 1. Which

then leads me to be believe that the output will be the number (length) of arguments,i.e., length of the along.with argument, which indeed it does.

seq(1,10,along.with = c(1,3,5,7)) yields 1 4 7 10

seq(1,10,along.with = c(111,13,5555,7) yields 1 4 7 10

seq(1,10,along.with = c("a","b","c","d")) yields 1 4 7 10

Obviously the authors of this function saw a need for this argument, but I am

just not bright enough to figure out what that purpose was. It appears

to me that length.out does the same thing in a much more straightforward

manner, but then I am probably missing some point, subtle or otherwise.

Carl Sutton

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