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Hi R User, Would you give me your hand to standardize some columns in a matrix? I have included the example table. > dput(test) structure(list(X = c(1, 2, 3, 4, 5, 6), Y = c(4, 5, 6, 7, 8, 9), temp = c(0.818, 0.113, 0.256, 0.587, 0.955, 0.207), oxy = c(0.797, 0.487, 0.727, 0.128, 0.514, 0.031)), .Names = c("X", "Y", "temp", "oxy"), row.names = c(NA, -6L), class = "data.frame") here I wanted to standardize the variable "temp" and "oxy". I have more than 75 variables so that I need to apply 'loop'. Could you help me to make a loop? I wrote following but, it did not work. for (i in 1:n(test)){ for (t in 1:T (test)) x.z[i] = (x[i,t] - mean(x(i,]/sd)x[i,]) } Thanks for your help. Kristi [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Hello,
Try scale(test[, c("temp", "oxy")]) Hope this helps, Rui Barradas Em 28-06-2012 20:11, Kristi Glover escreveu: > > Hi R User, > Would you give me your hand to standardize some columns in a matrix? > > I have included the example table. > >> dput(test) > structure(list(X = c(1, 2, 3, 4, 5, 6), Y = c(4, 5, 6, 7, 8, > 9), temp = c(0.818, 0.113, 0.256, 0.587, 0.955, 0.207), oxy = c(0.797, > 0.487, 0.727, 0.128, 0.514, 0.031)), .Names = c("X", "Y", "temp", > "oxy"), row.names = c(NA, -6L), class = "data.frame") > > here I wanted to standardize the variable "temp" and "oxy". I have more than 75 variables so that I need to apply 'loop'. > > Could you help me to make a loop? > > I wrote following but, it did not work. > > for (i in 1:n(test)){ > for (t in 1:T (test)) x.z[i] = (x[i,t] - mean(x(i,]/sd)x[i,]) > } > > Thanks for your help. > > Kristi > > > [[alternative HTML version deleted]] > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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In reply to this post by Kristi Glover
On 29/06/12 07:11, Kristi Glover wrote:
> Hi R User, > Would you give me your hand to standardize some columns in a matrix? No I would not give you my hand. I'm already married! :-) cheers, Rolf Turner ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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In reply to this post by Kristi Glover
Hi, you could use scale() test[,3:4]<-scale(test[,3:4]) > test X Y temp oxy [1,] 1 4 0.9408239 1.1264280 [2,] 2 5 -1.0772720 0.1277835 [3,] 3 6 -0.6679277 0.9009276 [4,] 4 7 0.2795755 -1.0287112 [5,] 5 8 1.3329929 0.2147622 [6,] 6 9 -0.8081926 -1.3411902 A.K. ----- Original Message ----- From: Kristi Glover <[hidden email]> To: R-help <[hidden email]> Cc: Sent: Thursday, June 28, 2012 3:11 PM Subject: [R] would you give me your hand to standardize columns in a matrix? Hi R User, Would you give me your hand to standardize some columns in a matrix? I have included the example table. > dput(test) structure(list(X = c(1, 2, 3, 4, 5, 6), Y = c(4, 5, 6, 7, 8, 9), temp = c(0.818, 0.113, 0.256, 0.587, 0.955, 0.207), oxy = c(0.797, 0.487, 0.727, 0.128, 0.514, 0.031)), .Names = c("X", "Y", "temp", "oxy"), row.names = c(NA, -6L), class = "data.frame") here I wanted to standardize the variable "temp" and "oxy". I have more than 75 variables so that I need to apply 'loop'. Could you help me to make a loop? I wrote following but, it did not work. for (i in 1:n(test)){ for (t in 1:T (test)) x.z[i] = (x[i,t] - mean(x(i,]/sd)x[i,]) } Thanks for your help. Kristi [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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