# year and week to date - before 1/1 and after 12/31

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## year and week to date - before 1/1 and after 12/31

 hi, to turn year and week into the date one can do the following: as.Date('2018 05 Sun', "%Y %W %a") however, when we want the Sunday (1st day of week) of the 1st week of 2018 we get NA because 1/1/2018 was on Monday as.Date('2018 00 Mon',format="%Y %U %a") ## 2018-01-01 as.Date('2018 00 Sun',format="%Y %U %a") ## NA btw the same goes for last week as.Date('2017 53 Sun',format="%Y %U %a") ## 2017-12-31 as.Date('2017 53 Mon',format="%Y %U %a") ## NA So my question is : how do i get from "2018 00 Sun" to 2018-12-31 and from "2017 53 Mon" to 2018-01-01 i realize i can loop over days of week and do some if/then statements, but is there a built in function? thank you peter -- Peter Salzman, PhD Department of Biostatistics and Computational Biology University of Rochester         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: year and week to date - before 1/1 and after 12/31

 it is simpler than i thought first day of given week is the last day minus 6days in other words: d1 = as.Date('2018 00 Sat',format="%Y %U %a") - 6 d2 = as.Date('2018 00 Sun',format="%Y %U %a") are the same as long both are not NA therefore to get the one that is not NA one can do max( c(d1,d2), na.rm=TRUE ) maybe there is some other trick best, peter On Tue, Oct 16, 2018 at 10:22 AM peter salzman <[hidden email]> wrote: > hi, > > to turn year and week into the date one can do the following: > > as.Date('2018 05 Sun', "%Y %W %a") > > however, when we want the Sunday (1st day of week) of the 1st week of 2018 > we get NA because 1/1/2018 was on Monday > > as.Date('2018 00 Mon',format="%Y %U %a") > ## 2018-01-01 > as.Date('2018 00 Sun',format="%Y %U %a") > ## NA > > btw the same goes for last week > as.Date('2017 53 Sun',format="%Y %U %a") > ## 2017-12-31 > as.Date('2017 53 Mon',format="%Y %U %a") > ## NA > > So my question is : > how do i get > from "2018 00 Sun" to 2018-12-31 > and > from "2017 53 Mon" to 2018-01-01 > > i realize i can loop over days of week and do some if/then statements, > but is there a built in function? > > thank you > peter > > > > > > -- > Peter Salzman, PhD > Department of Biostatistics and Computational Biology > University of Rochester > -- Peter Salzman, PhD Department of Biostatistics and Computational Biology University of Rochester         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: year and week to date - before 1/1 and after 12/31

 If the date in your character representation does not exist then there is no requirement for a POSIX function to give any reliable answer... including NA. Using 00 as the week number won't always work. The first week/weekday combination that is guaranteed to exist by POSIX is 1/1 (first Monday). If the corresponding mon/mday is 1/1 then no days exist in week zero for that year and the first Sunday is 6 days more than the mday of the first Monday, else the mday of the first Sunday is one day less than the mday of the first Monday. You should if at all possible repair the computations that are creating the invalid string dates you mention. On October 16, 2018 8:11:12 AM PDT, peter salzman <[hidden email]> wrote: >it is simpler than i thought > >first day of given week is the last day minus 6days > >in other words: >d1 = as.Date('2018 00 Sat',format="%Y %U %a") - 6 >d2 = as.Date('2018 00 Sun',format="%Y %U %a") >are the same as long both are not NA > >therefore to get the one that is not NA one can do > >max( c(d1,d2), na.rm=TRUE ) > >maybe there is some other trick > >best, >peter > > > > > > >On Tue, Oct 16, 2018 at 10:22 AM peter salzman ><[hidden email]> >wrote: > >> hi, >> >> to turn year and week into the date one can do the following: >> >> as.Date('2018 05 Sun', "%Y %W %a") >> >> however, when we want the Sunday (1st day of week) of the 1st week of >2018 >> we get NA because 1/1/2018 was on Monday >> >> as.Date('2018 00 Mon',format="%Y %U %a") >> ## 2018-01-01 >> as.Date('2018 00 Sun',format="%Y %U %a") >> ## NA >> >> btw the same goes for last week >> as.Date('2017 53 Sun',format="%Y %U %a") >> ## 2017-12-31 >> as.Date('2017 53 Mon',format="%Y %U %a") >> ## NA >> >> So my question is : >> how do i get >> from "2018 00 Sun" to 2018-12-31 >> and >> from "2017 53 Mon" to 2018-01-01 >> >> i realize i can loop over days of week and do some if/then >statements, >> but is there a built in function? >> >> thank you >> peter >> >> >> >> >> >> -- >> Peter Salzman, PhD >> Department of Biostatistics and Computational Biology >> University of Rochester >> -- Sent from my phone. Please excuse my brevity. ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: year and week to date - before 1/1 and after 12/31

 Er, my mistake, you are using %U not %W... but now I am really confused, because the first Sunday is trivial with %U/%u. Can you clarify what your actual upstream input is? Is it an invalid date string as you say below, or is it year number? On October 16, 2018 10:22:10 AM PDT, Jeff Newmiller <[hidden email]> wrote: >If the date in your character representation does not exist then there >is no requirement for a POSIX function to give any reliable answer... >including NA. Using 00 as the week number won't always work. > >The first week/weekday combination that is guaranteed to exist by POSIX >is 1/1 (first Monday). If the corresponding mon/mday is 1/1 then no >days exist in week zero for that year and the first Sunday is 6 days >more than the mday of the first Monday, else the mday of the first >Sunday is one day less than the mday of the first Monday. > >You should if at all possible repair the computations that are creating >the invalid string dates you mention. > >On October 16, 2018 8:11:12 AM PDT, peter salzman ><[hidden email]> wrote: >>it is simpler than i thought >> >>first day of given week is the last day minus 6days >> >>in other words: >>d1 = as.Date('2018 00 Sat',format="%Y %U %a") - 6 >>d2 = as.Date('2018 00 Sun',format="%Y %U %a") >>are the same as long both are not NA >> >>therefore to get the one that is not NA one can do >> >>max( c(d1,d2), na.rm=TRUE ) >> >>maybe there is some other trick >> >>best, >>peter >> >> >> >> >> >> >>On Tue, Oct 16, 2018 at 10:22 AM peter salzman >><[hidden email]> >>wrote: >> >>> hi, >>> >>> to turn year and week into the date one can do the following: >>> >>> as.Date('2018 05 Sun', "%Y %W %a") >>> >>> however, when we want the Sunday (1st day of week) of the 1st week >of >>2018 >>> we get NA because 1/1/2018 was on Monday >>> >>> as.Date('2018 00 Mon',format="%Y %U %a") >>> ## 2018-01-01 >>> as.Date('2018 00 Sun',format="%Y %U %a") >>> ## NA >>> >>> btw the same goes for last week >>> as.Date('2017 53 Sun',format="%Y %U %a") >>> ## 2017-12-31 >>> as.Date('2017 53 Mon',format="%Y %U %a") >>> ## NA >>> >>> So my question is : >>> how do i get >>> from "2018 00 Sun" to 2018-12-31 >>> and >>> from "2017 53 Mon" to 2018-01-01 >>> >>> i realize i can loop over days of week and do some if/then >>statements, >>> but is there a built in function? >>> >>> thank you >>> peter >>> >>> >>> >>> >>> >>> -- >>> Peter Salzman, PhD >>> Department of Biostatistics and Computational Biology >>> University of Rochester >>> -- Sent from my phone. Please excuse my brevity. ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: year and week to date - before 1/1 and after 12/31

 hi, thanks for replying, it has taken some time to understand i have year+week and i need to find the 1st day and the last day of that week i can decide when week starts for example these 3 examples: df <- data.frame(id = 1:3, year = c(2018, 2018, 2018), week=c(0,1,52)) ## now run for all 3 rows: for (kk in 1:3) {   print(df[kk,])   print('## version 1')   print(as.Date(paste(df\$year[kk],df\$week[kk],'Sun',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Mon',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Tue',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Wed',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Thu',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Fri',sep=' '), format = "%Y %U %a")       )   print(as.Date(paste(df\$year[kk],df\$week[kk],'Sat',sep=' '), format = "%Y %U %a")       )   print('## version 2')   print(as.Date(paste(df\$year[kk],df\$week[kk],'7',sep=' '), format = "%Y %U %u")        )   print(as.Date(paste(df\$year[kk],df\$week[kk],'1',sep=' '), format = "%Y %U %u")         )   print(as.Date(paste(df\$year[kk],df\$week[kk],'2',sep=' '), format = "%Y %U %u")         )   print(as.Date(paste(df\$year[kk],df\$week[kk],'3',sep=' '), format = "%Y %U %u")         )   print(as.Date(paste(df\$year[kk],df\$week[kk],'4',sep=' '), format = "%Y %U %u")         )   print(as.Date(paste(df\$year[kk],df\$week[kk],'5',sep=' '), format = "%Y %U %u")         )   print(as.Date(paste(df\$year[kk],df\$week[kk],'6',sep=' '), format = "%Y %U %u")         ) } for week 0 we get NA for Sunday because it was Dec 31, 2017 similarly for week 52 we get NA for Tue,Wed, ... because these are in January of 2019 my hope was to write as.Date(paste(year,week,1), format "%Y %month %weekday") as.Date(paste(year,week,7), format "%Y %month %weekday") and get the first and last day of the given week even at the beginning and end of year for example as.Date("2018 0 Sun","%Y %U %a")   = '2017-12-31' i hope this makes sense. thanks for replying peter On Tue, Oct 16, 2018 at 2:11 PM Jeff Newmiller <[hidden email]> wrote: > Er, my mistake, you are using %U not %W... but now I am really confused, > because the first Sunday is trivial with %U/%u. > > Can you clarify what your actual upstream input is? Is it an invalid date > string as you say below, or is it year number? > > On October 16, 2018 10:22:10 AM PDT, Jeff Newmiller < > [hidden email]> wrote: > >If the date in your character representation does not exist then there > >is no requirement for a POSIX function to give any reliable answer... > >including NA. Using 00 as the week number won't always work. > > > >The first week/weekday combination that is guaranteed to exist by POSIX > >is 1/1 (first Monday). If the corresponding mon/mday is 1/1 then no > >days exist in week zero for that year and the first Sunday is 6 days > >more than the mday of the first Monday, else the mday of the first > >Sunday is one day less than the mday of the first Monday. > > > >You should if at all possible repair the computations that are creating > >the invalid string dates you mention. > > > >On October 16, 2018 8:11:12 AM PDT, peter salzman > ><[hidden email]> wrote: > >>it is simpler than i thought > >> > >>first day of given week is the last day minus 6days > >> > >>in other words: > >>d1 = as.Date('2018 00 Sat',format="%Y %U %a") - 6 > >>d2 = as.Date('2018 00 Sun',format="%Y %U %a") > >>are the same as long both are not NA > >> > >>therefore to get the one that is not NA one can do > >> > >>max( c(d1,d2), na.rm=TRUE ) > >> > >>maybe there is some other trick > >> > >>best, > >>peter > >> > >> > >> > >> > >> > >> > >>On Tue, Oct 16, 2018 at 10:22 AM peter salzman > >><[hidden email]> > >>wrote: > >> > >>> hi, > >>> > >>> to turn year and week into the date one can do the following: > >>> > >>> as.Date('2018 05 Sun', "%Y %W %a") > >>> > >>> however, when we want the Sunday (1st day of week) of the 1st week > >of > >>2018 > >>> we get NA because 1/1/2018 was on Monday > >>> > >>> as.Date('2018 00 Mon',format="%Y %U %a") > >>> ## 2018-01-01 > >>> as.Date('2018 00 Sun',format="%Y %U %a") > >>> ## NA > >>> > >>> btw the same goes for last week > >>> as.Date('2017 53 Sun',format="%Y %U %a") > >>> ## 2017-12-31 > >>> as.Date('2017 53 Mon',format="%Y %U %a") > >>> ## NA > >>> > >>> So my question is : > >>> how do i get > >>> from "2018 00 Sun" to 2018-12-31 > >>> and > >>> from "2017 53 Mon" to 2018-01-01 > >>> > >>> i realize i can loop over days of week and do some if/then > >>statements, > >>> but is there a built in function? > >>> > >>> thank you > >>> peter > >>> > >>> > >>> > >>> > >>> > >>> -- > >>> Peter Salzman, PhD > >>> Department of Biostatistics and Computational Biology > >>> University of Rochester > >>> > > -- > Sent from my phone. Please excuse my brevity. > -- Peter Salzman, PhD BMS Greater Boston Area, MA         [[alternative HTML version deleted]] ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: year and week to date - before 1/1 and after 12/31

 You cannot obtain a predictable result by sending invalid time representation data to strptime... you have to work with valid time representations. See sample approach below: ############################ weekEnds <- function( DF ) {     d1_1 <- as.Date( sprintf( "%04d 1 1"                             , DF[[ "Y" ]]                             )                    , format = "%Y %U %u"                    )     d52_7 <- as.Date( sprintf( "%04d 52 7"                              , DF[[ "Y" ]]                              )                     , format = "%Y %U %u"                     )     week <- as.difftime( 7, units = "days" )     day <- as.difftime( 1, units = "days" )     d <- as.Date( sprintf( "%04d %d 1"                          , DF[[ "Y" ]]                          , DF[[ "wn" ]]                          )                 , format = "%Y %U %u"                 )     before <- 0 == DF[[ "wn" ]]     after <- 53 == DF[[ "wn" ]]     d[ before ] <- d1_1[ before ] - week     d[ after ] <- d52_7[ after ] + day     DF[[ "weekBegin" ]] <- d     DF[[ "weekEnd" ]] <- d + week     DF } tst <- expand.grid( Y = 2000:2028                    , wn = c( 0, 1, 53 )                    ) result <- weekEnds( tst ) set.seed( 42 ) result[ sample( nrow( result ), 5 ), ] #>       Y wn  weekBegin    weekEnd #> 80 2021 53 2021-12-27 2022-01-03 #> 81 2022 53 2022-12-26 2023-01-02 #> 25 2024  0 2024-01-01 2024-01-08 #> 70 2011 53 2011-12-26 2012-01-02 #> 54 2024  1 2024-01-08 2024-01-15 sum( is.na( result\$weekBegin ) ) #> [1] 0 ############################ On Tue, 16 Oct 2018, peter salzman wrote: > hi, > thanks for replying, > > it has taken some time to understand > > i have year+week and i need to find the 1st day and the last day of that week > i can decide when week starts > > for example these 3 examples: > df <- data.frame(id = 1:3, year = c(2018, 2018, 2018), week=c(0,1,52)) > > ## now run for all 3 rows: > for (kk in 1:3) { >   print(df[kk,]) >   print('## version 1') >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Sun',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Mon',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Tue',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Wed',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Thu',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Fri',sep=' '), format = "%Y %U %a")       )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'Sat',sep=' '), format = "%Y %U %a")       ) >    >   print('## version 2') >   print(as.Date(paste(df\$year[kk],df\$week[kk],'7',sep=' '), format = "%Y %U %u")        )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'1',sep=' '), format = "%Y %U %u")         )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'2',sep=' '), format = "%Y %U %u")         )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'3',sep=' '), format = "%Y %U %u")         )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'4',sep=' '), format = "%Y %U %u")         )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'5',sep=' '), format = "%Y %U %u")         )  >   print(as.Date(paste(df\$year[kk],df\$week[kk],'6',sep=' '), format = "%Y %U %u")         ) > } > > for week 0 we get NA for Sunday because it was Dec 31, 2017 > similarly for week 52 we get NA for Tue,Wed, ... because these are in January of 2019 > > my hope was to write  > as.Date(paste(year,week,1), format "%Y %month %weekday") > as.Date(paste(year,week,7), format "%Y %month %weekday") > and get the first and last day of the given week even at the beginning and end of year > for example > as.Date("2018 0 Sun","%Y %U %a")   = '2017-12-31' > > i hope this makes sense. > > thanks for replying > peter > > > > > > > > > > > On Tue, Oct 16, 2018 at 2:11 PM Jeff Newmiller <[hidden email]> wrote: >       Er, my mistake, you are using %U not %W... but now I am really confused, because the first Sunday is trivial with %U/%u. > >       Can you clarify what your actual upstream input is? Is it an invalid date string as you say below, or is it year number? > >       On October 16, 2018 10:22:10 AM PDT, Jeff Newmiller <[hidden email]> wrote: >       >If the date in your character representation does not exist then there >       >is no requirement for a POSIX function to give any reliable answer... >       >including NA. Using 00 as the week number won't always work. >       > >       >The first week/weekday combination that is guaranteed to exist by POSIX >       >is 1/1 (first Monday). If the corresponding mon/mday is 1/1 then no >       >days exist in week zero for that year and the first Sunday is 6 days >       >more than the mday of the first Monday, else the mday of the first >       >Sunday is one day less than the mday of the first Monday. >       > >       >You should if at all possible repair the computations that are creating >       >the invalid string dates you mention. >       > >       >On October 16, 2018 8:11:12 AM PDT, peter salzman >       ><[hidden email]> wrote: >       >>it is simpler than i thought >       >> >       >>first day of given week is the last day minus 6days >       >> >       >>in other words: >       >>d1 = as.Date('2018 00 Sat',format="%Y %U %a") - 6 >       >>d2 = as.Date('2018 00 Sun',format="%Y %U %a") >       >>are the same as long both are not NA >       >> >       >>therefore to get the one that is not NA one can do >       >> >       >>max( c(d1,d2), na.rm=TRUE ) >       >> >       >>maybe there is some other trick >       >> >       >>best, >       >>peter >       >> >       >> >       >> >       >> >       >> >       >> >       >>On Tue, Oct 16, 2018 at 10:22 AM peter salzman >       >><[hidden email]> >       >>wrote: >       >> >       >>> hi, >       >>> >       >>> to turn year and week into the date one can do the following: >       >>> >       >>> as.Date('2018 05 Sun', "%Y %W %a") >       >>> >       >>> however, when we want the Sunday (1st day of week) of the 1st week >       >of >       >>2018 >       >>> we get NA because 1/1/2018 was on Monday >       >>> >       >>> as.Date('2018 00 Mon',format="%Y %U %a") >       >>> ## 2018-01-01 >       >>> as.Date('2018 00 Sun',format="%Y %U %a") >       >>> ## NA >       >>> >       >>> btw the same goes for last week >       >>> as.Date('2017 53 Sun',format="%Y %U %a") >       >>> ## 2017-12-31 >       >>> as.Date('2017 53 Mon',format="%Y %U %a") >       >>> ## NA >       >>> >       >>> So my question is : >       >>> how do i get >       >>> from "2018 00 Sun" to 2018-12-31 >       >>> and >       >>> from "2017 53 Mon" to 2018-01-01 >       >>> >       >>> i realize i can loop over days of week and do some if/then >       >>statements, >       >>> but is there a built in function? >       >>> >       >>> thank you >       >>> peter >       >>> >       >>> >       >>> >       >>> >       >>> >       >>> -- >       >>> Peter Salzman, PhD >       >>> Department of Biostatistics and Computational Biology >       >>> University of Rochester >       >>> > >       -- >       Sent from my phone. Please excuse my brevity. > > > > -- > Peter Salzman, PhD > BMS > Greater Boston Area, MA > > --------------------------------------------------------------------------- Jeff Newmiller                        The     .....       .....  Go Live... DCN:<[hidden email]>        Basics: ##.#.       ##.#.  Live Go...                                        Live:   OO#.. Dead: OO#..  Playing Research Engineer (Solar/Batteries            O.O#.       #.O#.  with /Software/Embedded Controllers)               .OO#.       .OO#.  rocks...1k --------------------------------------------------------------------------- ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.