

package "caTools"
see ?trapz


Mr ". .",
MASS::area comes to mind but it may be more helpful if you could say what
you are looking for / why integrate is not appropriate it is for whatever
you are doing.
Strictly speaking, I suppose there are all sorts of "alternatives" to
integrate() if you are willing to be really creative and build something
from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
Michael Weylandt
On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
[[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Hi Michael,
This is the problem:
func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
result < function(x) {
f1 < function(n) {
f < function() {
dcom < paste("d", sad, sep="")
dots < c(as.name("n"), list(...))
do.call(dcom, dots)
}
g < function() {
dcom < paste("d", samp, sep="")
lambda < a * n
dots < c(as.name("x"), as.name("lambda"))
do.call(dcom, dots)
}
f() * g()
}
integrate(f1,0,2000)$value
# adaptIntegrate(f1,0,2000)$integral
# n < 0:2000
# trapz(n,f1(n))
# area(f1, 0, 2000, limit=10000, eps=1e100)
}
return(result(x) / (1  result(trunc)))
}, "x")
func(200, 0.05, "exp", rate=0.001)
If you could propose something I will be gratefull.
Thanks in advance.
On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
< [hidden email]> wrote:
> Mr ". .",
>
> MASS::area comes to mind but it may be more helpful if you could say what
> you are looking for / why integrate is not appropriate it is for whatever
> you are doing.
>
> Strictly speaking, I suppose there are all sorts of "alternatives" to
> integrate() if you are willing to be really creative and build something
> from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
>
> Michael Weylandt
>
> On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
>>
>> package "caTools"
>> see ?trapz
>>
>>
>> . wrote:
>> >
>> > Hi all,
>> >
>> > is there any alternative to the function integrate?
>> >
>> > Any comments are welcome.
>> >
>> > Thanks in advance.
>> >
>> > ______________________________________________
>> > [hidden email] mailing list
>> > https://stat.ethz.ch/mailman/listinfo/rhelp>> > PLEASE do read the posting guide
>> > http://www.Rproject.org/postingguide.html>> > and provide commented, minimal, selfcontained, reproducible code.
>> >
>>
>> 
>> View this message in context:
>> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html>> Sent from the R help mailing list archive at Nabble.com.
>>
>> ______________________________________________
>> [hidden email] mailing list
>> https://stat.ethz.ch/mailman/listinfo/rhelp>> PLEASE do read the posting guide
>> http://www.Rproject.org/postingguide.html>> and provide commented, minimal, selfcontained, reproducible code.
>
>
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


I'm going to try to put this nicely:
What you provided is not a problem with integrate. Instead, you provided a
rather unintelligible and badlywritten piece of code that (miraculously)
seems to work, though it's not well documented so I have no idea if 1.3e21
is what you want to get.
Let's try this again: per your original request, what is the problem with
integrate?
If instead you feel there's something wrong with your code, might I suggest
you just say that and ask for help, rather than passing the blame onto a
perfectly useful base function.
Oh, and since you asked that I propose something: comment your code.
Michael
On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
> Hi Michael,
>
> This is the problem:
>
> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
> result < function(x) {
> f1 < function(n) {
> f < function() {
> dcom < paste("d", sad, sep="")
> dots < c(as.name("n"), list(...))
> do.call(dcom, dots)
> }
> g < function() {
> dcom < paste("d", samp, sep="")
> lambda < a * n
> dots < c(as.name("x"), as.name("lambda"))
> do.call(dcom, dots)
> }
> f() * g()
> }
> integrate(f1,0,2000)$value
> # adaptIntegrate(f1,0,2000)$integral
>
> # n < 0:2000
> # trapz(n,f1(n))
>
> # area(f1, 0, 2000, limit=10000, eps=1e100)
> }
> return(result(x) / (1  result(trunc)))
> }, "x")
> func(200, 0.05, "exp", rate=0.001)
>
> If you could propose something I will be gratefull.
>
> Thanks in advance.
>
> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
> < [hidden email]> wrote:
> > Mr ". .",
> >
> > MASS::area comes to mind but it may be more helpful if you could say what
> > you are looking for / why integrate is not appropriate it is for whatever
> > you are doing.
> >
> > Strictly speaking, I suppose there are all sorts of "alternatives" to
> > integrate() if you are willing to be really creative and build something
> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
> >
> > Michael Weylandt
> >
> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
> >>
> >> package "caTools"
> >> see ?trapz
> >>
> >>
> >> . wrote:
> >> >
> >> > Hi all,
> >> >
> >> > is there any alternative to the function integrate?
> >> >
> >> > Any comments are welcome.
> >> >
> >> > Thanks in advance.
> >> >
> >> > ______________________________________________
> >> > [hidden email] mailing list
> >> > https://stat.ethz.ch/mailman/listinfo/rhelp> >> > PLEASE do read the posting guide
> >> > http://www.Rproject.org/postingguide.html> >> > and provide commented, minimal, selfcontained, reproducible code.
> >> >
> >>
> >> 
> >> View this message in context:
> >>
> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html> >> Sent from the R help mailing list archive at Nabble.com.
> >>
> >> ______________________________________________
> >> [hidden email] mailing list
> >> https://stat.ethz.ch/mailman/listinfo/rhelp> >> PLEASE do read the posting guide
> >> http://www.Rproject.org/postingguide.html> >> and provide commented, minimal, selfcontained, reproducible code.
> >
> >
>
[[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


So, please excuse me Michael, you are completely sure. I will try
describe I am trying to do, please let me know if I can provide more
info.
The idea is provide to "func" two probability density functions(PDFs)
and obtain another PDF that is a compound of them. In a final analysis
this characterize an abundance distribution for me. The two PDFs are
provided through "f" and "g" and there is some manipulation here
because I need flexibility to easily change this two funcions.
In the code provided, "f" is the Exponential distribution and "g" is
the Poisson distribution. For this case, I have the analytical
solution, below. This way I can check the result. But I am also
considering other combinations of "f" and "g" that have difficult, or
even does not have analitical solution. This is the reason why I am
trying to develop "func".
func2 < function(y, frac, rate, trunc=0, log=FALSE) {
is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
abs(x  round(x)) < tol
if(FALSE %in% sapply(y,is.wholenumber))
print("y must be integer because dpoix is a discrete PDF.")
else {
f < function(y){
b < y*log(frac)
m < log(rate)
n < (y+1)*log(rate+frac)
if(log)b+mn else exp(b+mn)
}
f(y)/(1f(trunc))
}
}
> func2(200,0.05,0.001)
[1] 0.000381062
In theory, the interval of integration is 0 to Inf, but for some tests
I did, go up to 2000 may still provide reasonable results.
Also, as it seems, I am still writing my first functions in R and
suggestions are welcome, please.
Again, appologies for my previous mistake. It was not my intention to
blame about "integrate".
On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
< [hidden email]> wrote:
> I'm going to try to put this nicely:
>
> What you provided is not a problem with integrate. Instead, you provided a
> rather unintelligible and badlywritten piece of code that (miraculously)
> seems to work, though it's not well documented so I have no idea if 1.3e21
> is what you want to get.
>
> Let's try this again: per your original request, what is the problem with
> integrate?
>
> If instead you feel there's something wrong with your code, might I suggest
> you just say that and ask for help, rather than passing the blame onto a
> perfectly useful base function.
>
> Oh, and since you asked that I propose something: comment your code.
>
> Michael
>
> On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
>>
>> Hi Michael,
>>
>> This is the problem:
>>
>> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
>> result < function(x) {
>> f1 < function(n) {
>> f < function() {
>> dcom < paste("d", sad, sep="")
>> dots < c(as.name("n"), list(...))
>> do.call(dcom, dots)
>> }
>> g < function() {
>> dcom < paste("d", samp, sep="")
>> lambda < a * n
>> dots < c(as.name("x"), as.name("lambda"))
>> do.call(dcom, dots)
>> }
>> f() * g()
>> }
>> integrate(f1,0,2000)$value
>> # adaptIntegrate(f1,0,2000)$integral
>>
>> # n < 0:2000
>> # trapz(n,f1(n))
>>
>> # area(f1, 0, 2000, limit=10000, eps=1e100)
>> }
>> return(result(x) / (1  result(trunc)))
>> }, "x")
>> func(200, 0.05, "exp", rate=0.001)
>>
>> If you could propose something I will be gratefull.
>>
>> Thanks in advance.
>>
>> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
>> < [hidden email]> wrote:
>> > Mr ". .",
>> >
>> > MASS::area comes to mind but it may be more helpful if you could say
>> > what
>> > you are looking for / why integrate is not appropriate it is for
>> > whatever
>> > you are doing.
>> >
>> > Strictly speaking, I suppose there are all sorts of "alternatives" to
>> > integrate() if you are willing to be really creative and build something
>> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
>> >
>> > Michael Weylandt
>> >
>> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
>> >>
>> >> package "caTools"
>> >> see ?trapz
>> >>
>> >>
>> >> . wrote:
>> >> >
>> >> > Hi all,
>> >> >
>> >> > is there any alternative to the function integrate?
>> >> >
>> >> > Any comments are welcome.
>> >> >
>> >> > Thanks in advance.
>> >> >
>> >> > ______________________________________________
>> >> > [hidden email] mailing list
>> >> > https://stat.ethz.ch/mailman/listinfo/rhelp>> >> > PLEASE do read the posting guide
>> >> > http://www.Rproject.org/postingguide.html>> >> > and provide commented, minimal, selfcontained, reproducible code.
>> >> >
>> >>
>> >> 
>> >> View this message in context:
>> >>
>> >> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html>> >> Sent from the R help mailing list archive at Nabble.com.
>> >>
>> >> ______________________________________________
>> >> [hidden email] mailing list
>> >> https://stat.ethz.ch/mailman/listinfo/rhelp>> >> PLEASE do read the posting guide
>> >> http://www.Rproject.org/postingguide.html>> >> and provide commented, minimal, selfcontained, reproducible code.
>> >
>> >
>
>
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Leaving aside some other issues that this whole email chain has opened up,
I'd guess that your most immediate problem is that you are trying to
numerically integrate the PMF of a discrete distribution but you are
treating it as a continuous distribution. If you took the time to properly
debug (as you were instructed yesterday) you'd probably find that whenever
you call dpois(x, lambda) for x not an integer you get a warning message.
Specifically, check this out
> integrate(dpois,0,Inf,1)
9.429158e13 with absolute error < 1.7e12
> n = 0:1000; sum(dpois(n,1))
1
I could be entirely off base here, but I'm guessing that many of your
problems derive from this.
On another basis, please, please read this:
http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.htmlor this
http://had.co.nz/stat405/resources/rstyleguide.htmlAnd, perhaps most importantly, don't rely on the black magic of values
moving in and out of functions (lexical scoping). Seriously, just don't do
it.
If you have helper functions that need values, actively pass them: you will
save yourself hours of trouble when (not if) you debug your functions. I'm
looking, for example, at g() in the first big block of code you provided.
Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It makes
everyone happier.
Michael
On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
> So, please excuse me Michael, you are completely sure. I will try
> describe I am trying to do, please let me know if I can provide more
> info.
>
> The idea is provide to "func" two probability density functions(PDFs)
> and obtain another PDF that is a compound of them. In a final analysis
> this characterize an abundance distribution for me. The two PDFs are
> provided through "f" and "g" and there is some manipulation here
> because I need flexibility to easily change this two funcions.
>
> In the code provided, "f" is the Exponential distribution and "g" is
> the Poisson distribution. For this case, I have the analytical
> solution, below. This way I can check the result. But I am also
> considering other combinations of "f" and "g" that have difficult, or
> even does not have analitical solution. This is the reason why I am
> trying to develop "func".
>
> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
> abs(x  round(x)) < tol
> if(FALSE %in% sapply(y,is.wholenumber))
> print("y must be integer because dpoix is a discrete PDF.")
> else {
> f < function(y){
> b < y*log(frac)
> m < log(rate)
> n < (y+1)*log(rate+frac)
> if(log)b+mn else exp(b+mn)
> }
> f(y)/(1f(trunc))
> }
> }
> > func2(200,0.05,0.001)
> [1] 0.000381062
>
> In theory, the interval of integration is 0 to Inf, but for some tests
> I did, go up to 2000 may still provide reasonable results.
>
> Also, as it seems, I am still writing my first functions in R and
> suggestions are welcome, please.
>
> Again, appologies for my previous mistake. It was not my intention to
> blame about "integrate".
>
> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
> < [hidden email]> wrote:
> > I'm going to try to put this nicely:
> >
> > What you provided is not a problem with integrate. Instead, you provided
> a
> > rather unintelligible and badlywritten piece of code that (miraculously)
> > seems to work, though it's not well documented so I have no idea if
> 1.3e21
> > is what you want to get.
> >
> > Let's try this again: per your original request, what is the problem with
> > integrate?
> >
> > If instead you feel there's something wrong with your code, might I
> suggest
> > you just say that and ask for help, rather than passing the blame onto a
> > perfectly useful base function.
> >
> > Oh, and since you asked that I propose something: comment your code.
> >
> > Michael
> >
> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
> >>
> >> Hi Michael,
> >>
> >> This is the problem:
> >>
> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
> >> result < function(x) {
> >> f1 < function(n) {
> >> f < function() {
> >> dcom < paste("d", sad, sep="")
> >> dots < c(as.name("n"), list(...))
> >> do.call(dcom, dots)
> >> }
> >> g < function() {
> >> dcom < paste("d", samp, sep="")
> >> lambda < a * n
> >> dots < c(as.name("x"), as.name("lambda"))
> >> do.call(dcom, dots)
> >> }
> >> f() * g()
> >> }
> >> integrate(f1,0,2000)$value
> >> # adaptIntegrate(f1,0,2000)$integral
> >>
> >> # n < 0:2000
> >> # trapz(n,f1(n))
> >>
> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
> >> }
> >> return(result(x) / (1  result(trunc)))
> >> }, "x")
> >> func(200, 0.05, "exp", rate=0.001)
> >>
> >> If you could propose something I will be gratefull.
> >>
> >> Thanks in advance.
> >>
> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
> >> < [hidden email]> wrote:
> >> > Mr ". .",
> >> >
> >> > MASS::area comes to mind but it may be more helpful if you could say
> >> > what
> >> > you are looking for / why integrate is not appropriate it is for
> >> > whatever
> >> > you are doing.
> >> >
> >> > Strictly speaking, I suppose there are all sorts of "alternatives" to
> >> > integrate() if you are willing to be really creative and build
> something
> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
> >> >
> >> > Michael Weylandt
> >> >
> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
> >> >>
> >> >> package "caTools"
> >> >> see ?trapz
> >> >>
> >> >>
> >> >> . wrote:
> >> >> >
> >> >> > Hi all,
> >> >> >
> >> >> > is there any alternative to the function integrate?
> >> >> >
> >> >> > Any comments are welcome.
> >> >> >
> >> >> > Thanks in advance.
> >> >> >
> >> >> > ______________________________________________
> >> >> > [hidden email] mailing list
> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> > PLEASE do read the posting guide
> >> >> > http://www.Rproject.org/postingguide.html> >> >> > and provide commented, minimal, selfcontained, reproducible code.
> >> >> >
> >> >>
> >> >> 
> >> >> View this message in context:
> >> >>
> >> >>
> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html> >> >> Sent from the R help mailing list archive at Nabble.com.
> >> >>
> >> >> ______________________________________________
> >> >> [hidden email] mailing list
> >> >> https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> PLEASE do read the posting guide
> >> >> http://www.Rproject.org/postingguide.html> >> >> and provide commented, minimal, selfcontained, reproducible code.
> >> >
> >> >
> >
> >
>
[[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Thanks for your reply Michael, it seems I have a lot of things to
learn yet but for sure, your response is being very helpful in this
proccess. I will try to explore every point you said:
A doubt I have is, if I define "func < function(x,y) x + y" how can I
integrate it only in "x"? My solution for this would be to define
"func < function(x) x + y". Is not ok?
Also, with respect to the helper functions I'd created, I am wondering
if you can see a better organization for my code. It is so because
this is the only way I can see. Particularly I do not like how I am
using "results", but I can not think in another form.
Thanks in advance.
On Thu, Sep 1, 2011 at 2:44 PM, R. Michael Weylandt
< [hidden email]> wrote:
> Leaving aside some other issues that this whole email chain has opened up,
>
> I'd guess that your most immediate problem is that you are trying to
> numerically integrate the PMF of a discrete distribution but you are
> treating it as a continuous distribution. If you took the time to properly
> debug (as you were instructed yesterday) you'd probably find that whenever
> you call dpois(x, lambda) for x not an integer you get a warning message.
>
> Specifically, check this out
>
>> integrate(dpois,0,Inf,1)
> 9.429158e13 with absolute error < 1.7e12
>
>> n = 0:1000; sum(dpois(n,1))
> 1
>
> I could be entirely off base here, but I'm guessing that many of your
> problems derive from this.
>
>
>
> On another basis, please, please read this:
> http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.html> or this
> http://had.co.nz/stat405/resources/rstyleguide.html>
> And, perhaps most importantly, don't rely on the black magic of values
> moving in and out of functions (lexical scoping). Seriously, just don't do
> it.
>
> If you have helper functions that need values, actively pass them: you will
> save yourself hours of trouble when (not if) you debug your functions. I'm
> looking, for example, at g() in the first big block of code you provided.
> Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It makes
> everyone happier.
>
> Michael
>
> On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
>>
>> So, please excuse me Michael, you are completely sure. I will try
>> describe I am trying to do, please let me know if I can provide more
>> info.
>>
>> The idea is provide to "func" two probability density functions(PDFs)
>> and obtain another PDF that is a compound of them. In a final analysis
>> this characterize an abundance distribution for me. The two PDFs are
>> provided through "f" and "g" and there is some manipulation here
>> because I need flexibility to easily change this two funcions.
>>
>> In the code provided, "f" is the Exponential distribution and "g" is
>> the Poisson distribution. For this case, I have the analytical
>> solution, below. This way I can check the result. But I am also
>> considering other combinations of "f" and "g" that have difficult, or
>> even does not have analitical solution. This is the reason why I am
>> trying to develop "func".
>>
>> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
>> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
>> abs(x  round(x)) < tol
>> if(FALSE %in% sapply(y,is.wholenumber))
>> print("y must be integer because dpoix is a discrete PDF.")
>> else {
>> f < function(y){
>> b < y*log(frac)
>> m < log(rate)
>> n < (y+1)*log(rate+frac)
>> if(log)b+mn else exp(b+mn)
>> }
>> f(y)/(1f(trunc))
>> }
>> }
>> > func2(200,0.05,0.001)
>> [1] 0.000381062
>>
>> In theory, the interval of integration is 0 to Inf, but for some tests
>> I did, go up to 2000 may still provide reasonable results.
>>
>> Also, as it seems, I am still writing my first functions in R and
>> suggestions are welcome, please.
>>
>> Again, appologies for my previous mistake. It was not my intention to
>> blame about "integrate".
>>
>> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
>> < [hidden email]> wrote:
>> > I'm going to try to put this nicely:
>> >
>> > What you provided is not a problem with integrate. Instead, you provided
>> > a
>> > rather unintelligible and badlywritten piece of code that
>> > (miraculously)
>> > seems to work, though it's not well documented so I have no idea if
>> > 1.3e21
>> > is what you want to get.
>> >
>> > Let's try this again: per your original request, what is the problem
>> > with
>> > integrate?
>> >
>> > If instead you feel there's something wrong with your code, might I
>> > suggest
>> > you just say that and ask for help, rather than passing the blame onto a
>> > perfectly useful base function.
>> >
>> > Oh, and since you asked that I propose something: comment your code.
>> >
>> > Michael
>> >
>> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
>> >>
>> >> Hi Michael,
>> >>
>> >> This is the problem:
>> >>
>> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
>> >> result < function(x) {
>> >> f1 < function(n) {
>> >> f < function() {
>> >> dcom < paste("d", sad, sep="")
>> >> dots < c(as.name("n"), list(...))
>> >> do.call(dcom, dots)
>> >> }
>> >> g < function() {
>> >> dcom < paste("d", samp, sep="")
>> >> lambda < a * n
>> >> dots < c(as.name("x"), as.name("lambda"))
>> >> do.call(dcom, dots)
>> >> }
>> >> f() * g()
>> >> }
>> >> integrate(f1,0,2000)$value
>> >> # adaptIntegrate(f1,0,2000)$integral
>> >>
>> >> # n < 0:2000
>> >> # trapz(n,f1(n))
>> >>
>> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
>> >> }
>> >> return(result(x) / (1  result(trunc)))
>> >> }, "x")
>> >> func(200, 0.05, "exp", rate=0.001)
>> >>
>> >> If you could propose something I will be gratefull.
>> >>
>> >> Thanks in advance.
>> >>
>> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
>> >> < [hidden email]> wrote:
>> >> > Mr ". .",
>> >> >
>> >> > MASS::area comes to mind but it may be more helpful if you could say
>> >> > what
>> >> > you are looking for / why integrate is not appropriate it is for
>> >> > whatever
>> >> > you are doing.
>> >> >
>> >> > Strictly speaking, I suppose there are all sorts of "alternatives" to
>> >> > integrate() if you are willing to be really creative and build
>> >> > something
>> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
>> >> >
>> >> > Michael Weylandt
>> >> >
>> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
>> >> >>
>> >> >> package "caTools"
>> >> >> see ?trapz
>> >> >>
>> >> >>
>> >> >> . wrote:
>> >> >> >
>> >> >> > Hi all,
>> >> >> >
>> >> >> > is there any alternative to the function integrate?
>> >> >> >
>> >> >> > Any comments are welcome.
>> >> >> >
>> >> >> > Thanks in advance.
>> >> >> >
>> >> >> > ______________________________________________
>> >> >> > [hidden email] mailing list
>> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp>> >> >> > PLEASE do read the posting guide
>> >> >> > http://www.Rproject.org/postingguide.html>> >> >> > and provide commented, minimal, selfcontained, reproducible code.
>> >> >> >
>> >> >>
>> >> >> 
>> >> >> View this message in context:
>> >> >>
>> >> >>
>> >> >> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html>> >> >> Sent from the R help mailing list archive at Nabble.com.
>> >> >>
>> >> >> ______________________________________________
>> >> >> [hidden email] mailing list
>> >> >> https://stat.ethz.ch/mailman/listinfo/rhelp>> >> >> PLEASE do read the posting guide
>> >> >> http://www.Rproject.org/postingguide.html>> >> >> and provide commented, minimal, selfcontained, reproducible code.
>> >> >
>> >> >
>> >
>> >
>
>
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Actually, it's very easy to integrate a function of two variables in a
single variable for a given value of the other variable.
Using your example:
MySum < function(x,y) {
ans = x + y
return(ans)
}
Note a things about how I wrote this. One, I broke the function out and used
curly braces to enclose the body of the expression; secondly, I kept the
body of the function at a constant indent level using spaces, not hard tabs;
thirdly, I gave it a meaningful (if somewhat silly) name. (There are so many
things that have names like "func" or "f" in R that you really don't want to
risk overloading something important) Finally, I used the (technically
unnecessary) return() command to say specifically what values my function
will be return. The use of "ans" is a personal preference, but I think it
makes clear what the function is aiming at.
Suppose I want to integrate this over [0,1] with y = 3. This can be coded
R> integrate(MySum, 0, 1, 3)
3.5
If you read the documentation for integrate (? integrate) you'll see that
there is an optional "..." argument that allows further parameters to be
passed to the integrand. Here, this is only the value of y.
Now suppose I want to define a function that integrates over that same unit
interval but takes y as an argument. This can be done as
BadIntegrateMySum < function(y) {
ans = integrate(MySum, 0, 1, y)
return(ans)
}
However, this is a potentially dangerous thing to do because it requires
MySum to just show up inside of BadIntegrateMySum. R is able to try to help
you out, but really it's very dangerous so don't rely on it. Rather, define
MySum inside of the first function as a helper inside of the larger
function:
GoodIntegrateMySum < function(y) {
MySumHelper < function(x,y) {
ans = x + y
return(ans)
}
ans = integrate(MySumHelper, 0, 1, y)
return(ans)
}
Hopefully this is much clearer. There's a slightly contentious stylistic
point here  whether it's ok to use y in the definition of the helper and
in the bigger function  but I think it's ok in this circumstance because
the two instances specifically correspond to each other.
A more general form of this could take in "MySumHelper" as an argument (yes
functions can be passed like that)
# MySum as above
GoodIntegrateUnitInterval < function(xIntegrand, yParameter) {
# Requires xIntegrand to be a function of two variables x,y
# You can actually do this in the code, but for now let's just assume no
user error and that xIntegrand is the right sort of thing.
ans = integrate(xIntegrand, 0, 1, yParameter)
return(ans)
}
R> GoodIntegrateUnitInverval(MySum, 3)
3.5
as before.
There's nothing wrong with using "result" like I've used "ans," but I do
hesitate to see it used as a function rather than a variable. A good rule of
thumb is to check if a variable is already defined as a function name using
the apropos() command.
I don't have time or inclination to rework your whole code right now, but
take a stab at formatting it with consistent+informative variable and
function names, a well reasoned use of scoping, and appropriate use of
integrate() and I'll happily comment on it.
Hope this helps,
Michael Weylandt
On Thu, Sep 1, 2011 at 8:57 PM, . . < [hidden email]> wrote:
> Thanks for your reply Michael, it seems I have a lot of things to
> learn yet but for sure, your response is being very helpful in this
> proccess. I will try to explore every point you said:
>
> A doubt I have is, if I define "func < function(x,y) x + y" how can I
> integrate it only in "x"? My solution for this would be to define
> "func < function(x) x + y". Is not ok?
>
> Also, with respect to the helper functions I'd created, I am wondering
> if you can see a better organization for my code. It is so because
> this is the only way I can see. Particularly I do not like how I am
> using "results", but I can not think in another form.
>
> Thanks in advance.
>
> On Thu, Sep 1, 2011 at 2:44 PM, R. Michael Weylandt
> < [hidden email]> wrote:
> > Leaving aside some other issues that this whole email chain has opened
> up,
> >
> > I'd guess that your most immediate problem is that you are trying to
> > numerically integrate the PMF of a discrete distribution but you are
> > treating it as a continuous distribution. If you took the time to
> properly
> > debug (as you were instructed yesterday) you'd probably find that
> whenever
> > you call dpois(x, lambda) for x not an integer you get a warning message.
> >
> > Specifically, check this out
> >
> >> integrate(dpois,0,Inf,1)
> > 9.429158e13 with absolute error < 1.7e12
> >
> >> n = 0:1000; sum(dpois(n,1))
> > 1
> >
> > I could be entirely off base here, but I'm guessing that many of your
> > problems derive from this.
> >
> >
> >
> > On another basis, please, please read this:
> > http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.html> > or this
> > http://had.co.nz/stat405/resources/rstyleguide.html> >
> > And, perhaps most importantly, don't rely on the black magic of values
> > moving in and out of functions (lexical scoping). Seriously, just don't
> do
> > it.
> >
> > If you have helper functions that need values, actively pass them: you
> will
> > save yourself hours of trouble when (not if) you debug your functions.
> I'm
> > looking, for example, at g() in the first big block of code you provided.
> > Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It
> makes
> > everyone happier.
> >
> > Michael
> >
> > On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
> >>
> >> So, please excuse me Michael, you are completely sure. I will try
> >> describe I am trying to do, please let me know if I can provide more
> >> info.
> >>
> >> The idea is provide to "func" two probability density functions(PDFs)
> >> and obtain another PDF that is a compound of them. In a final analysis
> >> this characterize an abundance distribution for me. The two PDFs are
> >> provided through "f" and "g" and there is some manipulation here
> >> because I need flexibility to easily change this two funcions.
> >>
> >> In the code provided, "f" is the Exponential distribution and "g" is
> >> the Poisson distribution. For this case, I have the analytical
> >> solution, below. This way I can check the result. But I am also
> >> considering other combinations of "f" and "g" that have difficult, or
> >> even does not have analitical solution. This is the reason why I am
> >> trying to develop "func".
> >>
> >> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
> >> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
> >> abs(x  round(x)) < tol
> >> if(FALSE %in% sapply(y,is.wholenumber))
> >> print("y must be integer because dpoix is a discrete PDF.")
> >> else {
> >> f < function(y){
> >> b < y*log(frac)
> >> m < log(rate)
> >> n < (y+1)*log(rate+frac)
> >> if(log)b+mn else exp(b+mn)
> >> }
> >> f(y)/(1f(trunc))
> >> }
> >> }
> >> > func2(200,0.05,0.001)
> >> [1] 0.000381062
> >>
> >> In theory, the interval of integration is 0 to Inf, but for some tests
> >> I did, go up to 2000 may still provide reasonable results.
> >>
> >> Also, as it seems, I am still writing my first functions in R and
> >> suggestions are welcome, please.
> >>
> >> Again, appologies for my previous mistake. It was not my intention to
> >> blame about "integrate".
> >>
> >> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
> >> < [hidden email]> wrote:
> >> > I'm going to try to put this nicely:
> >> >
> >> > What you provided is not a problem with integrate. Instead, you
> provided
> >> > a
> >> > rather unintelligible and badlywritten piece of code that
> >> > (miraculously)
> >> > seems to work, though it's not well documented so I have no idea if
> >> > 1.3e21
> >> > is what you want to get.
> >> >
> >> > Let's try this again: per your original request, what is the problem
> >> > with
> >> > integrate?
> >> >
> >> > If instead you feel there's something wrong with your code, might I
> >> > suggest
> >> > you just say that and ask for help, rather than passing the blame onto
> a
> >> > perfectly useful base function.
> >> >
> >> > Oh, and since you asked that I propose something: comment your code.
> >> >
> >> > Michael
> >> >
> >> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
> >> >>
> >> >> Hi Michael,
> >> >>
> >> >> This is the problem:
> >> >>
> >> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
> >> >> result < function(x) {
> >> >> f1 < function(n) {
> >> >> f < function() {
> >> >> dcom < paste("d", sad, sep="")
> >> >> dots < c(as.name("n"), list(...))
> >> >> do.call(dcom, dots)
> >> >> }
> >> >> g < function() {
> >> >> dcom < paste("d", samp, sep="")
> >> >> lambda < a * n
> >> >> dots < c(as.name("x"), as.name("lambda"))
> >> >> do.call(dcom, dots)
> >> >> }
> >> >> f() * g()
> >> >> }
> >> >> integrate(f1,0,2000)$value
> >> >> # adaptIntegrate(f1,0,2000)$integral
> >> >>
> >> >> # n < 0:2000
> >> >> # trapz(n,f1(n))
> >> >>
> >> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
> >> >> }
> >> >> return(result(x) / (1  result(trunc)))
> >> >> }, "x")
> >> >> func(200, 0.05, "exp", rate=0.001)
> >> >>
> >> >> If you could propose something I will be gratefull.
> >> >>
> >> >> Thanks in advance.
> >> >>
> >> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
> >> >> < [hidden email]> wrote:
> >> >> > Mr ". .",
> >> >> >
> >> >> > MASS::area comes to mind but it may be more helpful if you could
> say
> >> >> > what
> >> >> > you are looking for / why integrate is not appropriate it is for
> >> >> > whatever
> >> >> > you are doing.
> >> >> >
> >> >> > Strictly speaking, I suppose there are all sorts of "alternatives"
> to
> >> >> > integrate() if you are willing to be really creative and build
> >> >> > something
> >> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
> >> >> >
> >> >> > Michael Weylandt
> >> >> >
> >> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
> >> >> >>
> >> >> >> package "caTools"
> >> >> >> see ?trapz
> >> >> >>
> >> >> >>
> >> >> >> . wrote:
> >> >> >> >
> >> >> >> > Hi all,
> >> >> >> >
> >> >> >> > is there any alternative to the function integrate?
> >> >> >> >
> >> >> >> > Any comments are welcome.
> >> >> >> >
> >> >> >> > Thanks in advance.
> >> >> >> >
> >> >> >> > ______________________________________________
> >> >> >> > [hidden email] mailing list
> >> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> >> > PLEASE do read the posting guide
> >> >> >> > http://www.Rproject.org/postingguide.html> >> >> >> > and provide commented, minimal, selfcontained, reproducible
> code.
> >> >> >> >
> >> >> >>
> >> >> >> 
> >> >> >> View this message in context:
> >> >> >>
> >> >> >>
> >> >> >>
> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html> >> >> >> Sent from the R help mailing list archive at Nabble.com.
> >> >> >>
> >> >> >> ______________________________________________
> >> >> >> [hidden email] mailing list
> >> >> >> https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> >> PLEASE do read the posting guide
> >> >> >> http://www.Rproject.org/postingguide.html> >> >> >> and provide commented, minimal, selfcontained, reproducible code.
> >> >> >
> >> >> >
> >> >
> >> >
> >
> >
>
[[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Hi, continuing the improvements...
I've prepared a new code:
ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
dots < list(...)
Compound < function(individuals, frac, n.species, sad, samp, dots) {
print(c("Size:", length(individuals), "Compound individuals:",
individuals, "End."))
RegDist < function(n.species, sad, dots) { # "RegDist" may be
Exponential, Gamma, etc.
dcom < paste("d", as.name(sad), sep="")
dots < as.list(c(n.species, dots))
ans < do.call(dcom, dots)
return(ans)
}
SampDist < function(individuals, frac, n.species, samp) { #
"SampDist" may be Poisson or Negative Binomial
dcom < paste("d", samp, sep="")
lambda < frac * n.species
dots < as.list(c(individuals, lambda))
ans < do.call(dcom, dots)
return(ans)
}
ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
n.species, samp)
return(ans)
}
IntegrateScheme < function(Compound, individuals, frac, sad, samp, dots) {
print(c("Size:", length(individuals), "Integrate individuals:",
individuals))
ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
dots)$value
return(ans)
}
ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
return(ans)
}
ddae(2, 0.05, "exp")
Now I can't understand what happen to "individuals", why is it
changing in value and size? I've tried to "traceback()" and "debug()",
but I was not smart enough to understand what is going on.
Could you, please, give some more help?
Thanks in advance.
On Thu, Sep 1, 2011 at 10:41 PM, R. Michael Weylandt
< [hidden email]> wrote:
> Actually, it's very easy to integrate a function of two variables in a
> single variable for a given value of the other variable.
>
> Using your example:
>
> MySum < function(x,y) {
> ans = x + y
> return(ans)
> }
>
> Note a things about how I wrote this. One, I broke the function out and used
> curly braces to enclose the body of the expression; secondly, I kept the
> body of the function at a constant indent level using spaces, not hard tabs;
> thirdly, I gave it a meaningful (if somewhat silly) name. (There are so many
> things that have names like "func" or "f" in R that you really don't want to
> risk overloading something important) Finally, I used the (technically
> unnecessary) return() command to say specifically what values my function
> will be return. The use of "ans" is a personal preference, but I think it
> makes clear what the function is aiming at.
>
> Suppose I want to integrate this over [0,1] with y = 3. This can be coded
>
> R> integrate(MySum, 0, 1, 3)
> 3.5
>
> If you read the documentation for integrate (? integrate) you'll see that
> there is an optional "..." argument that allows further parameters to be
> passed to the integrand. Here, this is only the value of y.
>
> Now suppose I want to define a function that integrates over that same unit
> interval but takes y as an argument. This can be done as
>
> BadIntegrateMySum < function(y) {
> ans = integrate(MySum, 0, 1, y)
> return(ans)
> }
>
> However, this is a potentially dangerous thing to do because it requires
> MySum to just show up inside of BadIntegrateMySum. R is able to try to help
> you out, but really it's very dangerous so don't rely on it. Rather, define
> MySum inside of the first function as a helper inside of the larger
> function:
>
> GoodIntegrateMySum < function(y) {
>
> MySumHelper < function(x,y) {
> ans = x + y
> return(ans)
> }
>
> ans = integrate(MySumHelper, 0, 1, y)
> return(ans)
> }
>
> Hopefully this is much clearer. There's a slightly contentious stylistic
> point here  whether it's ok to use y in the definition of the helper and
> in the bigger function  but I think it's ok in this circumstance because
> the two instances specifically correspond to each other.
>
> A more general form of this could take in "MySumHelper" as an argument (yes
> functions can be passed like that)
>
> # MySum as above
>
> GoodIntegrateUnitInterval < function(xIntegrand, yParameter) {
> # Requires xIntegrand to be a function of two variables x,y
> # You can actually do this in the code, but for now let's just assume no
> user error and that xIntegrand is the right sort of thing.
> ans = integrate(xIntegrand, 0, 1, yParameter)
> return(ans)
> }
>
> R> GoodIntegrateUnitInverval(MySum, 3)
> 3.5
>
> as before.
>
> There's nothing wrong with using "result" like I've used "ans," but I do
> hesitate to see it used as a function rather than a variable. A good rule of
> thumb is to check if a variable is already defined as a function name using
> the apropos() command.
>
> I don't have time or inclination to rework your whole code right now, but
> take a stab at formatting it with consistent+informative variable and
> function names, a well reasoned use of scoping, and appropriate use of
> integrate() and I'll happily comment on it.
>
> Hope this helps,
>
> Michael Weylandt
>
> On Thu, Sep 1, 2011 at 8:57 PM, . . < [hidden email]> wrote:
>>
>> Thanks for your reply Michael, it seems I have a lot of things to
>> learn yet but for sure, your response is being very helpful in this
>> proccess. I will try to explore every point you said:
>>
>> A doubt I have is, if I define "func < function(x,y) x + y" how can I
>> integrate it only in "x"? My solution for this would be to define
>> "func < function(x) x + y". Is not ok?
>>
>> Also, with respect to the helper functions I'd created, I am wondering
>> if you can see a better organization for my code. It is so because
>> this is the only way I can see. Particularly I do not like how I am
>> using "results", but I can not think in another form.
>>
>> Thanks in advance.
>>
>> On Thu, Sep 1, 2011 at 2:44 PM, R. Michael Weylandt
>> < [hidden email]> wrote:
>> > Leaving aside some other issues that this whole email chain has opened
>> > up,
>> >
>> > I'd guess that your most immediate problem is that you are trying to
>> > numerically integrate the PMF of a discrete distribution but you are
>> > treating it as a continuous distribution. If you took the time to
>> > properly
>> > debug (as you were instructed yesterday) you'd probably find that
>> > whenever
>> > you call dpois(x, lambda) for x not an integer you get a warning
>> > message.
>> >
>> > Specifically, check this out
>> >
>> >> integrate(dpois,0,Inf,1)
>> > 9.429158e13 with absolute error < 1.7e12
>> >
>> >> n = 0:1000; sum(dpois(n,1))
>> > 1
>> >
>> > I could be entirely off base here, but I'm guessing that many of your
>> > problems derive from this.
>> >
>> >
>> >
>> > On another basis, please, please read this:
>> > http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.html>> > or this
>> > http://had.co.nz/stat405/resources/rstyleguide.html>> >
>> > And, perhaps most importantly, don't rely on the black magic of values
>> > moving in and out of functions (lexical scoping). Seriously, just don't
>> > do
>> > it.
>> >
>> > If you have helper functions that need values, actively pass them: you
>> > will
>> > save yourself hours of trouble when (not if) you debug your functions.
>> > I'm
>> > looking, for example, at g() in the first big block of code you
>> > provided.
>> > Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It
>> > makes
>> > everyone happier.
>> >
>> > Michael
>> >
>> > On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
>> >>
>> >> So, please excuse me Michael, you are completely sure. I will try
>> >> describe I am trying to do, please let me know if I can provide more
>> >> info.
>> >>
>> >> The idea is provide to "func" two probability density functions(PDFs)
>> >> and obtain another PDF that is a compound of them. In a final analysis
>> >> this characterize an abundance distribution for me. The two PDFs are
>> >> provided through "f" and "g" and there is some manipulation here
>> >> because I need flexibility to easily change this two funcions.
>> >>
>> >> In the code provided, "f" is the Exponential distribution and "g" is
>> >> the Poisson distribution. For this case, I have the analytical
>> >> solution, below. This way I can check the result. But I am also
>> >> considering other combinations of "f" and "g" that have difficult, or
>> >> even does not have analitical solution. This is the reason why I am
>> >> trying to develop "func".
>> >>
>> >> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
>> >> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
>> >> abs(x  round(x)) < tol
>> >> if(FALSE %in% sapply(y,is.wholenumber))
>> >> print("y must be integer because dpoix is a discrete PDF.")
>> >> else {
>> >> f < function(y){
>> >> b < y*log(frac)
>> >> m < log(rate)
>> >> n < (y+1)*log(rate+frac)
>> >> if(log)b+mn else exp(b+mn)
>> >> }
>> >> f(y)/(1f(trunc))
>> >> }
>> >> }
>> >> > func2(200,0.05,0.001)
>> >> [1] 0.000381062
>> >>
>> >> In theory, the interval of integration is 0 to Inf, but for some tests
>> >> I did, go up to 2000 may still provide reasonable results.
>> >>
>> >> Also, as it seems, I am still writing my first functions in R and
>> >> suggestions are welcome, please.
>> >>
>> >> Again, appologies for my previous mistake. It was not my intention to
>> >> blame about "integrate".
>> >>
>> >> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
>> >> < [hidden email]> wrote:
>> >> > I'm going to try to put this nicely:
>> >> >
>> >> > What you provided is not a problem with integrate. Instead, you
>> >> > provided
>> >> > a
>> >> > rather unintelligible and badlywritten piece of code that
>> >> > (miraculously)
>> >> > seems to work, though it's not well documented so I have no idea if
>> >> > 1.3e21
>> >> > is what you want to get.
>> >> >
>> >> > Let's try this again: per your original request, what is the problem
>> >> > with
>> >> > integrate?
>> >> >
>> >> > If instead you feel there's something wrong with your code, might I
>> >> > suggest
>> >> > you just say that and ask for help, rather than passing the blame
>> >> > onto a
>> >> > perfectly useful base function.
>> >> >
>> >> > Oh, and since you asked that I propose something: comment your code.
>> >> >
>> >> > Michael
>> >> >
>> >> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
>> >> >>
>> >> >> Hi Michael,
>> >> >>
>> >> >> This is the problem:
>> >> >>
>> >> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
>> >> >> result < function(x) {
>> >> >> f1 < function(n) {
>> >> >> f < function() {
>> >> >> dcom < paste("d", sad, sep="")
>> >> >> dots < c(as.name("n"), list(...))
>> >> >> do.call(dcom, dots)
>> >> >> }
>> >> >> g < function() {
>> >> >> dcom < paste("d", samp, sep="")
>> >> >> lambda < a * n
>> >> >> dots < c(as.name("x"), as.name("lambda"))
>> >> >> do.call(dcom, dots)
>> >> >> }
>> >> >> f() * g()
>> >> >> }
>> >> >> integrate(f1,0,2000)$value
>> >> >> # adaptIntegrate(f1,0,2000)$integral
>> >> >>
>> >> >> # n < 0:2000
>> >> >> # trapz(n,f1(n))
>> >> >>
>> >> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
>> >> >> }
>> >> >> return(result(x) / (1  result(trunc)))
>> >> >> }, "x")
>> >> >> func(200, 0.05, "exp", rate=0.001)
>> >> >>
>> >> >> If you could propose something I will be gratefull.
>> >> >>
>> >> >> Thanks in advance.
>> >> >>
>> >> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
>> >> >> < [hidden email]> wrote:
>> >> >> > Mr ". .",
>> >> >> >
>> >> >> > MASS::area comes to mind but it may be more helpful if you could
>> >> >> > say
>> >> >> > what
>> >> >> > you are looking for / why integrate is not appropriate it is for
>> >> >> > whatever
>> >> >> > you are doing.
>> >> >> >
>> >> >> > Strictly speaking, I suppose there are all sorts of "alternatives"
>> >> >> > to
>> >> >> > integrate() if you are willing to be really creative and build
>> >> >> > something
>> >> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
>> >> >> >
>> >> >> > Michael Weylandt
>> >> >> >
>> >> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
>> >> >> >>
>> >> >> >> package "caTools"
>> >> >> >> see ?trapz
>> >> >> >>
>> >> >> >>
>> >> >> >> . wrote:
>> >> >> >> >
>> >> >> >> > Hi all,
>> >> >> >> >
>> >> >> >> > is there any alternative to the function integrate?
>> >> >> >> >
>> >> >> >> > Any comments are welcome.
>> >> >> >> >
>> >> >> >> > Thanks in advance.
>> >> >> >> >
>> >> >> >> > ______________________________________________
>> >> >> >> > [hidden email] mailing list
>> >> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp>> >> >> >> > PLEASE do read the posting guide
>> >> >> >> > http://www.Rproject.org/postingguide.html>> >> >> >> > and provide commented, minimal, selfcontained, reproducible
>> >> >> >> > code.
>> >> >> >> >
>> >> >> >>
>> >> >> >> 
>> >> >> >> View this message in context:
>> >> >> >>
>> >> >> >>
>> >> >> >>
>> >> >> >> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html>> >> >> >> Sent from the R help mailing list archive at Nabble.com.
>> >> >> >>
>> >> >> >> ______________________________________________
>> >> >> >> [hidden email] mailing list
>> >> >> >> https://stat.ethz.ch/mailman/listinfo/rhelp>> >> >> >> PLEASE do read the posting guide
>> >> >> >> http://www.Rproject.org/postingguide.html>> >> >> >> and provide commented, minimal, selfcontained, reproducible
>> >> >> >> code.
>> >> >> >
>> >> >> >
>> >> >
>> >> >
>> >
>> >
>
>
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


Sorry about the indentation, it seems I'm doing some mistake when sending
the email. I've tried to indent here like the Google's style, but it
becomes a garbage in the email.
On Mon, Sep 5, 2011 at 11:27 AM, . . < [hidden email]> wrote:
> Hi, continuing the improvements...
>
> I've prepared a new code:
>
> ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
> dots < list(...)
> Compound < function(individuals, frac, n.species, sad, samp, dots) {
> print(c("Size:", length(individuals), "Compound individuals:",
> individuals, "End."))
> RegDist < function(n.species, sad, dots) { # "RegDist" may be
> Exponential, Gamma, etc.
> dcom < paste("d", as.name(sad), sep="")
> dots < as.list(c(n.species, dots))
> ans < do.call(dcom, dots)
> return(ans)
> }
> SampDist < function(individuals, frac, n.species, samp) { #
> "SampDist" may be Poisson or Negative Binomial
> dcom < paste("d", samp, sep="")
> lambda < frac * n.species
> dots < as.list(c(individuals, lambda))
> ans < do.call(dcom, dots)
> return(ans)
> }
> ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
> n.species, samp)
> return(ans)
> }
> IntegrateScheme < function(Compound, individuals, frac, sad, samp, dots)
{
> print(c("Size:", length(individuals), "Integrate individuals:",
> individuals))
> ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
> dots)$value
> return(ans)
> }
> ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
> return(ans)
> }
>
> ddae(2, 0.05, "exp")
>
> Now I can't understand what happen to "individuals", why is it
> changing in value and size? I've tried to "traceback()" and "debug()",
> but I was not smart enough to understand what is going on.
>
> Could you, please, give some more help?
>
> Thanks in advance.
>
> On Thu, Sep 1, 2011 at 10:41 PM, R. Michael Weylandt
> < [hidden email]> wrote:
>> Actually, it's very easy to integrate a function of two variables in a
>> single variable for a given value of the other variable.
>>
>> Using your example:
>>
>> MySum < function(x,y) {
>> ans = x + y
>> return(ans)
>> }
>>
>> Note a things about how I wrote this. One, I broke the function out and
used
>> curly braces to enclose the body of the expression; secondly, I kept the
>> body of the function at a constant indent level using spaces, not hard
tabs;
>> thirdly, I gave it a meaningful (if somewhat silly) name. (There are so
many
>> things that have names like "func" or "f" in R that you really don't want
to
>> risk overloading something important) Finally, I used the (technically
>> unnecessary) return() command to say specifically what values my function
>> will be return. The use of "ans" is a personal preference, but I think it
>> makes clear what the function is aiming at.
>>
>> Suppose I want to integrate this over [0,1] with y = 3. This can be coded
>>
>> R> integrate(MySum, 0, 1, 3)
>> 3.5
>>
>> If you read the documentation for integrate (? integrate) you'll see that
>> there is an optional "..." argument that allows further parameters to be
>> passed to the integrand. Here, this is only the value of y.
>>
>> Now suppose I want to define a function that integrates over that same
unit
>> interval but takes y as an argument. This can be done as
>>
>> BadIntegrateMySum < function(y) {
>> ans = integrate(MySum, 0, 1, y)
>> return(ans)
>> }
>>
>> However, this is a potentially dangerous thing to do because it requires
>> MySum to just show up inside of BadIntegrateMySum. R is able to try to
help
>> you out, but really it's very dangerous so don't rely on it. Rather,
define
>> MySum inside of the first function as a helper inside of the larger
>> function:
>>
>> GoodIntegrateMySum < function(y) {
>>
>> MySumHelper < function(x,y) {
>> ans = x + y
>> return(ans)
>> }
>>
>> ans = integrate(MySumHelper, 0, 1, y)
>> return(ans)
>> }
>>
>> Hopefully this is much clearer. There's a slightly contentious stylistic
>> point here  whether it's ok to use y in the definition of the helper
and
>> in the bigger function  but I think it's ok in this circumstance
because
>> the two instances specifically correspond to each other.
>>
>> A more general form of this could take in "MySumHelper" as an argument
(yes
>> functions can be passed like that)
>>
>> # MySum as above
>>
>> GoodIntegrateUnitInterval < function(xIntegrand, yParameter) {
>> # Requires xIntegrand to be a function of two variables x,y
>> # You can actually do this in the code, but for now let's just assume
no
>> user error and that xIntegrand is the right sort of thing.
>> ans = integrate(xIntegrand, 0, 1, yParameter)
>> return(ans)
>> }
>>
>> R> GoodIntegrateUnitInverval(MySum, 3)
>> 3.5
>>
>> as before.
>>
>> There's nothing wrong with using "result" like I've used "ans," but I do
>> hesitate to see it used as a function rather than a variable. A good rule
of
>> thumb is to check if a variable is already defined as a function name
using
>> the apropos() command.
>>
>> I don't have time or inclination to rework your whole code right now, but
>> take a stab at formatting it with consistent+informative variable and
>> function names, a well reasoned use of scoping, and appropriate use of
>> integrate() and I'll happily comment on it.
>>
>> Hope this helps,
>>
>> Michael Weylandt
>>
>> On Thu, Sep 1, 2011 at 8:57 PM, . . < [hidden email]> wrote:
>>>
>>> Thanks for your reply Michael, it seems I have a lot of things to
>>> learn yet but for sure, your response is being very helpful in this
>>> proccess. I will try to explore every point you said:
>>>
>>> A doubt I have is, if I define "func < function(x,y) x + y" how can I
>>> integrate it only in "x"? My solution for this would be to define
>>> "func < function(x) x + y". Is not ok?
>>>
>>> Also, with respect to the helper functions I'd created, I am wondering
>>> if you can see a better organization for my code. It is so because
>>> this is the only way I can see. Particularly I do not like how I am
>>> using "results", but I can not think in another form.
>>>
>>> Thanks in advance.
>>>
>>> On Thu, Sep 1, 2011 at 2:44 PM, R. Michael Weylandt
>>> < [hidden email]> wrote:
>>> > Leaving aside some other issues that this whole email chain has opened
>>> > up,
>>> >
>>> > I'd guess that your most immediate problem is that you are trying to
>>> > numerically integrate the PMF of a discrete distribution but you are
>>> > treating it as a continuous distribution. If you took the time to
>>> > properly
>>> > debug (as you were instructed yesterday) you'd probably find that
>>> > whenever
>>> > you call dpois(x, lambda) for x not an integer you get a warning
>>> > message.
>>> >
>>> > Specifically, check this out
>>> >
>>> >> integrate(dpois,0,Inf,1)
>>> > 9.429158e13 with absolute error < 1.7e12
>>> >
>>> >> n = 0:1000; sum(dpois(n,1))
>>> > 1
>>> >
>>> > I could be entirely off base here, but I'm guessing that many of your
>>> > problems derive from this.
>>> >
>>> >
>>> >
>>> > On another basis, please, please read this:
>>> > http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.html>>> > or this
>>> > http://had.co.nz/stat405/resources/rstyleguide.html>>> >
>>> > And, perhaps most importantly, don't rely on the black magic of values
>>> > moving in and out of functions (lexical scoping). Seriously, just
don't
>>> > do
>>> > it.
>>> >
>>> > If you have helper functions that need values, actively pass them: you
>>> > will
>>> > save yourself hours of trouble when (not if) you debug your functions.
>>> > I'm
>>> > looking, for example, at g() in the first big block of code you
>>> > provided.
>>> > Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It
>>> > makes
>>> > everyone happier.
>>> >
>>> > Michael
>>> >
>>> > On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
>>> >>
>>> >> So, please excuse me Michael, you are completely sure. I will try
>>> >> describe I am trying to do, please let me know if I can provide more
>>> >> info.
>>> >>
>>> >> The idea is provide to "func" two probability density functions(PDFs)
>>> >> and obtain another PDF that is a compound of them. In a final
analysis
>>> >> this characterize an abundance distribution for me. The two PDFs are
>>> >> provided through "f" and "g" and there is some manipulation here
>>> >> because I need flexibility to easily change this two funcions.
>>> >>
>>> >> In the code provided, "f" is the Exponential distribution and "g" is
>>> >> the Poisson distribution. For this case, I have the analytical
>>> >> solution, below. This way I can check the result. But I am also
>>> >> considering other combinations of "f" and "g" that have difficult,
or
>>> >> even does not have analitical solution. This is the reason why I am
>>> >> trying to develop "func".
>>> >>
>>> >> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
>>> >> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
>>> >> abs(x  round(x)) < tol
>>> >> if(FALSE %in% sapply(y,is.wholenumber))
>>> >> print("y must be integer because dpoix is a discrete PDF.")
>>> >> else {
>>> >> f < function(y){
>>> >> b < y*log(frac)
>>> >> m < log(rate)
>>> >> n < (y+1)*log(rate+frac)
>>> >> if(log)b+mn else exp(b+mn)
>>> >> }
>>> >> f(y)/(1f(trunc))
>>> >> }
>>> >> }
>>> >> > func2(200,0.05,0.001)
>>> >> [1] 0.000381062
>>> >>
>>> >> In theory, the interval of integration is 0 to Inf, but for some
tests
>>> >> I did, go up to 2000 may still provide reasonable results.
>>> >>
>>> >> Also, as it seems, I am still writing my first functions in R and
>>> >> suggestions are welcome, please.
>>> >>
>>> >> Again, appologies for my previous mistake. It was not my intention to
>>> >> blame about "integrate".
>>> >>
>>> >> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
>>> >> < [hidden email]> wrote:
>>> >> > I'm going to try to put this nicely:
>>> >> >
>>> >> > What you provided is not a problem with integrate. Instead, you
>>> >> > provided
>>> >> > a
>>> >> > rather unintelligible and badlywritten piece of code that
>>> >> > (miraculously)
>>> >> > seems to work, though it's not well documented so I have no idea if
>>> >> > 1.3e21
>>> >> > is what you want to get.
>>> >> >
>>> >> > Let's try this again: per your original request, what is the
problem
>>> >> > with
>>> >> > integrate?
>>> >> >
>>> >> > If instead you feel there's something wrong with your code, might I
>>> >> > suggest
>>> >> > you just say that and ask for help, rather than passing the blame
>>> >> > onto a
>>> >> > perfectly useful base function.
>>> >> >
>>> >> > Oh, and since you asked that I propose something: comment your
code.
>>> >> >
>>> >> > Michael
>>> >> >
>>> >> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
>>> >> >>
>>> >> >> Hi Michael,
>>> >> >>
>>> >> >> This is the problem:
>>> >> >>
>>> >> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
>>> >> >> result < function(x) {
>>> >> >> f1 < function(n) {
>>> >> >> f < function() {
>>> >> >> dcom < paste("d", sad, sep="")
>>> >> >> dots < c(as.name("n"), list(...))
>>> >> >> do.call(dcom, dots)
>>> >> >> }
>>> >> >> g < function() {
>>> >> >> dcom < paste("d", samp, sep="")
>>> >> >> lambda < a * n
>>> >> >> dots < c(as.name("x"), as.name("lambda"))
>>> >> >> do.call(dcom, dots)
>>> >> >> }
>>> >> >> f() * g()
>>> >> >> }
>>> >> >> integrate(f1,0,2000)$value
>>> >> >> # adaptIntegrate(f1,0,2000)$integral
>>> >> >>
>>> >> >> # n < 0:2000
>>> >> >> # trapz(n,f1(n))
>>> >> >>
>>> >> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
>>> >> >> }
>>> >> >> return(result(x) / (1  result(trunc)))
>>> >> >> }, "x")
>>> >> >> func(200, 0.05, "exp", rate=0.001)
>>> >> >>
>>> >> >> If you could propose something I will be gratefull.
>>> >> >>
>>> >> >> Thanks in advance.
>>> >> >>
>>> >> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
>>> >> >> < [hidden email]> wrote:
>>> >> >> > Mr ". .",
>>> >> >> >
>>> >> >> > MASS::area comes to mind but it may be more helpful if you could
>>> >> >> > say
>>> >> >> > what
>>> >> >> > you are looking for / why integrate is not appropriate it is for
>>> >> >> > whatever
>>> >> >> > you are doing.
>>> >> >> >
>>> >> >> > Strictly speaking, I suppose there are all sorts of
"alternatives"
>>> >> >> > to
>>> >> >> > integrate() if you are willing to be really creative and build
>>> >> >> > something
>>> >> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
>>> >> >> >
>>> >> >> > Michael Weylandt
>>> >> >> >
>>> >> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]> wrote:
>>> >> >> >>
>>> >> >> >> package "caTools"
>>> >> >> >> see ?trapz
>>> >> >> >>
>>> >> >> >>
>>> >> >> >> . wrote:
>>> >> >> >> >
>>> >> >> >> > Hi all,
>>> >> >> >> >
>>> >> >> >> > is there any alternative to the function integrate?
>>> >> >> >> >
>>> >> >> >> > Any comments are welcome.
>>> >> >> >> >
>>> >> >> >> > Thanks in advance.
>>> >> >> >> >
>>> >> >> >> > ______________________________________________
>>> >> >> >> > [hidden email] mailing list
>>> >> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp>>> >> >> >> > PLEASE do read the posting guide
>>> >> >> >> > http://www.Rproject.org/postingguide.html>>> >> >> >> > and provide commented, minimal, selfcontained, reproducible
>>> >> >> >> > code.
>>> >> >> >> >
>>> >> >> >>
>>> >> >> >> 
>>> >> >> >> View this message in context:
>>> >> >> >>
>>> >> >> >>
>>> >> >> >>
>>> >> >> >>
http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html [[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


I'm not sure what your worry about "individuals" is, but running the code as
given above hits another more fundamental problem: your use of the "..."
argument. Since integrate passes a vector of arguments**, your code
interprets most of those as "..." arguments and tries to pass them along to
dDIST. Specifically here you wind up passing a whole set of values to
dpois() that get interpreted as extra parameters  hence the error that it
throws.
The "..." argument can be a little tricky to work with: I'd suggest you
either avoid it for now or, if you really need it, look at some of the
functions that use it in a way similar to what you think it might be
necessary for. Also, take a quick look over
As far as your question about individuals, send working code and I'll look
at it.
Michael
PS  Also, take a look at replacing print(c("A","B")) with cat("A","B") 
a little cleaner.
** To get a feel with the fact that integrate requires vectorized functions
look at this:
f < function(x){print(x); return(x)}
integrate(f, 0, 1)
If you want, you can use Vectorize() to vectorize a function though I think
that's going to cause you some issues until you figure out how to work with
the dots.
On Mon, Sep 5, 2011 at 9:27 AM, . . < [hidden email]> wrote:
> Hi, continuing the improvements...
>
> I've prepared a new code:
>
> ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
> dots < list(...)
> Compound < function(individuals, frac, n.species, sad, samp, dots) {
> print(c("Size:", length(individuals), "Compound individuals:",
> individuals, "End."))
> RegDist < function(n.species, sad, dots) { # "RegDist" may be
> Exponential, Gamma, etc.
> dcom < paste("d", as.name(sad), sep="")
> dots < as.list(c(n.species, dots))
> ans < do.call(dcom, dots)
> return(ans)
> }
> SampDist < function(individuals, frac, n.species, samp) { #
> "SampDist" may be Poisson or Negative Binomial
> dcom < paste("d", samp, sep="")
> lambda < frac * n.species
> dots < as.list(c(individuals, lambda))
> ans < do.call(dcom, dots)
> return(ans)
> }
> ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
> n.species, samp)
> return(ans)
> }
> IntegrateScheme < function(Compound, individuals, frac, sad, samp, dots)
> {
> print(c("Size:", length(individuals), "Integrate individuals:",
> individuals))
> ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
> dots)$value
> return(ans)
> }
> ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
> return(ans)
> }
>
> ddae(2, 0.05, "exp")
>
> Now I can't understand what happen to "individuals", why is it
> changing in value and size? I've tried to "traceback()" and "debug()",
> but I was not smart enough to understand what is going on.
>
> Could you, please, give some more help?
>
> Thanks in advance.
>
> On Thu, Sep 1, 2011 at 10:41 PM, R. Michael Weylandt
> < [hidden email]> wrote:
> > Actually, it's very easy to integrate a function of two variables in a
> > single variable for a given value of the other variable.
> >
> > Using your example:
> >
> > MySum < function(x,y) {
> > ans = x + y
> > return(ans)
> > }
> >
> > Note a things about how I wrote this. One, I broke the function out and
> used
> > curly braces to enclose the body of the expression; secondly, I kept the
> > body of the function at a constant indent level using spaces, not hard
> tabs;
> > thirdly, I gave it a meaningful (if somewhat silly) name. (There are so
> many
> > things that have names like "func" or "f" in R that you really don't want
> to
> > risk overloading something important) Finally, I used the (technically
> > unnecessary) return() command to say specifically what values my function
> > will be return. The use of "ans" is a personal preference, but I think it
> > makes clear what the function is aiming at.
> >
> > Suppose I want to integrate this over [0,1] with y = 3. This can be coded
> >
> > R> integrate(MySum, 0, 1, 3)
> > 3.5
> >
> > If you read the documentation for integrate (? integrate) you'll see that
> > there is an optional "..." argument that allows further parameters to be
> > passed to the integrand. Here, this is only the value of y.
> >
> > Now suppose I want to define a function that integrates over that same
> unit
> > interval but takes y as an argument. This can be done as
> >
> > BadIntegrateMySum < function(y) {
> > ans = integrate(MySum, 0, 1, y)
> > return(ans)
> > }
> >
> > However, this is a potentially dangerous thing to do because it requires
> > MySum to just show up inside of BadIntegrateMySum. R is able to try to
> help
> > you out, but really it's very dangerous so don't rely on it. Rather,
> define
> > MySum inside of the first function as a helper inside of the larger
> > function:
> >
> > GoodIntegrateMySum < function(y) {
> >
> > MySumHelper < function(x,y) {
> > ans = x + y
> > return(ans)
> > }
> >
> > ans = integrate(MySumHelper, 0, 1, y)
> > return(ans)
> > }
> >
> > Hopefully this is much clearer. There's a slightly contentious stylistic
> > point here  whether it's ok to use y in the definition of the helper
> and
> > in the bigger function  but I think it's ok in this circumstance
> because
> > the two instances specifically correspond to each other.
> >
> > A more general form of this could take in "MySumHelper" as an argument
> (yes
> > functions can be passed like that)
> >
> > # MySum as above
> >
> > GoodIntegrateUnitInterval < function(xIntegrand, yParameter) {
> > # Requires xIntegrand to be a function of two variables x,y
> > # You can actually do this in the code, but for now let's just assume
> no
> > user error and that xIntegrand is the right sort of thing.
> > ans = integrate(xIntegrand, 0, 1, yParameter)
> > return(ans)
> > }
> >
> > R> GoodIntegrateUnitInverval(MySum, 3)
> > 3.5
> >
> > as before.
> >
> > There's nothing wrong with using "result" like I've used "ans," but I do
> > hesitate to see it used as a function rather than a variable. A good rule
> of
> > thumb is to check if a variable is already defined as a function name
> using
> > the apropos() command.
> >
> > I don't have time or inclination to rework your whole code right now, but
> > take a stab at formatting it with consistent+informative variable and
> > function names, a well reasoned use of scoping, and appropriate use of
> > integrate() and I'll happily comment on it.
> >
> > Hope this helps,
> >
> > Michael Weylandt
> >
> > On Thu, Sep 1, 2011 at 8:57 PM, . . < [hidden email]> wrote:
> >>
> >> Thanks for your reply Michael, it seems I have a lot of things to
> >> learn yet but for sure, your response is being very helpful in this
> >> proccess. I will try to explore every point you said:
> >>
> >> A doubt I have is, if I define "func < function(x,y) x + y" how can I
> >> integrate it only in "x"? My solution for this would be to define
> >> "func < function(x) x + y". Is not ok?
> >>
> >> Also, with respect to the helper functions I'd created, I am wondering
> >> if you can see a better organization for my code. It is so because
> >> this is the only way I can see. Particularly I do not like how I am
> >> using "results", but I can not think in another form.
> >>
> >> Thanks in advance.
> >>
> >> On Thu, Sep 1, 2011 at 2:44 PM, R. Michael Weylandt
> >> < [hidden email]> wrote:
> >> > Leaving aside some other issues that this whole email chain has opened
> >> > up,
> >> >
> >> > I'd guess that your most immediate problem is that you are trying to
> >> > numerically integrate the PMF of a discrete distribution but you are
> >> > treating it as a continuous distribution. If you took the time to
> >> > properly
> >> > debug (as you were instructed yesterday) you'd probably find that
> >> > whenever
> >> > you call dpois(x, lambda) for x not an integer you get a warning
> >> > message.
> >> >
> >> > Specifically, check this out
> >> >
> >> >> integrate(dpois,0,Inf,1)
> >> > 9.429158e13 with absolute error < 1.7e12
> >> >
> >> >> n = 0:1000; sum(dpois(n,1))
> >> > 1
> >> >
> >> > I could be entirely off base here, but I'm guessing that many of your
> >> > problems derive from this.
> >> >
> >> >
> >> >
> >> > On another basis, please, please read this:
> >> > http://googlestyleguide.googlecode.com/svn/trunk/googlerstyle.html> >> > or this
> >> > http://had.co.nz/stat405/resources/rstyleguide.html> >> >
> >> > And, perhaps most importantly, don't rely on the black magic of values
> >> > moving in and out of functions (lexical scoping). Seriously, just
> don't
> >> > do
> >> > it.
> >> >
> >> > If you have helper functions that need values, actively pass them: you
> >> > will
> >> > save yourself hours of trouble when (not if) you debug your functions.
> >> > I'm
> >> > looking, for example, at g() in the first big block of code you
> >> > provided.
> >> > Call it g(a,n) and spend the extra 4 keystrokes to pass the values. It
> >> > makes
> >> > everyone happier.
> >> >
> >> > Michael
> >> >
> >> > On Thu, Sep 1, 2011 at 12:37 PM, . . < [hidden email]> wrote:
> >> >>
> >> >> So, please excuse me Michael, you are completely sure. I will try
> >> >> describe I am trying to do, please let me know if I can provide more
> >> >> info.
> >> >>
> >> >> The idea is provide to "func" two probability density functions(PDFs)
> >> >> and obtain another PDF that is a compound of them. In a final
> analysis
> >> >> this characterize an abundance distribution for me. The two PDFs are
> >> >> provided through "f" and "g" and there is some manipulation here
> >> >> because I need flexibility to easily change this two funcions.
> >> >>
> >> >> In the code provided, "f" is the Exponential distribution and "g" is
> >> >> the Poisson distribution. For this case, I have the analytical
> >> >> solution, below. This way I can check the result. But I am also
> >> >> considering other combinations of "f" and "g" that have difficult,
> or
> >> >> even does not have analitical solution. This is the reason why I am
> >> >> trying to develop "func".
> >> >>
> >> >> func2 < function(y, frac, rate, trunc=0, log=FALSE) {
> >> >> is.wholenumber < function(x, tol = .Machine$double.eps^0.5)
> >> >> abs(x  round(x)) < tol
> >> >> if(FALSE %in% sapply(y,is.wholenumber))
> >> >> print("y must be integer because dpoix is a discrete PDF.")
> >> >> else {
> >> >> f < function(y){
> >> >> b < y*log(frac)
> >> >> m < log(rate)
> >> >> n < (y+1)*log(rate+frac)
> >> >> if(log)b+mn else exp(b+mn)
> >> >> }
> >> >> f(y)/(1f(trunc))
> >> >> }
> >> >> }
> >> >> > func2(200,0.05,0.001)
> >> >> [1] 0.000381062
> >> >>
> >> >> In theory, the interval of integration is 0 to Inf, but for some
> tests
> >> >> I did, go up to 2000 may still provide reasonable results.
> >> >>
> >> >> Also, as it seems, I am still writing my first functions in R and
> >> >> suggestions are welcome, please.
> >> >>
> >> >> Again, appologies for my previous mistake. It was not my intention to
> >> >> blame about "integrate".
> >> >>
> >> >> On Thu, Sep 1, 2011 at 11:49 AM, R. Michael Weylandt
> >> >> < [hidden email]> wrote:
> >> >> > I'm going to try to put this nicely:
> >> >> >
> >> >> > What you provided is not a problem with integrate. Instead, you
> >> >> > provided
> >> >> > a
> >> >> > rather unintelligible and badlywritten piece of code that
> >> >> > (miraculously)
> >> >> > seems to work, though it's not well documented so I have no idea if
> >> >> > 1.3e21
> >> >> > is what you want to get.
> >> >> >
> >> >> > Let's try this again: per your original request, what is the
> problem
> >> >> > with
> >> >> > integrate?
> >> >> >
> >> >> > If instead you feel there's something wrong with your code, might I
> >> >> > suggest
> >> >> > you just say that and ask for help, rather than passing the blame
> >> >> > onto a
> >> >> > perfectly useful base function.
> >> >> >
> >> >> > Oh, and since you asked that I propose something: comment your
> code.
> >> >> >
> >> >> > Michael
> >> >> >
> >> >> > On Thu, Sep 1, 2011 at 10:33 AM, . . < [hidden email]> wrote:
> >> >> >>
> >> >> >> Hi Michael,
> >> >> >>
> >> >> >> This is the problem:
> >> >> >>
> >> >> >> func < Vectorize(function(x, a, sad, samp="pois", trunc=0, ...) {
> >> >> >> result < function(x) {
> >> >> >> f1 < function(n) {
> >> >> >> f < function() {
> >> >> >> dcom < paste("d", sad, sep="")
> >> >> >> dots < c(as.name("n"), list(...))
> >> >> >> do.call(dcom, dots)
> >> >> >> }
> >> >> >> g < function() {
> >> >> >> dcom < paste("d", samp, sep="")
> >> >> >> lambda < a * n
> >> >> >> dots < c(as.name("x"), as.name("lambda"))
> >> >> >> do.call(dcom, dots)
> >> >> >> }
> >> >> >> f() * g()
> >> >> >> }
> >> >> >> integrate(f1,0,2000)$value
> >> >> >> # adaptIntegrate(f1,0,2000)$integral
> >> >> >>
> >> >> >> # n < 0:2000
> >> >> >> # trapz(n,f1(n))
> >> >> >>
> >> >> >> # area(f1, 0, 2000, limit=10000, eps=1e100)
> >> >> >> }
> >> >> >> return(result(x) / (1  result(trunc)))
> >> >> >> }, "x")
> >> >> >> func(200, 0.05, "exp", rate=0.001)
> >> >> >>
> >> >> >> If you could propose something I will be gratefull.
> >> >> >>
> >> >> >> Thanks in advance.
> >> >> >>
> >> >> >> On Thu, Sep 1, 2011 at 10:55 AM, R. Michael Weylandt
> >> >> >> < [hidden email]> wrote:
> >> >> >> > Mr ". .",
> >> >> >> >
> >> >> >> > MASS::area comes to mind but it may be more helpful if you could
> >> >> >> > say
> >> >> >> > what
> >> >> >> > you are looking for / why integrate is not appropriate it is for
> >> >> >> > whatever
> >> >> >> > you are doing.
> >> >> >> >
> >> >> >> > Strictly speaking, I suppose there are all sorts of
> "alternatives"
> >> >> >> > to
> >> >> >> > integrate() if you are willing to be really creative and build
> >> >> >> > something
> >> >> >> > from scratch: diff(), cumsum(), lm(), hist(), t(), c(), ....
> >> >> >> >
> >> >> >> > Michael Weylandt
> >> >> >> >
> >> >> >> > On Thu, Sep 1, 2011 at 9:53 AM, B77S < [hidden email]>
> wrote:
> >> >> >> >>
> >> >> >> >> package "caTools"
> >> >> >> >> see ?trapz
> >> >> >> >>
> >> >> >> >>
> >> >> >> >> . wrote:
> >> >> >> >> >
> >> >> >> >> > Hi all,
> >> >> >> >> >
> >> >> >> >> > is there any alternative to the function integrate?
> >> >> >> >> >
> >> >> >> >> > Any comments are welcome.
> >> >> >> >> >
> >> >> >> >> > Thanks in advance.
> >> >> >> >> >
> >> >> >> >> > ______________________________________________
> >> >> >> >> > [hidden email] mailing list
> >> >> >> >> > https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> >> >> > PLEASE do read the posting guide
> >> >> >> >> > http://www.Rproject.org/postingguide.html> >> >> >> >> > and provide commented, minimal, selfcontained, reproducible
> >> >> >> >> > code.
> >> >> >> >> >
> >> >> >> >>
> >> >> >> >> 
> >> >> >> >> View this message in context:
> >> >> >> >>
> >> >> >> >>
> >> >> >> >>
> >> >> >> >>
> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3783645.html> >> >> >> >> Sent from the R help mailing list archive at Nabble.com.
> >> >> >> >>
> >> >> >> >> ______________________________________________
> >> >> >> >> [hidden email] mailing list
> >> >> >> >> https://stat.ethz.ch/mailman/listinfo/rhelp> >> >> >> >> PLEASE do read the posting guide
> >> >> >> >> http://www.Rproject.org/postingguide.html> >> >> >> >> and provide commented, minimal, selfcontained, reproducible
> >> >> >> >> code.
> >> >> >> >
> >> >> >> >
> >> >> >
> >> >> >
> >> >
> >> >
> >
> >
>
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https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


. wrote
Hi, continuing the improvements...
I've prepared a new code:
ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
dots < list(...)
Compound < function(individuals, frac, n.species, sad, samp, dots) {
print(c("Size:", length(individuals), "Compound individuals:",
individuals, "End."))
RegDist < function(n.species, sad, dots) { # "RegDist" may be
Exponential, Gamma, etc.
dcom < paste("d", as.name(sad), sep="")
dots < as.list(c(n.species, dots))
ans < do.call(dcom, dots)
return(ans)
}
SampDist < function(individuals, frac, n.species, samp) { #
"SampDist" may be Poisson or Negative Binomial
dcom < paste("d", samp, sep="")
lambda < frac * n.species
dots < as.list(c(individuals, lambda))
ans < do.call(dcom, dots)
return(ans)
}
ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
n.species, samp)
return(ans)
}
IntegrateScheme < function(Compound, individuals, frac, sad, samp, dots) {
print(c("Size:", length(individuals), "Integrate individuals:",
individuals))
ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
dots)$value
return(ans)
}
ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
return(ans)
}
ddae(2, 0.05, "exp")
Now I can't understand what happen to "individuals", why is it
changing in value and size? I've tried to "traceback()" and "debug()",
but I was not smart enough to understand what is going on.
Could you, please, give some more help?
From the help for integrate argument f :
an R function taking a numeric first argument and returning a numeric vector of the same length. .....
Function Compound is passed to integrate. First argument is "individuals" and integrate is integrating over individuals. That is why it is changing in value and size: integrate is only doing what you asked it do.
The code is too uncommented and convoluted to supply further comments.
You really should simplify this
Berend


Hello all,
Returning to this question, I would like to ask for help on how to
integrate the PMF of a discrete distribution  Michael's guess about
the most immediate problem (Sep 01, 2011; 2:44pm).
I was thinking in two ways to do this: First is numerically integrate
the function but sampling it only at integer values. For this, I've
used the rectangle method of integration:
leftrect < function(f, from, to, n, ...) {
h < (to  from) / n
sum < 0
d < list(...)
for(i in seq(from, toh, h)) {
dots < c(list(i), d)
sum < sum + do.call(f, dots)
}
return(h * sum)
}
Second option in my mind is to, find and replace the discrete function
by a continuous version, but I've no idea how to do this.
First option don't gave results as good. May another method ... ? Is
it possible to specify the sampling points in "Integrate"?
Any comments are welcome.
Thanks in advanve.
On Wed, Sep 7, 2011 at 4:47 AM, Berend Hasselman < [hidden email]> wrote:
>
> . wrote:
>>
>> Hi, continuing the improvements...
>>
>> I've prepared a new code:
>>
>> ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
>> dots < list(...)
>> Compound < function(individuals, frac, n.species, sad, samp, dots) {
>> print(c("Size:", length(individuals), "Compound individuals:",
>> individuals, "End."))
>> RegDist < function(n.species, sad, dots) { # "RegDist" may be
>> Exponential, Gamma, etc.
>> dcom < paste("d", as.name(sad), sep="")
>> dots < as.list(c(n.species, dots))
>> ans < do.call(dcom, dots)
>> return(ans)
>> }
>> SampDist < function(individuals, frac, n.species, samp) { #
>> "SampDist" may be Poisson or Negative Binomial
>> dcom < paste("d", samp, sep="")
>> lambda < frac * n.species
>> dots < as.list(c(individuals, lambda))
>> ans < do.call(dcom, dots)
>> return(ans)
>> }
>> ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
>> n.species, samp)
>> return(ans)
>> }
>> IntegrateScheme < function(Compound, individuals, frac, sad, samp,
>> dots) {
>> print(c("Size:", length(individuals), "Integrate individuals:",
>> individuals))
>> ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
>> dots)$value
>> return(ans)
>> }
>> ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
>> return(ans)
>> }
>>
>> ddae(2, 0.05, "exp")
>>
>> Now I can't understand what happen to "individuals", why is it
>> changing in value and size? I've tried to "traceback()" and "debug()",
>> but I was not smart enough to understand what is going on.
>>
>> Could you, please, give some more help?
>>
>
> >From the help for integrate argument f :
>
> an R function taking a numeric first argument and returning a numeric vector
> of the same length. .....
>
> Function Compound is passed to integrate. First argument is "individuals"
> and integrate is integrating over individuals. That is why it is changing in
> value and size: integrate is only doing what you asked it do.
>
> The code is too uncommented and convoluted to supply further comments.
> You really should simplify this
>
> Berend
>
>
> 
> View this message in context: http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3795491.html> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/rhelp> PLEASE do read the posting guide http://www.Rproject.org/postingguide.html> and provide commented, minimal, selfcontained, reproducible code.
>
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.


You may perhaps want to be more specific about your problem then "First
option don't gave results as good. May another method ... ?" if you want
help...
I'm not entirely sure what your problem with this sort of discrete numerical
integration is, other than you are making it too hard:
rectIntegrate < function(f, from, to, ...) {
from < floor(from); to < ceiling(to)
n = seq(from, to)
return(sum(do.call(f, c(list(n),...))))
}
> rectIntegrate(dpois,0,20,3)
[1] 1
> rectIntegrate(function(x,...){dpois(x,...)*x},0,20,3)
[1] 3
So it seems to work pretty well. What was the problem again?
Michael
On Sun, Sep 18, 2011 at 11:40 AM, . . < [hidden email]> wrote:
> Hello all,
>
> Returning to this question, I would like to ask for help on how to
> integrate the PMF of a discrete distribution  Michael's guess about
> the most immediate problem (Sep 01, 2011; 2:44pm).
>
> I was thinking in two ways to do this: First is numerically integrate
> the function but sampling it only at integer values. For this, I've
> used the rectangle method of integration:
>
> leftrect < function(f, from, to, n, ...) {
> h < (to  from) / n
> sum < 0
> d < list(...)
> for(i in seq(from, toh, h)) {
> dots < c(list(i), d)
> sum < sum + do.call(f, dots)
> }
> return(h * sum)
> }
>
> Second option in my mind is to, find and replace the discrete function
> by a continuous version, but I've no idea how to do this.
>
> First option don't gave results as good. May another method ... ? Is
> it possible to specify the sampling points in "Integrate"?
>
> Any comments are welcome.
>
> Thanks in advanve.
>
>
> On Wed, Sep 7, 2011 at 4:47 AM, Berend Hasselman < [hidden email]> wrote:
> >
> > . wrote:
> >>
> >> Hi, continuing the improvements...
> >>
> >> I've prepared a new code:
> >>
> >> ddae < function(individuals, frac, sad, samp="pois", trunc=0, ...) {
> >> dots < list(...)
> >> Compound < function(individuals, frac, n.species, sad, samp, dots) {
> >> print(c("Size:", length(individuals), "Compound individuals:",
> >> individuals, "End."))
> >> RegDist < function(n.species, sad, dots) { # "RegDist" may be
> >> Exponential, Gamma, etc.
> >> dcom < paste("d", as.name(sad), sep="")
> >> dots < as.list(c(n.species, dots))
> >> ans < do.call(dcom, dots)
> >> return(ans)
> >> }
> >> SampDist < function(individuals, frac, n.species, samp) { #
> >> "SampDist" may be Poisson or Negative Binomial
> >> dcom < paste("d", samp, sep="")
> >> lambda < frac * n.species
> >> dots < as.list(c(individuals, lambda))
> >> ans < do.call(dcom, dots)
> >> return(ans)
> >> }
> >> ans < RegDist(n.species, sad, dots) * SampDist(individuals, frac,
> >> n.species, samp)
> >> return(ans)
> >> }
> >> IntegrateScheme < function(Compound, individuals, frac, sad, samp,
> >> dots) {
> >> print(c("Size:", length(individuals), "Integrate individuals:",
> >> individuals))
> >> ans < integrate(Compound, 0, 2000, individuals, frac, sad, samp,
> >> dots)$value
> >> return(ans)
> >> }
> >> ans < IntegrateScheme(Compound, individuals, frac, sad, samp, dots)
> >> return(ans)
> >> }
> >>
> >> ddae(2, 0.05, "exp")
> >>
> >> Now I can't understand what happen to "individuals", why is it
> >> changing in value and size? I've tried to "traceback()" and "debug()",
> >> but I was not smart enough to understand what is going on.
> >>
> >> Could you, please, give some more help?
> >>
> >
> > >From the help for integrate argument f :
> >
> > an R function taking a numeric first argument and returning a numeric
> vector
> > of the same length. .....
> >
> > Function Compound is passed to integrate. First argument is "individuals"
> > and integrate is integrating over individuals. That is why it is changing
> in
> > value and size: integrate is only doing what you asked it do.
> >
> > The code is too uncommented and convoluted to supply further comments.
> > You really should simplify this
> >
> > Berend
> >
> >
> > 
> > View this message in context:
> http://r.789695.n4.nabble.com/Alternativestointegratetp3783624p3795491.html> > Sent from the R help mailing list archive at Nabble.com.
> >
> > ______________________________________________
> > [hidden email] mailing list
> > https://stat.ethz.ch/mailman/listinfo/rhelp> > PLEASE do read the posting guide
> http://www.Rproject.org/postingguide.html> > and provide commented, minimal, selfcontained, reproducible code.
> >
>
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https://stat.ethz.ch/mailman/listinfo/rhelpPLEASE do read the posting guide http://www.Rproject.org/postingguide.htmland provide commented, minimal, selfcontained, reproducible code.

