Hi all,
I recently tried to calculate the mean and the median just for one column. In this column I have numbers with some empty cells due to missing data. So how can I calculate the mean just for the filled cells? I tried: mean(dataSet2$ac_60d_4d_after_ann[!is.na(master$ac_60d_4d_after_ann)], na.rm=TRUE) But the output was different to the calculation I died in Microsoft Excel. Thanks in advance, Felix |
Hi
see inline > -----Original Message----- > From: [hidden email] [mailto:r-help-bounces@r- > project.org] On Behalf Of fxen3k > Sent: Friday, October 05, 2012 11:28 AM > To: [hidden email] > Subject: [R] Calculating the mean in one column with empty cells > > Hi all, > > I recently tried to calculate the mean and the median just for one > column. > In this column I have numbers with some empty cells due to missing > data. > So how can I calculate the mean just for the filled cells? > I tried: > mean(dataSet2$ac_60d_4d_after_ann[!is.na(master$ac_60d_4d_after_ann)], > na.rm=TRUE) > mean(dataSet2$ac_60d_4d_after_ann, na.rm=TRUE) shall suffice. But the output was different to the calculation I died in Microsoft > Excel. Hm. I am also sometimes dying from Excel performance. There could be 2 options: Excel is wrong You did not have transferred values from Excel to R correctly, they are screwed somehow. Which one is true is difficult to decide based on information you revealed. Regards Petr > > Thanks in advance, > Felix > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with- > empty-cells-tp4645135.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
On 05-10-2012, at 11:27, fxen3k wrote: > Hi all, > > I recently tried to calculate the mean and the median just for one column. > In this column I have numbers with some empty cells due to missing data. > So how can I calculate the mean just for the filled cells? > I tried: > mean(dataSet2$ac_60d_4d_after_ann[!is.na(master$ac_60d_4d_after_ann)], > na.rm=TRUE) > But the output was different to the calculation I died in Microsoft Excel. > No data ==> no can answer question. What did you expect? What did Excel give you? But you are trying to calculate the mean of dataSet2$ac_60d_4d_after_ann and indexing with the indices of non-NA numbers of master$ac_60d_4d_after_ann. mean(dataSet2$ac_60d_4d_after_ann, na.rm=TRUE) should do what you want. Berend ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
fxen3k <f.sehardt <at> gmail.com> writes:
> > Hi all, > > I recently tried to calculate the mean and the median just for one column. > In this column I have numbers with some empty cells due to missing data. > So how can I calculate the mean just for the filled cells? > I tried: > mean(dataSet2$ac_60d_4d_after_ann[!is.na(master$ac_60d_4d_after_ann)], > na.rm=TRUE) > But the output was different to the calculation I died in Microsoft Excel. > > Thanks in advance, > Felix > > -- > View this message in context: > Sent from the R help mailing list archive at Nabble.com. > > Hi Felix, Assuming that you have the data frame formatted properly, mean(yourdata$column, na.rm = T) should work. When coverting an excel table to R, I usually fill in blank cells with NA before importing. If you try to import an data frame with empty cells, you usually get an error using read.table(). But since you seem to have already got you data into R, that may not be the problem. HTH, Ken ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
I'm sorry!
Now I tried it again with just 10 numbers (just random numbers) and Excel gives a different output than R. Here are the numbers I used: 0,2006160108532920 0,1321167173880490 0,0563941428921262 0,0264198664609803 0,0200581303857603 -0,2971754213679500 -0,2353086361784190 0,0667195538296534 0,1755852636926560 And this is the command in R: > nums <- as.numeric(as.character(dataSet2$ac_bhar_60d_4d_after_ann[2:10])) > m <- mean(nums, na.rm = T) > m The output of R is: > print(m, digits= 12) [1] 0.0166666666667 The output in Excel is: 0,0161584031062386 The numbers are imported correctly. Or does R reduce the imported numbers to any decimal place? (i don't think so ;-) ) Best Regards, Felix |
I imported the whole dataset with read.csv2() and it works fine. (2 for German is correct ;) )
I already checked the numbers and I also tried to calculate the mean of a range of numbers where there is no NA given. (as mentioned in my last post above). |
In reply to this post by fxen3k
HI,
Not sure how your dataset looks like: set.seed(1) dat1<-data.frame(col1=c(sample(1:50,5,replace=TRUE),NA,sample(1:25,3,replace=TRUE),NA,sample(1:25,2,replace=TRUE)),col2=c(NA,NA,rnorm(8,15),NA,NA)) mean(dat1$col1[!is.na(dat1$col1)]) #[1] 20.1 mean(dat1$col1,na.rm=TRUE) #[1] 20.1 But, there is one problem that is obvious "dataset2" and "master". Looks like you have two datasets. A.K. ----- Original Message ----- From: fxen3k <[hidden email]> To: [hidden email] Cc: Sent: Friday, October 5, 2012 5:27 AM Subject: [R] Calculating the mean in one column with empty cells Hi all, I recently tried to calculate the mean and the median just for one column. In this column I have numbers with some empty cells due to missing data. So how can I calculate the mean just for the filled cells? I tried: mean(dataSet2$ac_60d_4d_after_ann[!is.na(master$ac_60d_4d_after_ann)], na.rm=TRUE) But the output was different to the calculation I died in Microsoft Excel. Thanks in advance, Felix -- View this message in context: http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with-empty-cells-tp4645135.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
If the numbers were imported correctly you wouldn't need to do
as.numeric(as.character(yourdata)). Please use dput() to provide your data, as in: dput(dataSet2$ac_bhar_60d_4d_after_ann[2:10]) Otherwise it's impossible for us to diagnose your problem or reproduce your error. testdata <- c(0.2006160108532920, 0.1321167173880490, 0.0563941428921262, 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) > mean(testdata) [1] 0.0161584 Sarah On Fri, Oct 5, 2012 at 9:14 AM, fxen3k <[hidden email]> wrote: > I'm sorry! > > Now I tried it again with just 10 numbers (just random numbers) and Excel > gives a different output than R. > > Here are the numbers I used: > > 0,2006160108532920 > 0,1321167173880490 > 0,0563941428921262 > 0,0264198664609803 > 0,0200581303857603 > -0,2971754213679500 > -0,2353086361784190 > 0,0667195538296534 > 0,1755852636926560 > > And this is the command in R: > >> nums <- as.numeric(as.character(dataSet2$ac_bhar_60d_4d_after_ann[2:10])) >> m <- mean(nums, na.rm = T) >> m > > The output of R is: >> print(m, digits= 12) > [1] 0.0166666666667 > > The output in Excel is: > 0,0161584031062386 > > The numbers are imported correctly. Or does R reduce the imported numbers to > any decimal place? (i don't think so ;-) ) > > Best Regards, > Felix > > > Sarah Goslee http://www.functionaldiversity.org ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
You need to show us the verbatim output of the following R command
dput(dataSet2$ac_bhar_60d_4d_after_ann[2:10]) to make any further progress. Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com > -----Original Message----- > From: [hidden email] [mailto:[hidden email]] On Behalf > Of fxen3k > Sent: Friday, October 05, 2012 6:15 AM > To: [hidden email] > Subject: Re: [R] Calculating the mean in one column with empty cells > > I'm sorry! > > Now I tried it again with just 10 numbers (just random numbers) and Excel > gives a different output than R. > > Here are the numbers I used: > > 0,2006160108532920 > 0,1321167173880490 > 0,0563941428921262 > 0,0264198664609803 > 0,0200581303857603 > -0,2971754213679500 > -0,2353086361784190 > 0,0667195538296534 > 0,1755852636926560 > > And this is the command in R: > > > nums <- as.numeric(as.character(dataSet2$ac_bhar_60d_4d_after_ann[2:10])) > > m <- mean(nums, na.rm = T) > > m > > The output of R is: > > print(m, digits= 12) > [1] 0.0166666666667 > > The output in Excel is: > 0,0161584031062386 > > The numbers are imported correctly. Or does R reduce the imported numbers to > any decimal place? (i don't think so ;-) ) > > Best Regards, > Felix > > > > > -- > View this message in context: http://r.789695.n4.nabble.com/Calculating-the-mean-in- > one-column-with-empty-cells-tp4645135p4645165.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
Hi
> -----Original Message----- > From: [hidden email] [mailto:r-help-bounces@r- > project.org] On Behalf Of fxen3k > Sent: Friday, October 05, 2012 3:18 PM > To: [hidden email] > Subject: Re: [R] Calculating the mean in one column with empty cells > > I imported the whole dataset with read.csv2() and it works fine. (2 for > German is correct ;) ) > > I already checked the numbers and I also tried to calculate the mean of > a range of numbers where there is no NA given. (as mentioned in my last > post above). But as Sarah pointed out the result in R from your values (when correctly read) are the same as in Excel. Therefore the problem seems to be in ***your*** data output from str(dataSet2$ac_bhar_60d_4d_after_ann[2:10]) can be helpful in diagnosing what may be going on. Regards Petr > > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with- > empty-cells-tp4645135p4645166.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
Hi,
the first command was bringing the numbers into R directly: > testdata <- c(0.2006160108532920, 0.1321167173880490, 0.0563941428921262, 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) > mean(testdata) [1] 0.0161584 Here I tried to calculate the mean with the same numbers as given above, but taken from my dataset. > str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 > mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) [1] 0.01666667 It seems that in the second case he calculates the mean with rounded numbers (0.2 and not 0.20061601085...) Could it be that R imports only the rounded numbers? How can I build a CSV-file with numbers showing all decimal places? Because I think my current CSV-file only has numbers with 2 decimal places. Kind Regards, Felix |
On Sat, Oct 6, 2012 at 9:11 AM, fxen3k <[hidden email]> wrote:
> Hi, > > the first command was bringing the numbers into R directly: > *> testdata <- c(0.2006160108532920, 0.1321167173880490, 0.0563941428921262, > 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, > -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) >> mean(testdata) > [1] 0.0161584* > > Here I tried to calculate the mean with the same numbers as given above, but > taken from my dataset. > * >> str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 >> mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > [1] 0.01666667 > * > > It seems that in the second case he calculates the mean with rounded numbers > (0.2 and not 0.20061601085...) > Could it be that R imports only the rounded numbers? > How can I build a CSV-file with numbers showing all decimal places? Because > I think my current CSV-file only has numbers with 2 decimal places. That's something you need to figure out with whatever software is writing the csv. Cheers, Michael > > > Kind Regards, > Felix > > > > > -- > View this message in context: http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with-empty-cells-tp4645135p4645252.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
Where is the csv data coming from? If it is an export from a spreadsheet, Excel (and others?) has a nasty habit of exporting "as displayed" rather than the actual number as it's default.
John Kane Kingston ON Canada > -----Original Message----- > From: [hidden email] > Sent: Sat, 6 Oct 2012 01:11:11 -0700 (PDT) > To: [hidden email] > Subject: Re: [R] Calculating the mean in one column with empty cells > > Hi, > > the first command was bringing the numbers into R directly: > *> testdata <- c(0.2006160108532920, 0.1321167173880490, > 0.0563941428921262, > 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, > -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) >> mean(testdata) > [1] 0.0161584* > > Here I tried to calculate the mean with the same numbers as given above, > but > taken from my dataset. > * >> str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 >> mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > [1] 0.01666667 > * > > It seems that in the second case he calculates the mean with rounded > numbers > (0.2 and not 0.20061601085...) > Could it be that R imports only the rounded numbers? > How can I build a CSV-file with numbers showing all decimal places? > Because > I think my current CSV-file only has numbers with 2 decimal places. > > > Kind Regards, > Felix > > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with-empty-cells-tp4645135p4645252.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
I created a Microsoft Excel spreadsheet. As you said, I only have "as displayed" numbers. I just solved the problem by showing 25 decimal places in Excel and then exported the data into a CSV-file.
Is there a better way to solve this? Regards, Felix |
In reply to this post by fxen3k
On Oct 6, 2012, at 1:11 AM, fxen3k wrote: > Hi, > > the first command was bringing the numbers into R directly: > *> testdata <- c(0.2006160108532920, 0.1321167173880490, 0.0563941428921262, > 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, > -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) >> mean(testdata) > [1] 0.0161584* > > Here I tried to calculate the mean with the same numbers as given above, but > taken from my dataset. > * >> str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 >> mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > [1] 0.01666667 > * This is something that has happened in data processing: > dat <- read.csv2(text="0,2006160108532920 + 0,1321167173880490 + 0,0563941428921262 + 0,0264198664609803 + 0,0200581303857603 + -0,2971754213679500 + -0,2353086361784190 + 0,0667195538296534 + 0,1755852636926560 + ", header=FALSE) > mean(dat[[1]]) [1] 0.0161584 > > It seems that in the second case he calculates the mean with rounded numbers > (0.2 and not 0.20061601085...) > Could it be that R imports only the rounded numbers? > How can I build a CSV-file with numbers showing all decimal places? Because > I think my current CSV-file only has numbers with 2 decimal places. > That is more likely the fault of Excel than it is something R is responsible for. -- David Winsemius, MD Alameda, CA, USA ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
For nine numbers, R-helpers should recommend that people
show their data with dput(obj) instead of str(obj). dput() shows everything in the object to full precision. str() shows a summary of the object and rounds numbers to 2 digits -- it is good for an overview of the data, but when the question is "why did I get a mean of .066666 instead of .06547494 from my 9 numbers" str() is not useful. Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com > -----Original Message----- > From: [hidden email] [mailto:[hidden email]] On Behalf > Of David Winsemius > Sent: Saturday, October 06, 2012 9:08 AM > To: fxen3k > Cc: [hidden email] > Subject: Re: [R] Calculating the mean in one column with empty cells > > > On Oct 6, 2012, at 1:11 AM, fxen3k wrote: > > > Hi, > > > > the first command was bringing the numbers into R directly: > > *> testdata <- c(0.2006160108532920, 0.1321167173880490, 0.0563941428921262, > > 0.0264198664609803, 0.0200581303857603, -0.2971754213679500, > > -0.2353086361784190, 0.0667195538296534, 0.1755852636926560) > >> mean(testdata) > > [1] 0.0161584* > > > > Here I tried to calculate the mean with the same numbers as given above, but > > taken from my dataset. > > * > >> str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > > num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 > >> mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > > [1] 0.01666667 > > * > > This is something that has happened in data processing: > > > dat <- read.csv2(text="0,2006160108532920 > + 0,1321167173880490 > + 0,0563941428921262 > + 0,0264198664609803 > + 0,0200581303857603 > + -0,2971754213679500 > + -0,2353086361784190 > + 0,0667195538296534 > + 0,1755852636926560 > + ", header=FALSE) > > mean(dat[[1]]) > [1] 0.0161584 > > > > > > It seems that in the second case he calculates the mean with rounded numbers > > (0.2 and not 0.20061601085...) > > Could it be that R imports only the rounded numbers? > > How can I build a CSV-file with numbers showing all decimal places? Because > > I think my current CSV-file only has numbers with 2 decimal places. > > > > That is more likely the fault of Excel than it is something R is responsible for. > > -- > > David Winsemius, MD > Alameda, CA, USA > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by fxen3k
On Oct 6, 2012, at 4:54 PM, fxen3k <[hidden email]> wrote: > I created a Microsoft Excel spreadsheet. As you said, I only have "as > displayed" numbers. I just solved the problem by showing 25 decimal places > in Excel and then exported the data into a CSV-file. > > Is there a better way to solve this? > Don't use Excel. (or at least find a way to get reasonable defaults) This isn't sarcastic: just acknowledging that instances like this show Excel really isn't a suitable tool for real data analysis (cf Pat Burns' 'Spreadsheet Addiction' paper) Michael > Regards, > Felix > > > > -- > View this message in context: http://r.789695.n4.nabble.com/Calculating-the-mean-in-one-column-with-empty-cells-tp4645135p4645278.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
In reply to this post by William Dunlap
Hi
> -----Original Message----- > From: [hidden email] [mailto:r-help-bounces@r- > project.org] On Behalf Of William Dunlap > Sent: Saturday, October 06, 2012 6:17 PM > To: David Winsemius; fxen3k > Cc: [hidden email] > Subject: Re: [R] Calculating the mean in one column with empty cells > > For nine numbers, R-helpers should recommend that people show their > data with dput(obj) instead of str(obj). > dput() shows everything in the object to full precision. str() shows a > summary of the object and rounds numbers to 2 digits -- it is good for actually 4 digits str(testdata) num [1:9] 0.2006 0.1321 0.0564 0.0264 0.0201 ... but you are right that dput does not hide anything. Anyway exporting through csv from Excel like programs through csv can be rather problematic due to rounding habit of those programs. The best way to solve this problem will probably be to ask Microsoft help for assistance. Regards Petr > an overview of the data, but when the question is "why did I get a mean > of .066666 instead of .06547494 from my 9 numbers" > str() is not useful. > > Bill Dunlap > Spotfire, TIBCO Software > wdunlap tibco.com > > > > -----Original Message----- > > From: [hidden email] > > [mailto:[hidden email]] On Behalf Of David Winsemius > > Sent: Saturday, October 06, 2012 9:08 AM > > To: fxen3k > > Cc: [hidden email] > > Subject: Re: [R] Calculating the mean in one column with empty cells > > > > > > On Oct 6, 2012, at 1:11 AM, fxen3k wrote: > > > > > Hi, > > > > > > the first command was bringing the numbers into R directly: > > > *> testdata <- c(0.2006160108532920, 0.1321167173880490, > > > 0.0563941428921262, 0.0264198664609803, 0.0200581303857603, > > > -0.2971754213679500, -0.2353086361784190, 0.0667195538296534, > > > 0.1755852636926560) > > >> mean(testdata) > > > [1] 0.0161584* > > > > > > Here I tried to calculate the mean with the same numbers as given > > > above, but taken from my dataset. > > > * > > >> str(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > > > num [1:9] 0.2 0.13 0.06 0.03 0.02 -0.3 -0.24 0.07 0.18 > > >> mean(dataSet2$ac_bhar_60d_4d_after_ann[1:9]) > > > [1] 0.01666667 > > > * > > > > This is something that has happened in data processing: > > > > > dat <- read.csv2(text="0,2006160108532920 > > + 0,1321167173880490 > > + 0,0563941428921262 > > + 0,0264198664609803 > > + 0,0200581303857603 > > + -0,2971754213679500 > > + -0,2353086361784190 > > + 0,0667195538296534 > > + 0,1755852636926560 > > + ", header=FALSE) > > > mean(dat[[1]]) > > [1] 0.0161584 > > > > > > > > > > It seems that in the second case he calculates the mean with > rounded > > > numbers > > > (0.2 and not 0.20061601085...) > > > Could it be that R imports only the rounded numbers? > > > How can I build a CSV-file with numbers showing all decimal places? > > > Because I think my current CSV-file only has numbers with 2 decimal > places. > > > > > > > That is more likely the fault of Excel than it is something R is > responsible for. > > > > -- > > > > David Winsemius, MD > > Alameda, CA, USA > > > > ______________________________________________ > > [hidden email] mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ > [hidden email] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting- > guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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