New psi with rlm

Previous Topic Next Topic
classic Classic list List threaded Threaded
1 message Options
Reply | Threaded
Open this post in threaded view

New psi with rlm

Angelo Secchi

How can I define a new psi function in the rlm comand?
In particular  I would like to implement the case for

\rho(u)=0.5*(u^2) and \psi(u)=u

in order to assume normally distributed errors.
Any help?

 Angelo Secchi                     PGP Key ID:EA280337

[hidden email] mailing list
PLEASE do read the posting guide!