# Problem with LM

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## Problem with LM

 The values read into z2 came from a CSV file. Please consider this R session:  > length(x2) [1] 1632  > length(x) [1] 1632  > length(z2) [1] 1632  > head(z2) [1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0  > tail(z2) [1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15  > lm ( y ~ x2 + x, z2 ) Error in eval(predvars, data, env) :    numeric 'envir' arg not of length one  > lm ( y ~ x2 + x, as.data.frme(z2) ) Error in as.data.frme(z2) : could not find function "as.data.frme"  > lm ( y ~ x2 + x, as.data.frame(z2) ) Error in eval(predvars, data, env) :    numeric 'envir' arg not of length one lm(formula = y ~ x2 + x, data = as.data.frame(z2)) Coefficients: (Intercept)           x2            x   -1.475e-09    1.000e+00    6.044e-13  > min(z2) [1] 24420  > max(z2) [1] 35524.85  > class(z2) [1] "numeric"  > where x is set to x = seq(1:1632) and x2 is set to x^2 I am looking for an interpolating polynomial of the form:      Ax^2 + Bx + C I do not think the results I got make sense. I believe that I have a data type error.  I do not understand why I need to convert z2 to a data frame if it is already numeric. Thanks, Bob ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: Problem with LM

 ## This example, with your variable names, works correctly. z2 <- data.frame(y=1:5, x=c(1,5,2,3,5), x2=c(1,5,2,3,5)^2) z2 class(z2) length(z2) dim(z2) lm(y ~ x + x2, data=z2) ## note that that variable names y, x, x2 are column names of the ## data.frame z2 ## please review the definitions and examples of data.frame in ?data.frame ## also the argument requirements for lm in ?lm On Tue, Dec 18, 2018 at 6:32 PM rsherry8 <[hidden email]> wrote: > > The values read into z2 came from a CSV file. Please consider this R > session: > >  > length(x2) > [1] 1632 >  > length(x) > [1] 1632 >  > length(z2) > [1] 1632 >  > head(z2) > [1] 28914.0 28960.5 28994.5 29083.0 29083.0 29083.0 >  > tail(z2) > [1] 32729.65 32751.85 32386.05 32379.75 32379.15 31977.15 >  > lm ( y ~ x2 + x, z2 ) > Error in eval(predvars, data, env) : >    numeric 'envir' arg not of length one >  > lm ( y ~ x2 + x, as.data.frme(z2) ) > Error in as.data.frme(z2) : could not find function "as.data.frme" >  > lm ( y ~ x2 + x, as.data.frame(z2) ) > Error in eval(predvars, data, env) : >    numeric 'envir' arg not of length one > lm(formula = y ~ x2 + x, data = as.data.frame(z2)) > > Coefficients: > (Intercept)           x2            x >   -1.475e-09    1.000e+00    6.044e-13 > >  > min(z2) > [1] 24420 >  > max(z2) > [1] 35524.85 >  > class(z2) > [1] "numeric" >  > > > where x is set to x = seq(1:1632) > and x2 is set to x^2 > > I am looking for an interpolating polynomial of the form: >      Ax^2 + Bx + C > I do not think the results I got make sense. I believe that I have a > data type error.  I do not understand why > I need to convert z2 to a data frame if it is already numeric. > > Thanks, > Bob > > ______________________________________________ > [hidden email] mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.