# if statement and for loop question

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## if statement and for loop question

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## Re: if statement and for loop question

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## Re: if statement and for loop question

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## Re: if statement and for loop question

 In reply to this post by R help mailing list-2 Hello, You don't need a loop, the R way is a vectorized solution and it's also clearer. Create a logical index (note only one &) and assign b, c, d where it's TRUE. i <- try\$a != "Positive" & try\$a != "VUS" try <- within(try, {    b[i] <- ''    c[i] <- ''    d[i] <- '' }) Hope this helps, Rui Barradas Às 17:28 de 30/05/21, Kai Yang via R-help escreveu: > Hello List,I have a data frame which having the character columns: > > | a1 | b1 | c1 | d1 | > | a2 | b2 | c2 | d2 | > | a3 | b3 | c3 | d3 | > | a4 | b4 | c4 | d4 | > | a5 | b5 | c5 | d5 | > > > > I need to do: if a1 not = "Positive" and not = "VUS" then values of  b1, c1 and d1 will be zero out. And do the same thing for the a2 to a5 series. > I write the code below to do this. But it doesn't work. Would you please correct my code? > Thank you, > Kai > > > for (i in 1:5) > { >    if (isTRUE(try\$a[i] != "Positive" && try\$a[i] != "VUS")) >    { >      try\$b[i]== '' >      try\$c[i] == '' >      try\$d[i]== '' >    } > } > > > [[alternative HTML version deleted]] > > ______________________________________________ > [hidden email] mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ [hidden email] mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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## Re: if statement and for loop question

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