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This post was updated on .
thanks to your guys help I am closer to solving my problem but I have some small problem. So let's say I start with
>data
number day hour
1 17 10
2 17 11
3 17 6
4 18 4
5 18 10
6 19 8
7 19 8
I want to split to odd days, which I am able to do, I call this object frames, which looks like:
> frames
$`1`
c1 day1 hour1
1 1 17 10
2 2 17 11
3 3 17 6
$`2`
c1 day1 hour1
4 6 19 8
5 7 19 8
Now I want to make plots of the hours for all odd days next to each other, but not by hand. I need some sort of loop for this. How is this done?
So
par(mfrow=c(1,2))
for(…) plot(…hours…)
thanks for the help
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It's not really clear to me what you mean when you say that you want to
plot the hours, so it's hard to help. Regardless, take a look at looping
and plotting in any of the free documentation on CRAN.
http://cran.r-project.org/other-docs.htmlI hope that this helps,
Andrew
On Fri, Jan 18, 2013 at 2:21 AM, condor < [hidden email]> wrote:
> thanks to your guys help I am closer to solving my problem but I have some
> small problem. So let's say I start with
>
> >data
> number day hour
> 1 17 10
> 2 17 11
> 3 17 6
> 4 18 4
> 5 18 10
> 6 19 8
> 7 19 8
>
> I want to split to odd days, which I am able to do, I call this object
> frames, which looks like:
>
> > frames
> $`1`
> c1 day1 hour1
> 1 1 17 10
> 2 2 17 11
> 3 3 17 6
>
> $`2`
> c1 day1 hour1
> 4 6 19 8
> 5 7 19 8
>
> Now I want to make plot of the hours of both days, but not by hand. I need
> some sort of loop for this. How is this done?
>
> So
> par(mfrow=c(1,2))
> for(
) plot(
hours
)
>
> thanks for the help
>
>
>
> --
> View this message in context:
> http://r.789695.n4.nabble.com/plotting-from-dataframes-tp4655851.html> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> [hidden email] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code.
>
--
Andrew Robinson
Director (A/g), ACERA
Senior Lecturer in Applied Statistics Tel:
+61-3-8344-6410
Department of Mathematics and Statistics Fax: +61-3-8344 4599
University of Melbourne, VIC 3010 Australia
Email: [hidden email] Website: http://www.ms.unimelb.edu.auFAwR: http://www.ms.unimelb.edu.au/~andrewpr/FAwR/SPuR: http://www.ms.unimelb.edu.au/spuRs/ [[alternative HTML version deleted]]
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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This post was updated on .
So by hand the command would be
par(mfrow=c(1,2))
plot(frames$'1'$hour1)
plot(frames$'2'$hour1)
But in my case there are far more than 2 days, so I want to use a loop. Suppose I have 10 days I want to plot
par(mfrow=c(2,5))
for(i in 1:10){
plot( what should be put here??)
}
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Hi
> -----Original Message-----
> From: [hidden email] [mailto:r-help-bounces@r-
> project.org] On Behalf Of condor
> Sent: Friday, January 18, 2013 10:17 AM
> To: [hidden email]
> Subject: Re: [R] plotting from dataframes
>
> So by hand the command would be
>
> par(mfrow=c(1,2))
> plot(frames$'1'hour1)
> plot(frames$'2'hour1)
>
> But in my case there are far more than 2 days, so I want to use a loop.
> Suppose I have 10 plots
> par(mfrow=c(2,5))
> for(i in 1:10){
> plot( /what should be put here??/)
use
plot[,i]
if you want plot columns 1:10 or
put this
col.to.plot=c(5,7,9,12,15, 17, 21, 25, 26, 30)
in front of cycle and use
plot[,col.to.plot[i]]
if you want to plot preselected columns
Regards
Petr
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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You need to (re-) read the Introduction to R document that comes with R, particularly about indexing lists.
Briefly, there are three ways: integer, string, and approximate string indexing. You seem to be stuck now using approximate string indexing with the $ operator. Integer indexing is more appropriate for your loop.
for(i in 1:10){
plot( frames[[ i ]]$hour1 )
}
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condor < [hidden email]> wrote:
______________________________________________
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Hi,
May be this helps:
frames<-list(data.frame(c1=1:3,day1=17,hour1=c(10,11,6)),data.frame(c1=6:7,day1=19,hour1=8),data.frame(c1=8:10,day1=21,hour1=c(11,15,18)),data.frame(c1=12:13,day1=23,hour1=7))
par(mfrow=c(2,2))
lapply(seq_along(frames),function(i) plot(frames[[i]][,3]))
A.K.
----- Original Message -----
From: condor < [hidden email]>
To: [hidden email]
Cc:
Sent: Friday, January 18, 2013 4:16 AM
Subject: Re: [R] plotting from dataframes
So by hand the command would be
par(mfrow=c(1,2))
plot(frames$'1'hour1)
plot(frames$'2'hour1)
But in my case there are far more than 2 days, so I want to use a loop.
Suppose I have 10 plots
par(mfrow=c(2,5))
for(i in 1:10){
plot( /what should be put here??/)
}
--
View this message in context: http://r.789695.n4.nabble.com/plotting-from-dataframes-tp4655851p4655931.htmlSent from the R help mailing list archive at Nabble.com.
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
______________________________________________
[hidden email] mailing list
https://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting guide http://www.R-project.org/posting-guide.htmland provide commented, minimal, self-contained, reproducible code.
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